/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 69 In each of the geometric series ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In each of the geometric series in Exercises \(69-72,\) write out the first few terms of the series to find \(a\) and \(r,\) and find the sum of the series. Then express the inequality \(|r|<1\) in terms of \(x\) and find the values of \(x\) for which the inequality holds and the series converges. $$\sum_{n=0}^{\infty}(-1)^{n} x^{n}$$

Short Answer

Expert verified
The series converges for \(-1 < x < 1\), and the sum is \(\frac{1}{1+x}\) for \(|x|<1\).

Step by step solution

01

Identifying the Series Components

The series given is \( \sum_{n=0}^{\infty}(-1)^{n} x^{n} \). To find the first few terms, we start by substituting small values for \( n \). For \( n = 0 \), the term is \((-1)^0 x^0 = 1\). For \( n = 1 \), the term is \((-1)^1 x^1 = -x\). For \( n = 2 \), the term is \((-1)^2 x^2 = x^2\). Thus, the first few terms are \(1, -x, x^2, -x^3, \ldots\). This confirms that \( a = 1 \) (the first term) and \( r = -x \) (the common ratio).
02

Finding Sum of Infinite Series

The sum of an infinite geometric series is given by the formula \( S = \frac{a}{1-r} \), where \( |r| < 1 \). Given \( a = 1 \) and \( r = -x \), the sum is \( S = \frac{1}{1 - (-x)} = \frac{1}{1 + x} \). This formula applies as long as \(|r| = |-x| = |x| < 1\).
03

Expressing |r| < 1 in Terms of x

Given \( r = -x \), the condition \(|r| < 1\) is the same as \(|-x| < 1\). Simplifying gives \(|x| < 1\). This means \(-1 < x < 1\). These are the values of \( x \) for which the series converges.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Infinite Series
An infinite series is a sum of an infinite sequence of numbers. In simpler terms, instead of having a list of numbers that ends, you have one that goes on forever. Let's look at the given exercise, where we have the series:\[\sum_{n=0}^{\infty}(-1)^{n} x^{n}\]Each term of the series is of the form \((-1)^n x^n\), and these terms continue infinitely as \(n\) goes from 0 to infinity.
  • Infinite series are foundational in various fields of mathematics, especially calculus.
  • They can often represent functions in a simplified or more manageable form.
  • Not all infinite series sum up to a finite number; understanding their behavior is crucial.
In this exercise, we only consider the series when it converges to a finite value. Otherwise, the infinite sum does not have a meaningful result.
Convergence
Convergence in the context of series means that as you add more and more terms, the sum approaches a specific value. This is important because not all series converge.For a geometric series, a key factor for convergence is the common ratio, denoted by \(r\). The series converges if:\[|r| < 1\]This ensures that as more terms are added, their contribution becomes smaller, allowing the sum to stabilize to a finite number. Let's apply this to our series:\[r = -x\]The series will converge if:\[|-x| = |x| < 1\]Thus, the series converges when \(-1 < x < 1\). Convergence is crucial in finding meaningful sums in infinite series. Only when a series converges can we apply formulas like \(S = \frac{a}{1-r}\) to find its sum.
Common Ratio
In a geometric series, each term is a fixed multiple, called the 'common ratio', of the previous term. It's what defines the progression from one term to the next.For our series \[\sum_{n=0}^{\infty}(-1)^{n} x^{n}\]the common ratio \(r\) is identified as \(-x\).
  • The common ratio is essential in determining the behavior of a series.
  • It tells us how quickly terms grow, shrink, or oscillate.
  • A positive \(r\) leads to terms of the same sign, while a negative \(r\) causes terms to alternate signs, as seen here.
With \(r = -x\), the terms alternate in sign due to \((-1)^n\). Understanding the common ratio helps us check the convergence condition \(|x| < 1\), ensuring the series produces a finite sum.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For what values of \(r\) does the infinite series $$ 1+2 r+r^{2}+2 r^{3}+r^{4}+2 r^{5}+r^{6}+\cdots $$ converge? Find the sum of the series when it converges.

What happens if you add a finite number of terms to a divergent series or delete a finite number of terms from a divergent series? Give reasons for your answer.

Prove that \(\lim _{n \rightarrow \infty} x^{1 / n}=1,(x>0)\).

Using a CAS, perform the following steps to aid in answering questions (a) and (b) for the functions and intervals. Step 1: Plot the function over the specified interval. Step 2: Find the Taylor polynomials \(P_{1}(x), P_{2}(x),\) and \(P_{3}(x)\) at \(\bar{x}=0\) Step 3: Calculate the ( \(n+1\) )st derivative \(f^{(n+1)}(c)\) associated with the remainder term for each Taylor polynomial. Plot the derivative as a function of \(c\) over the specified interval and estimate its maximum absolute value, \(M\) Step 4: Calculate the remainder \(R_{n}(x)\) for each polynomial. Using the estimate \(M\) from Step 3 in place of \(f^{(n+1)}(c),\) plot \(R_{n}(x)\) over the specified interval. Then estimate the values of \(x\) that answer question (a). Step 5: Compare your estimated error with the actual error \(E_{n}(x)=\left|f(x)-P_{n}(x)\right|\) by plotting \(E_{n}(x)\) over the specified interval. This will help answer question (b). Step 6: Graph the function and its three Taylor approximations together. Discuss the graphs in relation to the information discovered in Steps 4 and 5. $$f(x)=\frac{1}{\sqrt{1+x}}, \quad|x| \leq \frac{3}{4}$$

Does the series $$ \sum_{n=1}^{\infty}\left(\frac{1}{n}-\frac{1}{n^{2}}\right) $$ converge or diverge? Justify your answer.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.