Chapter 10: Problem 57
Which of the sequences \(\left\\{a_{n}\right\\}\) converge, and which diverge? Find the limit of each convergent sequence. \(a_{n}=\left(\frac{3}{n}\right)^{1 / n}\)
Short Answer
Expert verified
The sequence converges to 1.
Step by step solution
01
Analyze the General Term
The sequence given is \(a_n = \left( \frac{3}{n} \right)^{1/n}\). To determine the behavior as \(n\to \infty\), analyze the general term by taking the \(n\)-th root of the fraction \(\frac{3}{n}\).
02
Consider the Limit as n Approaches Infinity
Consider the limit \(\lim_{n \to \infty} \left( \frac{3}{n} \right)^{1/n}\). Rewrite this in exponential form to simplify, using \(x^\frac{1}{n} = e^\frac{\ln(x)}{n}\).
03
Apply the Logarithm to Simplify
Take the logarithm of \(a_n\). This gives \(\ln(a_n) = \frac{1}{n} \ln\left( \frac{3}{n} \right) = \frac{1}{n} (\ln 3 - \ln n)\).
04
Evaluate the Limit of the Logarithm
Focus on the expression \(\frac{1}{n} (\ln 3 - \ln n)\). Split this into \(\frac{\ln 3}{n} - \frac{\ln n}{n}\) and evaluate limits separately. As \(n \to \infty\), \(\frac{\ln 3}{n} \to 0\) and \(\frac{\ln n}{n} \to 0\) since \(\ln n\) grows slower than \(n\).
05
Use Results from Limits
Since both components \(\frac{\ln 3}{n}\) and \(\frac{\ln n}{n}\) approach 0, it follows that \(\ln(a_n) \to 0\). Therefore, \(a_n \to e^0 = 1\).
06
Conclusion about Convergence
The sequence \(a_n\) converges to 1, as deduced from the analysis of the limits.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limits
Limits are a fundamental concept in calculus and mathematical analysis. They help us understand the behavior of sequences or functions as they approach a certain point or go to infinity. When we talk about the limit of a sequence, we're discussing what the terms of the sequence get closer to as the index becomes very large.For the sequence given in the exercise, we were asked to find if \( a_n = \left( \frac{3}{n} \right)^{1/n} \) converges as \( n \) approaches infinity. We begin this process by taking the limit of the sequence as \( n \to \infty \), focusing on how the terms behave when \( n \) gets larger and larger.In this case, transformations and simplifications with logarithms and exponential forms become useful. This combination allows us to establish whether the sequence will settle at a number, called the limit. After applying mathematical techniques, we deduce that this sequence converges to a limit of 1.
Logarithm
Logarithms are the inverse operations to exponentiation. Essentially, the logarithm tells us the power to which a number (the base) must be raised to get some other number. The formula for logarithms can be expressed as \( y = \log_b(x) \), which means \( b^y = x \).When solving problems involving sequence convergence, logarithms can simplify expressions, especially when dealing with powers and roots. In our original exercise, the expression \( a_n = \left(\frac{3}{n}\right)^{1/n} \) was simplified by taking the natural logarithm:
- The natural logarithm of \( a_n \) is \( \ln(a_n) = \frac{1}{n} (\ln 3 - \ln n) \).
- This step turns a complex power into a more manageable subtraction of two logarithmic terms.
Exponential Form
Exponential forms provide a powerful way of expressing numbers and algebraic expressions. The base of the exponential points to repeated multiplication, and this can be written as \( a^n \), where \( a \) is the base and \( n \) is the exponent.In the given solution, converting the sequence to an exponential form enabled further simplification. The expression \( x^{1/n} = e^{(\ln x)/n} \) was used to handle the \( n \)-th root of a term:
- This allows for rewriting the original sequence \( a_n = \left( \frac{3}{n} \right)^{1/n} \) into a power of \( e \), making the analysis of its limit more straightforward.
- By focusing on the exponential form, especially in the context of large values of \( n \), we align our understanding with principles of continuous growth and decay governed by \( e \).
Nth Root
The \( n \)-th root of a number is a concept in mathematics referring to a value that, when raised to the power of \( n \), gives the original number. For example, the \( n \)-th root of \( x \) is denoted as \( x^{1/n} \).In the sequence \( a_n = \left( \frac{3}{n} \right)^{1/n} \), the \( n \)-th root is applied to \( \frac{3}{n} \), transforming the sequence into a more approachable form for limit evaluation. The idea is to observe how the operation affects the sequence as \( n \) grows:
- Taking the \( n \)-th root generally makes values larger than 1 smaller and values less than 1 larger.
- For large \( n \), \( \left( \frac{3}{n} \right)^{1/n} \) reflects the tendencies of diminutive fractions raised to small powers, approaching a stable value.