Chapter 10: Problem 54
Which of the series, and which diverge? Use any method, and give reasons for your answers. $$\sum_{n=1}^{\infty} \frac{1}{1+2^{2}+3^{2}+\cdots+n^{2}}$$
Short Answer
Expert verified
The series converges by the Comparison Test.
Step by step solution
01
Understand the Series
The given series is \( \sum_{n=1}^{\infty} \frac{1}{1+2^{2}+3^{2}+\cdots+n^{2}} \). This is a series where the denominator is the sum of squares of the first \( n \) natural numbers. We need to determine whether this series converges or diverges.
02
Analyze the Denominator
The denominator of the terms can be represented as the expression \( \sum_{k=1}^{n} k^{2} \). The formula for this sum is \( \frac{n(n+1)(2n+1)}{6} \). Substituting this in gives the series: \[ \sum_{n=1}^{\infty} \frac{1}{\frac{n(n+1)(2n+1)}{6}} = \sum_{n=1}^{\infty} \frac{6}{n(n+1)(2n+1)}. \]
03
Check for Convergence Using Comparison Test
Observe that the denominator \( n(n+1)(2n+1) \) grows rapidly as \( n \to \infty \). We compare it with the series \( \sum_{n=1}^{\infty} \frac{1}{n^3} \), which is a p-series with \( p = 3 \), and we know it converges. Since \( \frac{6}{n(n+1)(2n+1)} \approx \frac{6}{2n^3} = \frac{3}{n^3} \) as \( n \to \infty \), and \( \sum_{n=1}^{\infty} \frac{3}{n^3} \) converges, our series \( \sum_{n=1}^{\infty} \frac{6}{n(n+1)(2n+1)} \) also converges.
04
Conclusion
By the Comparison Test, since the terms of our transformed series are less than the terms of a known convergent p-series with \( p > 1 \), the given series \( \sum_{n=1}^{\infty} \frac{1}{1+2^{2}+3^{2}+\cdots+n^{2}} \) converges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Comparison Test
The Comparison Test is a handy tool in mathematics to determine the convergence or divergence of an infinite series. It allows us to compare a series whose convergence we don't know with another series whose behavior is well established. Here's how it works:
- Take the series in question and compare its terms with those of a second series with known convergence properties.
- If the terms of your series are always smaller than the corresponding terms of a convergent series, then your series converges too.
- Similarly, if the terms of your series are larger than those of a divergent series, then your series also diverges.
P-series
A p-series is a specific type of series that takes the form \( \sum_{n=1}^{\infty} \frac{1}{n^p} \). The behavior of a p-series is determined by the value of \( p \):
- If \( p > 1 \), the series converges.
- If \( p \leq 1 \), the series diverges.
Sum of Squares
The sum of squares refers to the sum of the squares of sequential natural numbers, represented as \( 1^2 + 2^2 + 3^2 + \cdots + n^2 \). This is important to understand because it forms the denominator of the series in our problem.
To calculate this, we use the formula:
\[ \sum_{k=1}^{n} k^2 = \frac{n(n+1)(2n+1)}{6} \]
Substituting this into the series allows us to rewrite our original series in a more manageable form. Understanding how the denominator grows with increasing \( n \) is crucial for analyzing the behavior of the series as a whole. It shows us that as \( n \) becomes large, the denominator increases rapidly, which pushes the terms of the series towards zero, hinting towards convergence.
To calculate this, we use the formula:
\[ \sum_{k=1}^{n} k^2 = \frac{n(n+1)(2n+1)}{6} \]
Substituting this into the series allows us to rewrite our original series in a more manageable form. Understanding how the denominator grows with increasing \( n \) is crucial for analyzing the behavior of the series as a whole. It shows us that as \( n \) becomes large, the denominator increases rapidly, which pushes the terms of the series towards zero, hinting towards convergence.
Series Convergence Methods
Determining whether a series converges or diverges is a fundamental task in calculus and analysis. Various methods exist to test convergence, each suited to different kinds of series.
- Comparison Test: As shown above, compares the terms with those of a known series.
- Ratio and Root Tests: Often used for series with factorials or exponential terms, checking the limit of the ratio or root of the terms.
- Integral Test: Uses the associated function's integral to determine convergence.
- Limit Comparison Test: Similar but uses the limit of the ratio of the terms instead of direct comparison.