Chapter 10: Problem 43
The Taylor polynomial of order 2 generated by a twice-differentiable function \(f(x)\) at \(x=a\) is called the quadratic approximation of \(f\) at \(x=a .\) In Exercises \(41-46,\) find the (a) linearization (Taylor polynomial of order 1 ) and (b) quadratic approximation of \(f\) at \(x=0\) $$f(x)=1 / \sqrt{1-x^{2}}$$
Short Answer
Step by step solution
Identify the Function and its Derivatives
Find the First Derivative
Find the Second Derivative
Evaluate Derivatives at \(x = 0\)
Write the Linearization (First-order)
Write the Quadratic Approximation (Second-order)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Approximation
- \( f(a) \) is the value of the function at the point \( a \).
- \( f'(a) \) is the first derivative, representing the slope of the tangent at that point.
- \( f''(a) \) is the second derivative, indicating the curvature or concavity near the point \( a \).
Linearization
- \( f(a) \) is the value of the function at point \( a \).
- \( f'(a) \) is the slope of the function at \( a \).
Derivative Calculation
- The first derivative \( f'(x) \) was found using the chain rule to capture the rate of change or slope.\[ f'(x) = \frac{x}{(1-x^2)^{3/2}} \]
- The second derivative \( f''(x) \) involves further differentiation of \( f'(x) \), implementing the quotient rule along with the chain rule again.\[ f''(x) = \frac{2x^2 + 1}{(1-x^2)^{5/2}} \]
Chain Rule
- An outer function: \( g(u) = u^{-1/2} \)
- An inner function: \( u(x) = 1 - x^2 \)
- First, differentiate the outer function with respect to \( u \). This yields \( g'(u) = -\frac{1}{2}u^{-3/2} \).
- Then, differentiate the inner function with respect to \( x \), giving \( u'(x) = -2x \).
- Multiply the derivatives from the previous steps to get the overall derivative: \( f'(x) = g'(u) \cdot u'(x) = -\frac{1}{2}(1-x^2)^{-3/2} \cdot (-2x) \), simplifying to \( f'(x) = \frac{x}{(1-x^2)^{3/2}} \).
Twice-Differentiable Function
- The first derivative \( f'(x) \) tells us about its slope and the direction in which it is heading at any point \( x \).
- The second derivative \( f''(x) \) provides information about the function's curvature or concavity. A positive second derivative usually indicates the function is "concave up" (like a cup), while a negative one implies "concave down" (like a frown).