Chapter 10: Problem 33
Find the first four nonzero terms in the Maclaurin series for the functions. $$e^{\sin x}$$
Short Answer
Expert verified
The first four nonzero terms are \( 1 + x + \frac{x^2}{2} - \frac{x^3}{6} + \ldots \).
Step by step solution
01
Review the Maclaurin Series Concept
The Maclaurin series is a Taylor series expansion of a function about 0. For a function \( f(x) \), it is given by \( f(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + \ldots \). We will find the series for \( e^{\sin x} \) by using the expansion of \( e^x \) and \( \sin x \).
02
Write the Expansion for \( \sin x \)
The Maclaurin series for \( \sin x \) is \( x - \frac{x^3}{3!} + \frac{x^5}{5!} - \ldots \). We will use this series as part of our function \( e^{\sin x} \).
03
Write the Expansion for \( e^u \)
The Maclaurin series for \( e^u \) is \( 1 + u + \frac{u^2}{2!} + \frac{u^3}{3!} + \ldots \). Here, \( u = \sin x \). Substitute the expansion from Step 2 into this series for \( u \).
04
Substitute \( \sin x \) into the Series for \( e^u \)
Substitute \( \sin x = x - \frac{x^3}{6} \) into the series for \( e^u \). So, \( e^{\sin x} = 1 + (x - \frac{x^3}{6}) + \frac{(x - \frac{x^3}{6})^2}{2!} + \ldots \).
05
Simplify to Find Nonzero Terms
Calculate the first few terms: 1, the linear term \( x \), since \( x^3 \) is negligible for the early terms we focus on \( -\frac{x^3}{6}\), and then look at the square term \( \frac{(x - \frac{x^3}{6})^2}{2} \), which gives \( \frac{x^2}{2} \). Proceed to simplify terms for accuracy.
06
Determine the First Four Nonzero Terms
Combine the calculated terms: \( e^{\sin x} = 1 + x + \frac{x^2}{2} - \frac{x^3}{6} + \ldots \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor series
The Taylor series is a powerful mathematical tool used to approximate functions using an infinite sum of polynomial terms. This approximation is centered around a specific point, which we call "a". By setting "a" to zero, we get the Maclaurin series as a special case. The formula for the Taylor series of a function, \( f(x) \), is: \[ f(x) = f(a) + f'(a)(x - a) + \frac{f''(a)}{2!}(x - a)^2 + \frac{f'''(a)}{3!}(x - a)^3 + \, \cdots\] The Maclaurin series form simply sets \( a = 0 \). When using Taylor series, it is important to understand:
- "\( a \)" refers to the point around which the function is expanded. If \( a = 0 \), we get a Maclaurin series.
- Derivatives of \( f(x) \), calculated at "a", become coefficients in the polynomial expansion.
- The series approximation becomes more accurate with more terms.
- Taylor series apply well to a wide variety of functions, including exponential, logarithmic, and trigonometric functions.
exponential function
The exponential function, \( e^x \), is a fundamental mathematical function that grows rapidly and has the unique property that its derivative and integral are the same: \( e^x \). It can be expressed as a series expansion using its Taylor (or Maclaurin) series.For \( e^x \), the series expansion around zero is:\[e^x = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \frac{x^4}{4!} + \cdots\]This expansion helps us understand how the exponential function behaves around small values of \( x \).Why is \( e^x \) special?
- It's the base of natural logarithms, providing a natural growth pattern, relevant in many scientific fields.
- The function models continuous growth or decay processes, like population growth or radioactive decay.
- The constant \( e \) (approximately 2.718) arises in real-life processes and equations relating to calculus and differential equations.
sine function
The sine function, \( \sin x \), is a fundamental trigonometric function that varies periodically, representing oscillations or waveforms. It can also be described using a Maclaurin series, especially for approximations around zero.The series expansion for \( \sin x \) is:\[\sin x = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \cdots\]This pattern of alternating terms continues, with increasing powers and factorials in the denominator.Key features of \( \sin x \):
- The function oscillates between -1 and 1, with a period of \( 2\pi \).
- The Maclaurin series captures this oscillation, especially effective for small \( x \), where only a few terms are needed for a good approximation.
- Essential in modeling waves, signals, and various physical phenomena.
series expansion
Series expansion offers a robust way to represent functions as sums of simpler terms. This becomes increasingly valuable when dealing with complex functions like \( e^{\sin x} \), as in your exercise.The essence of series expansion is to express functions in an infinite sum form, often to simplify calculations or analyze behavior closely around a point:
- A series expansion can be a finite series (an approximation) or an infinite one, with its convergence requiring careful consideration.
- The most common series expansions in mathematics include polynomial series, like Taylor and Maclaurin series, especially useful for analytic functions.
- Each term in the series is constructed based on derivatives of the function, evaluated at a specific point (often zero for Maclaurin).
- The more terms you include, the more accurate your approximation becomes.