/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 Which of the series Converge abs... [FREE SOLUTION] | 91Ó°ÊÓ

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Which of the series Converge absolutely, which converge, and which diverge? Give reasons for your answers. $$\sum_{n=1}^{\infty}(-1)^{n+1}(\sqrt[n]{10})$$

Short Answer

Expert verified
The series diverges.

Step by step solution

01

Identify the Series Type

The given series is \(\sum_{n=1}^{\infty}(-1)^{n+1}(\sqrt[n]{10})\). This is an alternating series because it involves terms that alternate signs due to the factor \((-1)^{n+1}\).
02

Check for Absolute Convergence

To check for absolute convergence, consider the series \(\sum_{n=1}^{\infty}\left|(-1)^{n+1}(\sqrt[n]{10})\right| = \sum_{n=1}^{\infty}\sqrt[n]{10}\). We test the convergence of this series. The term \(\sqrt[n]{10}\) can be written as \(10^{1/n}\). As \(n\) approaches infinity, \(10^{1/n}\) approaches 1 because \(10^{1/n} = e^{\frac{\log(10)}{n}}\) and \(\frac{\log(10)}{n} \to 0\) as \(n \to \infty\).The nth-term test for divergence states that if the limit of \(a_n eq 0\) as \(n \to \infty\), the series \(\sum a_n\) diverges. Since \(10^{1/n} \to 1\), the absolute series diverges.
03

Apply Alternating Series Test

Now, apply the alternating series test to \(\sum_{n=1}^{\infty}(-1)^{n+1}(\sqrt[n]{10})\).The alternating series test requires that the absolute value \(b_n = \sqrt[n]{10}\) be decreasing (\(b_{n+1} \leq b_n\)) and that \(\lim_{n \to \infty} b_n = 0\). Since \(\sqrt[n]{10} \to 1\) as \(n \to \infty\) and not to 0, the alternating series test also fails.
04

Conclude Divergence

Since neither the absolute series converges nor does the original alternating series satisfy the conditions of the alternating series test, the given series \(\sum_{n=1}^{\infty}(-1)^{n+1}(\sqrt[n]{10})\) diverges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Alternating Series
Alternating series are special types of series where the signs of the terms alternate between positive and negative. This is mathematically expressed using a factor of \((-1)^{n+1}\) or \((-1)^{n}\), which causes this alternating behavior.

An example of an alternating series is \(\sum_{n=1}^{\infty} (-1)^{n+1} a_n\). The signs change because of the \((-1)^{n+1}\) component.
Some series can still converge even if their terms grow smaller slowly because the alternating sign causes a canceling out effect.
When analyzing alternating series, mathematicians often look at two main conditions:
  • The absolute value of the sequence of terms, \(b_n = |a_n|\), must be decreasing. This means that each term should be less than or equal to the term before it like \(b_{n+1} \leq b_n\).
  • The limit of the absolute sequence \(b_n\) as \(n\) approaches infinity must be zero, \(\lim_{n \to \infty} b_n = 0\).
When these conditions are met, the alternating series converges. If these conditions do not hold, the series may diverge.
Absolute Convergence
Absolute convergence is an important concept that helps us evaluate if a series is really converging by looking at the sum of the absolute values of its terms.

If a series \(\sum_{n=1}^{\infty} a_n\) converges absolutely, then the series \(\sum_{n=1}^{\infty} |a_n|\) formed by taking the absolute values of its terms, must also converge.
Absolute convergence is a stronger form of convergence:
  • If a series converges absolutely, it means the series will converge for sure.
  • If a series only converges, but not absolutely, it might still converge in a different way (conditionally).
To check for absolute convergence, we test if the series created by the absolute values of the terms converges.
In our exercise, taking the absolute terms \(\sqrt[n]{10}\), which can be written as \(10^{1/n}\), and checking their limit at infinity \((10^{1/n} \to 1)\) shows they do not approach zero, hence the series \(\sum_{n=1}^{\infty} |a_n|\) diverges. Hence, no absolute convergence is found here.
Nth-Term Test for Divergence
The nth-term test is the "go-to" test to determine if a series might diverge early in the analysis.

It's simple but very effective: if the terms of a series do not approach zero as \(n\) becomes very large, the series must diverge.
In mathematical terms, for a series \(\sum_{n=1}^{\infty} a_n\), if \(\lim_{n \to \infty} a_n eq 0\), then the series diverges.
This test is very useful because performing this limit test is often straightforward:
  • If the terms tend towards a non-zero number, the series diverges.
  • If the limit equals zero, the series may converge, but further testing is needed to confirm.
In our example, applying this test by looking at \(\sqrt[n]{10} = 10^{1/n}\) shows the terms converge to 1. Since \((10^{1/n} \to 1)\) is not zero, the series \(\sum_{n=1}^{\infty} a_n\) diverges.

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Most popular questions from this chapter

a. Show that the improper integral $$ \int_{2}^{\infty} \frac{d x}{x(\ln x)^{p}} \quad(p \text { a positive constant }) $$ converges if and only if \(p>1\) b. What implications does the fact in part (a) have for the convergence of the series $$ \sum_{n=2}^{\infty} \frac{1}{n(\ln n)^{p}} ? $$ Give reasons for your answer.

A sequence of rational numbers is described as follows: \(\frac{1}{1}, \frac{3}{2}, \frac{7}{5}, \frac{17}{12}, \ldots, \frac{a}{b}, \frac{a+2 b}{a+b}, \ldots\) Here the numerators form one sequence, the denominators form a second sequence, and their ratios form a third sequence. Let \(x_{n}\) and \(y_{n}\) be, respectively, the numerator and the denominator of the \(n\) th fraction \(r_{n}=x_{n} / y_{n}\) a. Verify that \(x_{1}^{2}-2 y_{1}^{2}=-1, x_{2}^{2}-2 y_{2}^{2}=+1\) and, more generally, that if \(a^{2}-2 b^{2}=-1\) or \(+1,\) then \((a+2 b)^{2}-2(a+b)^{2}=+1 \quad\) or \(\quad-1\) respectively. b. The fractions \(r_{n}=x_{n} / y_{n}\) approach a limit as \(n\) increases. What is that limit? (Hint: Use part (a) to show that \(\left.r_{n}^{2}-2=\pm\left(1 / y_{n}\right)^{2} \text { and that } y_{n} \text { is not less than } n .\right)\)

Estimate the error if \(P_{4}(x)=1+x+\left(x^{2} / 2\right)+\left(x^{3} / 6\right)+\left(x^{4} / 24\right)\) is used to estimate the value of \(e^{x}\) at \(x=1 / 2\).

a. Find the interval of convergence of the power series $$\sum_{n=0}^{\infty} \frac{8}{4^{n+2}} x^{n}$$ b. Represent the power series in part (a) as a power series about \(x=3\) and identify the interval of convergence of the new series. (Later in the chapter you will understand why the new interval of convergence does not necessarily include all of the numbers in the original interval of convergence.)

Use a CAS to perform the following steps for the sequences. a. Calculate and then plot the first 25 terms of the sequence. Does the sequence appear to be bounded from above or below? Does it appear to converge or diverge? If it does converge, what is the limit \(L\) ? b. If the sequence converges, find an integer \(N\) such that \(\left|a_{n}-L\right| \leq 0.01\) for \(n \geq N .\) How far in the sequence do you have to get for the terms to lie within 0.0001 of \(L ?\) \(a_{1}=1, \quad a_{n+1}=a_{n}+\frac{1}{5^{n}}\)

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