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Which of the series converge, and which diverge? Give reasons for your answers. (When you check an answer, remember that there may be more than one way to determine the series' convergence or divergence.) $$\sum_{n=1}^{\infty} \frac{1}{2 n-1}$$

Short Answer

Expert verified
The series \( \sum_{n=1}^{\infty} \frac{1}{2n-1} \) diverges.

Step by step solution

01

Identify the Series Type

The series given is \( \sum_{n=1}^{\infty} \frac{1}{2n-1} \). This is an example of a series with terms of the form \( \frac{1}{a_n} \) where each term is a positive decreasing function. The terms resemble the harmonic series.
02

Use the n-th Term Test

The n-th term of the series is \( a_n = \frac{1}{2n-1} \). According to the n-th term test for divergence, if \( \lim_{n \to \infty} a_n eq 0 \), then the series diverges. However, in this case, \( \lim_{n \to \infty} \frac{1}{2n-1} = 0 \). Therefore, the n-th term test is inconclusive.
03

Compare with the Harmonic Series

The series \( \sum_{n=1}^{\infty} \frac{1}{2n-1} \) closely resembles the harmonic series \( \sum_{n=1}^{\infty} \frac{1}{n} \), which is known to diverge. We can compare \( \sum_{n=1}^{\infty} \frac{1}{2n-1} \) with \( \sum_{n=1}^{\infty} \frac{1}{n} \) using the Limit Comparison Test.
04

Use the Limit Comparison Test

For two series \( \sum b_n \) and \( \sum a_n \), if \( \lim_{n \to \infty} \frac{a_n}{b_n} = c \) where \( 0 < c < \infty \), then both series either converge or diverge together. Comparing \( \sum_{n=1}^{\infty} \frac{1}{2n-1} \) with \( \sum_{n=1}^{\infty} \frac{1}{n} \):\[ \lim_{n \to \infty} \frac{\frac{1}{2n-1}}{\frac{1}{n}} = \lim_{n \to \infty} \frac{n}{2n-1} = \lim_{n \to \infty} \frac{1}{2 - \frac{1}{n}} = \frac{1}{2} \]Since \( \frac{1}{2} \) is a positive finite number, both series either converge or diverge.
05

Conclusion on Convergence

The harmonic series \( \sum_{n=1}^{\infty} \frac{1}{n} \) diverges. Since the limit comparison test shows this series \( \sum_{n=1}^{\infty} \frac{1}{2n-1} \) relates similarly to the harmonic series, it also diverges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Harmonic Series
The harmonic series is a type of infinite series that plays a key role in understanding series convergence. It takes the form
  • \( \sum_{n=1}^{\infty} \frac{1}{n} \)
Despite being made up of terms that approach zero, the harmonic series diverges. This means that the series grows without bound, and its sum never settles on a specific finite number.

The divergence of the harmonic series can be intuitively understood by considering that each subsequent term is just too large to allow the series to converge. Even as the terms get smaller, they remain large enough so that, collectively, they push the sum towards infinity. Recognizing the harmonic series and its divergence is important because many other series can be compared to it to determine their behavior.
n-th Term Test
The n-th term test, also known as the term test for divergence, is a simple yet powerful tool in the world of series convergence. It helps us determine whether a series might diverge. The test states:
  • If \( \lim_{n \to \infty} a_n eq 0 \), then the series \( \sum a_n \) diverges.
However, if the limit of \( a_n \) is zero, this does not provide information about convergence. Instead, the test is inconclusive in such cases.

In practice, the n-th term test is often the first step applied when analyzing a series. For example, if examining \( \sum_{n=1}^{\infty} \frac{1}{2n-1} \), applying the n-th term test shows \( \lim_{n \to \infty} \frac{1}{2n-1} = 0 \). This indicates we can't conclude anything about convergence or divergence directly from this test.
Limit Comparison Test
The limit comparison test is a more advanced method to determine the convergence or divergence of a series. It is particularly useful when dealing with series that are similar to a basic series, like the harmonic series.
  • Consider two series \( \sum a_n \) and \( \sum b_n \).
  • If \( \lim_{n \to \infty} \frac{a_n}{b_n} = c \), with \( 0 < c < \infty \), then both series converge or diverge together.
This test provides insight into the behavior of complex series by comparing them to series whose convergence properties are already known.

For instance, to determine the convergence of \( \sum_{n=1}^{\infty} \frac{1}{2n-1} \), one can compare it with the harmonic series \( \sum_{n=1}^{\infty} \frac{1}{n} \). Calculating \( \lim_{n \to \infty} \frac{\frac{1}{2n-1}}{\frac{1}{n}} \), which equals \( \frac{1}{2} \), shows that both series diverge because the harmonic series is known to diverge.

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Most popular questions from this chapter

According to the Alternating Series Estimation Theorem, how many terms of the Taylor series for \(\tan ^{-1} 1\) would you have to add to be sure of finding \(\pi / 4\) with an error of magnitude less than \(10^{-3} ?\) Give reasons for your answer.

When \(a\) and \(b\) are real, we define \(e^{(a+i b) x}\) with the equation $$ e^{(a+i b) x}=e^{a x} \cdot e^{i b x}=e^{a x}(\cos b x+i \sin b x) $$ Differentiate the right-hand side of this equation to show that $$ \frac{d}{d x} e^{(a+i b) x}=(a+i b) e^{(a+i b) x} $$ Thus the familiar rule \((d / d x) e^{k x}=k e^{k x}\) holds for \(k\) complex as well as real.

Use the identity \(\sin ^{2} x=(1-\cos 2 x) / 2\) to obtain the Maclaurin series for \(\sin ^{2} x\). Then differentiate this series to obtain the Maclaurin series for \(2 \sin x \cos x .\) Check that this is the series for \(\sin 2 x\).

Show that if \(M_{1}\) and \(M_{2}\) are least upper bounds for the sequence \(\left\\{a_{n}\right\\},\) then \(M_{1}=M_{2}\) That is, a sequence cannot have two different least upper bounds.

Using a CAS, perform the following steps to aid in answering questions (a) and (b) for the functions and intervals. Step 1: Plot the function over the specified interval. Step 2: Find the Taylor polynomials \(P_{1}(x), P_{2}(x),\) and \(P_{3}(x)\) at \(\bar{x}=0\) Step 3: Calculate the ( \(n+1\) )st derivative \(f^{(n+1)}(c)\) associated with the remainder term for each Taylor polynomial. Plot the derivative as a function of \(c\) over the specified interval and estimate its maximum absolute value, \(M\) Step 4: Calculate the remainder \(R_{n}(x)\) for each polynomial. Using the estimate \(M\) from Step 3 in place of \(f^{(n+1)}(c),\) plot \(R_{n}(x)\) over the specified interval. Then estimate the values of \(x\) that answer question (a). Step 5: Compare your estimated error with the actual error \(E_{n}(x)=\left|f(x)-P_{n}(x)\right|\) by plotting \(E_{n}(x)\) over the specified interval. This will help answer question (b). Step 6: Graph the function and its three Taylor approximations together. Discuss the graphs in relation to the information discovered in Steps 4 and 5. $$f(x)=\frac{1}{\sqrt{1+x}}, \quad|x| \leq \frac{3}{4}$$

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