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Use any method to determine if the series converges or diverges. Give reasons for your answer. $$\sum_{n=1}^{\infty} \frac{n^{10}}{10^{n}}$$

Short Answer

Expert verified
The series converges by the Ratio Test.

Step by step solution

01

Identify the Series

The series given is \( \sum_{n=1}^{\infty} \frac{n^{10}}{10^n} \). We need to determine if it converges or diverges.
02

Consider Applying the Ratio Test

The ratio test is helpful for series where the general term involves factorials or powers. For the series \( \sum_{n=1}^{\infty} a_n \), if \( a_n = \frac{n^{10}}{10^n} \), we compute the limit \( L = \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \). If \( L < 1 \), the series converges; if \( L > 1 \) or \( L = \infty \), the series diverges.
03

Apply the Ratio Test

Calculate \( \frac{a_{n+1}}{a_n} \): \( a_{n+1} = \frac{(n+1)^{10}}{10^{n+1}} \) and \( a_n = \frac{n^{10}}{10^n} \). Thus, \( \frac{a_{n+1}}{a_n} = \frac{(n+1)^{10}}{10^{n+1}} \times \frac{10^n}{n^{10}} = \frac{(n+1)^{10}}{10 imes n^{10}} \).
04

Simplify the Ratio

Simplify the expression \( \frac{(n+1)^{10}}{10 imes n^{10}} \). You can factor it as \( \frac{1}{10} \left( \frac{n+1}{n} \right)^{10} \). Simplify further: \( \frac{n+1}{n} = 1 + \frac{1}{n} \), so \( \left( 1 + \frac{1}{n} \right)^{10} \).
05

Evaluate the Limit

Take the limit as \( n \to \infty \): \( L = \lim_{n \to \infty} \frac{1}{10} \left( 1 + \frac{1}{n} \right)^{10} = \frac{1}{10} \times 1^{10} = \frac{1}{10} \).
06

Conclusion from Ratio Test

Since \( L = \frac{1}{10} < 1 \), the Ratio Test tells us that the series \( \sum_{n=1}^{\infty} \frac{n^{10}}{10^n} \) converges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ratio Test
The Ratio Test is a powerful tool when dealing with series, especially those involving factorials or large powers. Here's how it works. Given a series \( \sum_{n=1}^{\infty} a_n \), the Ratio Test considers the ratio \( \left| \frac{a_{n+1}}{a_n} \right| \). By taking the limit as \( n \to \infty \), we find the value \( L \).
  • If \( L < 1 \), the series converges absolutely.
  • If \( L > 1 \) or \( L = \infty \), the series diverges.
  • If \( L = 1 \), the test is inconclusive, and other methods need to be used.

For our example series \( \sum_{n=1}^{\infty} \frac{n^{10}}{10^n} \), applying the Ratio Test and simplifying gives \( L = \frac{1}{10} \), indicating convergence since \( L < 1 \). This suggests not only convergence but absolute convergence as well, meaning it remains convergent regardless of the sign of the terms.
Infinite Series
An infinite series is a sum of infinitely many terms, written as \( \sum_{n=1}^{\infty} a_n \). Each term in the series is denoted by \( a_n \). The concept hinges on the idea that even though there are infinitely many terms, the sum can approach a finite limit.
Understanding infinite series is fundamental in advanced mathematics. It connects to calculus, where limits are a core concept. When we talk about series, the terms can shrink and seemingly become negligible, yet their cumulative addition might not.
It's crucial to determine whether an infinite series converges or diverges. If the series converges, then it sums to a finite number. If it diverges, the sum isn't finite, possibly stretching to infinity or lacking a clear limit.
Power Series
A power series is a type of infinite series where each term involves a power of the variable. It looks like something:\( \sum_{n=0}^{\infty} a_n (x - c)^n \), where \( c \) is the center of the series and \( a_n \) are the coefficients.
Power series are at the heart of techniques such as Taylor and Maclaurin series. They allow complex functions to be represented as an infinite sum of terms. With them, we can approximate functions and perform calculations that would otherwise be difficult.
  • Radius of convergence: Determines the interval within which the series converges.
  • Convergence: At points within the radius, the series behaves nicely, while outside it, convergence isn't guaranteed.

Our given series isn't a power series in the variable sense but understanding power series introduces important convergence concepts that apply broadly.
Series Convergence Tests
Series convergence tests are methods used to determine whether an infinite series converges. They form the basis for understanding series in depth.
  • Ratio Test: Uses the limit of the ratio of successive terms.
  • Root Test: Analyzes the limit of the \( n \)-th root of the absolute value of terms.
  • Integral Test: Connects series to improper integrals.
  • Comparison Test: Compares a series with another one whose convergence behavior is known.

Different series require different tests based on their structure and terms. For a series like \( \sum_{n=1}^{\infty} \frac{n^{10}}{10^n} \), the Ratio Test is particularly effective due to its form involving powers.
Sometimes more than one test might apply, and using multiple checks can confirm a result or suggest different approaches when tests yield inconclusive results.

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Most popular questions from this chapter

Using a CAS, perform the following steps to aid in answering questions (a) and (b) for the functions and intervals. Step 1: Plot the function over the specified interval. Step 2: Find the Taylor polynomials \(P_{1}(x), P_{2}(x),\) and \(P_{3}(x)\) at \(\bar{x}=0\) Step 3: Calculate the ( \(n+1\) )st derivative \(f^{(n+1)}(c)\) associated with the remainder term for each Taylor polynomial. Plot the derivative as a function of \(c\) over the specified interval and estimate its maximum absolute value, \(M\) Step 4: Calculate the remainder \(R_{n}(x)\) for each polynomial. Using the estimate \(M\) from Step 3 in place of \(f^{(n+1)}(c),\) plot \(R_{n}(x)\) over the specified interval. Then estimate the values of \(x\) that answer question (a). Step 5: Compare your estimated error with the actual error \(E_{n}(x)=\left|f(x)-P_{n}(x)\right|\) by plotting \(E_{n}(x)\) over the specified interval. This will help answer question (b). Step 6: Graph the function and its three Taylor approximations together. Discuss the graphs in relation to the information discovered in Steps 4 and 5. $$f(x)=\frac{1}{\sqrt{1+x}}, \quad|x| \leq \frac{3}{4}$$

Use a CAS to perform the following steps for the sequences. a. Calculate and then plot the first 25 terms of the sequence. Does the sequence appear to be bounded from above or below? Does it appear to converge or diverge? If it does converge, what is the limit \(L\) ? b. If the sequence converges, find an integer \(N\) such that \(\left|a_{n}-L\right| \leq 0.01\) for \(n \geq N .\) How far in the sequence do you have to get for the terms to lie within 0.0001 of \(L ?\) \(a_{n}=(123456)^{1 / n}\)

Prove that if \(\left\\{a_{n}\right\\}\) is a convergent sequence, then to every positive number \(\epsilon\) there corresponds an integer \(N\) such that for all \(m\) and \(n\), $$m>N \text { and } n>N \Rightarrow\left|a_{m}-a_{n}\right|<\epsilon$$.

Determine if the sequence is monotonic and if it is bounded. \(a_{n}=\frac{3 n+1}{n+1}\)

Use a CAS to perform the following steps for the sequences. a. Calculate and then plot the first 25 terms of the sequence. Does the sequence appear to be bounded from above or below? Does it appear to converge or diverge? If it does converge, what is the limit \(L\) ? b. If the sequence converges, find an integer \(N\) such that \(\left|a_{n}-L\right| \leq 0.01\) for \(n \geq N .\) How far in the sequence do you have to get for the terms to lie within 0.0001 of \(L ?\) \(a_{n}=\frac{n^{41}}{19^{n}}\)

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