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Find the Taylor polynomials of orders \(0,1,2,\) and 3 generated by \(f\) at \(a\). $$f(x)=\sin x, \quad a=0$$

Short Answer

Expert verified
0th: 0, 1st: x, 2nd: x, 3rd: x - (1/6)x^3.

Step by step solution

01

Review Function and Point of Expansion

The function given is \( f(x) = \sin x \) and we need to find its Taylor polynomials at \( a = 0 \). This is a Maclaurin series since the expansion is at zero.
02

Calculate Function and Derivatives at a

Compute the derivatives of \( f(x) = \sin x \) at \( x = 0 \).1. \( f(x) = \sin x \), thus \( f(0) = \sin(0) = 0 \).2. \( f'(x) = \cos x \), hence \( f'(0) = \cos(0) = 1 \).3. \( f''(x) = -\sin x \), implying \( f''(0) = -\sin(0) = 0 \).4. \( f'''(x) = -\cos x \), so \( f'''(0) = -\cos(0) = -1 \).
03

Construct the 0th Order Taylor Polynomial

The 0th order Taylor polynomial is simply the value of \( f(x) \) at \( a \):\[ T_0(x) = f(0) = 0. \]
04

Construct the 1st Order Taylor Polynomial

Use the formula for the 1st order Taylor polynomial:\[ T_1(x) = f(0) + f'(0)x = 0 + 1 \cdot x = x. \]
05

Construct the 2nd Order Taylor Polynomial

Use the formula for the second order polynomial:\[ T_2(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 = 0 + x + \frac{0}{2}x^2 = x. \]
06

Construct the 3rd Order Taylor Polynomial

Use the formula for the third order polynomial:\[ T_3(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 \]\[ = 0 + x + 0 + \frac{-1}{6}x^3 = x - \frac{1}{6}x^3. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Maclaurin series
The Taylor series is a powerful mathematical tool used to approximate functions using polynomials. When this approximation is centered around zero, it is specifically referred to as the Maclaurin series. This type of series is particularly useful because many functions can be expressed as an infinite sum of terms calculated from the values of their derivatives at zero. In the Maclaurin series, each term represents an improvement upon the previous one, adding more accuracy to the function representation as more terms are included.
Although the Maclaurin series can go on indefinitely, for practical purposes, it is often truncated to provide a polynomial of a certain order that approximates the function within a required degree of accuracy.
Derivatives
Derivatives lie at the heart of calculus and play a fundamental role in creating Maclaurin series. They measure how a function changes as its input changes, essentially capturing the function's rate of change or slope. Calculating the derivatives of a function is a preliminary step in finding its Maclaurin series.
In the exercise, for the function \( f(x) = \sin x \), we find the following derivatives:
  • The first derivative, \( f'(x) = \cos x \), gives the slope of \( f(x) \) at any point.
  • The second derivative, \( f''(x) = -\sin x \), indicates how the slope itself is changing.
  • Further derivatives provide even deeper insight into the function's behavior.
These values at \( x = 0 \) are crucial for constructing the Maclaurin polynomial as they inform how each term should be weighted.
Polynomials
Polynomials are expressions made up of variables and coefficients combined using addition, multiplication, and exponentiation. In the context of Taylor and Maclaurin series, polynomials serve as approximating functions that can mimic the behavior of more complex functions over a specific interval.
For example, consider the series expansion of \( \sin x \) up to the third order:
  • The 0th order polynomial, \( T_0(x) = 0 \), represents the simplest form, merely a constant.
  • The third order polynomial, \( T_3(x) = x - \frac{1}{6}x^3 \), introduces cubic terms, making it a remarkable approximation of \( \sin x \) near zero.
Through these polynomial models, we break down and simplify the study and use of functions, particularly those that are otherwise challenging to handle.
Order of approximation
When working with the Maclaurin series, the 'order of approximation' refers to the degree of the polynomial being used to approximate a function. The order tells us how many terms from the series we are using and therefore impacts how closely the polynomial resembles the original function.
In mathematical terms, the order is linked to the highest derivative included in the polynomial. For instance:
  • A 0th order approximation is a constant term, capturing the function's value at the center point.
  • A 1st order approximation includes the first derivative, introducing a linear component that lightly contours the function's immediate trend.
  • Higher-order approximations, like the third order, consider additional derivatives, thereby following the function's more nuanced variations.
Selecting the appropriate order is a balance between computational simplicity and the need for precision.

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