/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 134 Prove that a sequence \(\left\\{... [FREE SOLUTION] | 91Ó°ÊÓ

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Prove that a sequence \(\left\\{a_{n}\right\\}\) converges to 0 if and only if the sequence of absolute values \(\left\\{\left|a_{n}\right|\right\\}\) converges to 0 .

Short Answer

Expert verified
A sequence \(\{a_n\}\) converges to 0 if and only if \(\{|a_n|\}\) converges to 0.

Step by step solution

01

Understand the Definitions

A sequence \(\{a_n\}\) converges to 0 if for every \(\varepsilon > 0\), there exists a natural number \(N\) such that for all \(n \geq N\), \(|a_n| < \varepsilon\). A sequence \(\{|a_n|\}\) converges to 0 if for every \(\varepsilon > 0\), there exists a natural number \(M\) such that for all \(n \geq M\), \(|a_n| < \varepsilon\).
02

Prove the Forward Implication

Assume \(\{a_n\}\) converges to 0. We want to show \(\{|a_n|\}\) also converges to 0. For any \(\varepsilon > 0\), since \(a_n\) converges to 0, there exists \(N\) such that for all \(n \geq N\), \(|a_n| < \varepsilon\). Thus, \(|a_n|\) is less than \(\varepsilon\) for all \(n \geq N\), proving \(\{|a_n|\}\) converges to 0.
03

Prove the Backward Implication

Assume \(|a_n|\) converges to 0. We need to show \(a_n\) converges to 0. For any \(\varepsilon > 0\), there exists \(M\) such that for all \(n \geq M\), \(|a_n| < \varepsilon\). This directly implies that \(a_n\) is also less than \(\varepsilon\) in magnitude for all \(n \geq M\), hence \(a_n\) converges to 0.
04

Conclusion

Since both conditions (forward and backward implications) have been proven, we conclude that \(\{a_n\}\) converges to 0 if and only if \(\{|a_n|\}\) converges to 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Epsilon-Delta Definition
The epsilon-delta definition is a formal approach used in mathematics to determine the convergence of sequences and functions. This definition meticulously describes what it means for a sequence to converge to a specific limit, such as 0 in our current scenario. Specifically, for a sequence \( \{a_n\} \) to converge to 0, it must satisfy the condition: for every \( \varepsilon > 0 \), however small, there exists a natural number \( N \) such that for all \( n \geq N \), we have \( |a_n| < \varepsilon \).- **Purpose**: This definition helps in quantifying how close the terms of the sequence need to be to the limit from a given point onward. - **Universal Applicability**: By demonstrating this condition, not only does it confirm convergence for any sequence, but it also highlights a rigorous standard applicable to all convergent sequences. - **Intuition**: Think of \( \varepsilon \) as a tolerance level of closeness and \( N \) as a milestone beyond which every sequence term stays within this tolerance. It verifies that eventually the sequence "behaves" consistently close to the limit by a predetermined measurement.
Absolute Value Sequence
An absolute value sequence \( \{|a_n|\} \) is derived by taking the absolute values of the terms of another sequence \( \{a_n\} \). The significance of using absolute values lies in simplifying the consideration of distance from zero, without regard to whether a sequence value is positive or negative. Here's how it connects to the idea of convergence:- **Simplicity**: The absolute value removes any concern of positive or negative fluctuation by aligning all values positively. This uniform treatment is beneficial while checking convergence towards a non-negative limit like 0.- **Impact on Convergence**: The convergence of the absolute value sequence \( \{|a_n|\} \) to 0 implies that each term's magnitude is shrinking towards zero. When \( |a_n| < \varepsilon \) is achieved for every \( n \geq M \), it ensures no terms go beyond this "smallness threshold" whether originating from positive or negative values.- **Relation to Original Sequence**: When \( \{|a_n|\} \) converges to 0, \( \{a_n\} \) must also converge to 0, as the distance from zero is the same regardless of the sign. Hence, convergence of the absolute values directly confirms the convergence of the original sequence.
Convergence Proof
Proofs of sequence convergence, especially using the epsilon-delta approach, solidify the understanding of how sequences behave in mathematical analysis. Let's walk through the convergence proof related to our specific case:- **Forward Implication**: Assume \( \{a_n\} \) converges to 0. By the definition of convergence, \( |a_n| < \varepsilon \) for all \( n \geq N \). This automatically implies \( \{|a_n|\} \) converges to 0 since confirming the same bounds for absolute values is easier.- **Backward Implication**: Conversely, assume \( \{|a_n|\} \) converges to 0. Then for every \( \varepsilon > 0 \), there exists some \( M \) such that \( |a_n| < \varepsilon \), hence \( a_n \) itself is within this bound, confirming \( \{a_n\} \) converges to 0.This bidirectional logic ensures that the presence of convergence in the absolute value sequence dictates the same outcome in the original sequence. Such proofs underscore the consistency and reliability of convergence criteria under the epsilon-delta framework.

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