Chapter 10: Problem 126
Use the definition of convergence to prove the given limit. \(\lim _{n \rightarrow \infty}\left(1-\frac{1}{n^{2}}\right)=1\)
Short Answer
Expert verified
The limit as \(n\) approaches infinity of \(1-\frac{1}{n^2}\) is 1.
Step by step solution
01
Understanding the Definition of Convergence
According to the definition of convergence, a sequence \(a_n\) converges to a limit \(L\) as \(n\) approaches infinity if for every \(\epsilon > 0\), there exists a positive integer \(N\) such that for all \(n > N\), \(|a_n - L| < \epsilon\). In this exercise, \(a_n = 1-\frac{1}{n^2}\) and \(L=1\).
02
Express the Absolute Value Inequality
We need to prove that for any \(\epsilon > 0\), there exists an \(N\) such that if \(n > N\), then \(|1-\frac{1}{n^2} - 1| < \epsilon\). Simplify the left side to obtain: \(|1 - \frac{1}{n^2} - 1| = | -\frac{1}{n^2} | = \frac{1}{n^2}\).
03
Solve the Inequality for n
Now, we need \(\frac{1}{n^2} < \epsilon\). This translates to finding \(n\) such that \(n^2 > \frac{1}{\epsilon}\).
04
Determine N
Since \(n^2 > \frac{1}{\epsilon}\), we take the square root on both sides to get \(n > \sqrt{\frac{1}{\epsilon}}\). Thus, we can choose \(N = \lceil \sqrt{\frac{1}{\epsilon}} \rceil\) to ensure that for all \(n > N\), the inequality holds. The ceiling function \(\lceil \cdot \rceil\) ensures \(N\) is an integer.
05
Conclude the Proof
By setting \(N = \lceil \sqrt{\frac{1}{\epsilon}} \rceil\), we have shown that for every \(\epsilon > 0\), there exists a corresponding \(N\) such that for all \(n > N\), \(|1-\frac{1}{n^2} - 1| < \epsilon\). Therefore, by the definition of convergence, \(\lim_{n \rightarrow \infty} (1 - \frac{1}{n^2}) = 1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limit of a Sequence
When we talk about the limit of a sequence, we refer to the value that a sequence approaches as the term number goes to infinity. In mathematics, the limit is not just an estimated value but a definitive point that the terms of the sequence get arbitrarily close to. For instance, if you have a sequence \( a_n \) such that \( a_n = 1 - \frac{1}{n^2} \), as \( n \) grows larger and larger, the values of this sequence get closer and closer to 1.
Think of it like someone getting closer to touching a target; every step they take gets them closer, even though they might not ever reach the target perfectly. The sequence gets infinitely close to the target value. This proximity to a target value, as \( n \) approaches infinity, is what we mean when we say \( \lim_{n \to \infty} a_n = L \), where \( L \) is the limit.
Think of it like someone getting closer to touching a target; every step they take gets them closer, even though they might not ever reach the target perfectly. The sequence gets infinitely close to the target value. This proximity to a target value, as \( n \) approaches infinity, is what we mean when we say \( \lim_{n \to \infty} a_n = L \), where \( L \) is the limit.
- The sequence gets closer to 1 as \( n \) increases.
- The limit indicates stability, meaning the sequence behaves in a predictable pattern as it goes on indefinitely.
- In mathematical terms, the sequence \( 1 - \frac{1}{n^2} \) converges to the limit 1 as \( n \to \infty \).
Epsilon-Delta Definition
The epsilon-delta definition is a formal way to define the concept of limit for sequences. It utilizes two parameters: \( \epsilon \) ("epsilon") and \( \delta \). However, when dealing with sequences, we usually use \( N \) instead of \( \delta \). The approach describes how close a sequence gets to the limit \( L \) when \( n \) is sufficiently large.
If we have a sequence \( a_n \) and want to say it converges to \( L \), we must show that for any small positive number \( \epsilon \), there exists an integer \( N \) such that for every term of the sequence beyond the \( N^{th} \) term, the distance between \( a_n \) and \( L \) is less than \( \epsilon \). This distance we express as \(|a_n - L| < \epsilon\).
If we have a sequence \( a_n \) and want to say it converges to \( L \), we must show that for any small positive number \( \epsilon \), there exists an integer \( N \) such that for every term of the sequence beyond the \( N^{th} \) term, the distance between \( a_n \) and \( L \) is less than \( \epsilon \). This distance we express as \(|a_n - L| < \epsilon\).
- \( \epsilon \) represents how close we want the sequence terms to get to the limit \( L \).
- \( N \) is the point beyond which all terms of the sequence are closer than \( \epsilon \) to the limit.
- This definition provides a rigorous method to validate that a sequence truly converges to its limit.
Infinite Sequences
Infinite sequences are a fundamental concept in mathematics, representing sequences that continue indefinitely without terminating. While finite sequences have a limited number of terms, infinite sequences keep going, offering a profound way to explore limits and convergence.
Think of infinite sequences like never-ending lists or patterns. An example is \( 1, \frac{3}{4}, \frac{7}{8}, \frac{15}{16}, \ldots \), which keeps getting closer to 1 but never actually stops.
Think of infinite sequences like never-ending lists or patterns. An example is \( 1, \frac{3}{4}, \frac{7}{8}, \frac{15}{16}, \ldots \), which keeps getting closer to 1 but never actually stops.
- Infinite sequences allow us to explore deep mathematical ideas, such as calculus concepts.
- They enable us to discuss behaviors at the limit, like how sequences tend to settle near values as terms grow.
- Understanding infinite sequences is critical for advanced studies, especially in understanding series, integration, and other higher-level math topics.