Chapter 10: Problem 12
Find the binomial series for the functions. $$\left(1+x^{2}\right)^{3}$$
Short Answer
Expert verified
The binomial series is \(1 + 3x^2 + 3x^4 + x^6\).
Step by step solution
01
Identify the Binomial Expression
The expression we need to expand is \((1 + x^2)^3\). This is a binomial expression where \(a = 1\), \(b = x^2\), and \(n = 3\).
02
Apply Binomial Theorem
The Binomial Theorem states that \((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\). For our expression \((1 + x^2)^3\), this becomes \(\sum_{k=0}^{3} \binom{3}{k} (1)^{3-k} (x^2)^k\).
03
Calculate Binomial Coefficients
Calculate the binomial coefficients \(\binom{3}{k}\) for \(k = 0\) to \(3\). The coefficients are: \(\binom{3}{0} = 1\), \(\binom{3}{1} = 3\), \(\binom{3}{2} = 3\), \(\binom{3}{3} = 1\).
04
Substitute and Simplify Each Term
Substitute \(k = 0, 1, 2, 3\) into the expression:- For \(k = 0\): \(1 \cdot (1)^3 \cdot (x^2)^0 = 1\)- For \(k = 1\): \(3 \cdot (1)^2 \cdot (x^2)^1 = 3x^2\)- For \(k = 2\): \(3 \cdot (1)^1 \cdot (x^2)^2 = 3x^4\)- For \(k = 3\): \(1 \cdot (1)^0 \cdot (x^2)^3 = x^6\)
05
Write the Binomial Series
Combine all the terms from Step 4 to form the series: \(1 + 3x^2 + 3x^4 + x^6\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Theorem
The Binomial Theorem is a powerful algebraic tool that allows for the expansion of expressions raised to a power. It provides a formulaic approach to expand any binomial expression
By applying this theorem, we can easily expand expressions like \((1 + x^2)^3\) by computing each term separately. This makes complex polynomial manipulations manageable and helps to solve problems efficiently.
- An expression of the form \((a + b)^n\) contains two terms, 'a' and 'b', raised to any power 'n'.
- The theorem states that \[(a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\].
By applying this theorem, we can easily expand expressions like \((1 + x^2)^3\) by computing each term separately. This makes complex polynomial manipulations manageable and helps to solve problems efficiently.
Polynomial Expansion
Polynomial expansion is the process of turning a compact expression into a larger one by applying algebraic rules. This process often uses the Binomial Theorem to systematically expand expressions like \((1 + x^2)^3\).When expanding such a polynomial, each term's power sum corresponds to the total power the polynomial is raised to. For example:
- The first term is derived from \(k = 0\) and contributes only the leading coefficient since \((x^2)^0 = 1\).
- Subsequent terms involve sequential incrementation of the power of \(b\), which in this case is \(x^2\).
Binomial Coefficients
Binomial coefficients are the numerical factors that appear in the expansion of binomial expressions raised to a power. They are crucial in determining the weight or significance of each term within the expanded polynomial.
These coefficients are represented as \(\binom{n}{k}\), where 'n' denotes the power of the binomial and 'k' indicates the specific term's position. They can be calculated using the formula: \[\binom{n}{k} = \frac{n!}{k!(n-k)!}\]Where 'n!' (n factorial) is the product of all integers from 1 to n. For example, when expanding \((1 + x^2)^3,\) the coefficients \(\binom{3}{0} = 1, \binom{3}{1} = 3, \binom{3}{2} = 3,\) and \(\binom{3}{3} = 1\) dictate the size of each term in the expansion.
These coefficients are represented as \(\binom{n}{k}\), where 'n' denotes the power of the binomial and 'k' indicates the specific term's position. They can be calculated using the formula: \[\binom{n}{k} = \frac{n!}{k!(n-k)!}\]Where 'n!' (n factorial) is the product of all integers from 1 to n. For example, when expanding \((1 + x^2)^3,\) the coefficients \(\binom{3}{0} = 1, \binom{3}{1} = 3, \binom{3}{2} = 3,\) and \(\binom{3}{3} = 1\) dictate the size of each term in the expansion.
- These coefficients ensure that the expansion is precisely balanced, contributing to the symmetry and elegance of polynomial expressions.