/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 117 Which of the sequences converge,... [FREE SOLUTION] | 91Ó°ÊÓ

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Which of the sequences converge, and which diverge? Give reasons for your answers. \(a_{n}=\frac{2^{n}-1}{2^{n}}\)

Short Answer

Expert verified
The sequence converges to 1.

Step by step solution

01

Understand the Sequence

The given sequence is \( a_n = \frac{2^n - 1}{2^n} \). We need to determine if this sequence converges or diverges as \( n \) approaches infinity.
02

Simplify the Sequence Expression

Notice that \( a_n = \frac{2^n - 1}{2^n} \) can be rewritten as \( a_n = 1 - \frac{1}{2^n} \). This simplifies analyzing the sequence as \( n \to \infty \).
03

Evaluate the Limit as n Approaches Infinity

As \( n \to \infty \), the term \( \frac{1}{2^n} \) approaches 0 because \( 2^n \) grows exponentially. Therefore, the expression \( 1 - \frac{1}{2^n} \) approaches \( 1 \).
04

Conclusion About Convergence

Since \( a_n = 1 - \frac{1}{2^n} \to 1 \) as \( n \to \infty \), the sequence converges to 1. Therefore, the sequence \( \{a_n\} \) is convergent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limits
In mathematics, a limit is a fundamental concept used to understand the behavior of functions and sequences as they approach certain points or values. For sequences, limits help us find what value a sequence approaches as the number of terms goes to infinity. In simple terms, if we say a sequence has a limit, it means that as we go further out in the sequence, the terms get closer and closer to a specific number.

When analyzing the sequence given in the exercise, the limit is crucial. We determined that as the sequence progresses (as the variable \( n \) becomes very large), the part \( \frac{1}{2^n} \) gets closer to zero. This is because the denominator \( 2^n \) increases exponentially, which makes the fraction very small. Hence, the sequence approaches \( 1 \) since the expression simplifies to \( 1 - \frac{1}{2^n} \). This behavior of the sequence getting closer to the number \( 1 \) allows us to conclude that the sequence converges to that value.
Exponential Functions
Exponential functions are mathematical expressions where a constant base is raised to a variable exponent, typically denoted as \( f(x) = a^x \), where \( a \) is a positive constant. These functions grow rapidly and are often used to model growth and decay processes.

In the context of the given sequence \( a_n = \frac{2^n - 1}{2^n} \), the term \( 2^n \) is an exponential function. Its property of growing exponentially plays a significant role in determining the sequence's behavior. As \( n \) increases, \( 2^n \) becomes very large, causing \( \frac{1}{2^n} \) to become very small since the numerator \( 1 \) remains constant. This rapid growth of \( 2^n \) demonstrates the powerful nature of exponential functions in influencing the convergence of sequences.

Understanding exponential growth helps us grasp why the term \( 1 - \frac{1}{2^n} \) approaches \( 1 \) as \( n \) becomes very large, illustrating how the exponential component drives this convergence.
Infinite Sequences
Infinite sequences are lists of numbers written in a specific order that continue indefinitely. Each number in the sequence is called a term, and the sequence itself is often represented with a special formula or rule that defines how to find each term.

When we examine an infinite sequence, like \( a_n = \frac{2^n - 1}{2^n} \), we are looking at a potentially endless series of terms. An essential question is whether the sequence converges to a limit, or if it diverges by not settling towards any particular value.
  • Converging Sequence: This is when terms in the sequence get closer to a fixed number as we move further along the sequence.
  • Diverging Sequence: This means that the terms do not settle towards a single, finite value.
For the sequence \( a_n = 1 - \frac{1}{2^n} \), we saw that it converges to the number \( 1 \). The shrinking effect of the exponential term \( \frac{1}{2^n} \) as \( n \) increases ensures that the sequence approaches a particular limit, showcasing how sequences can beautifully demonstrate mathematical convergence.

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