Chapter 1: Problem 18
(a) Write formulas for \(f^{\circ} g\) and \(g \circ f\) and find the (b) domain and (c) range of each.$$f(x)=x^{2}, g(x)=1-\sqrt{x}.$$
Short Answer
Expert verified
\(f^{\circ} g(x) = 1 - 2\sqrt{x} + x\), \(g^{\circ} f(x) = 1 - |x|\). Domain and range of \(f^{\circ} g\): \([0, \infty)\) and \([0, \infty)\), of \(g^{\circ} f\): \((-\infty, \infty)\) and \((-\infty, 1]\).
Step by step solution
01
Find the formula for f ∘ g
To find \(f^{\circ} g\), we substitute \(g(x) = 1 - \sqrt{x}\) into \(f(x) = x^{2}\). This gives us: \[f(g(x)) = f(1 - \sqrt{x}) = (1 - \sqrt{x})^2.\] Expand \((1 - \sqrt{x})^2\) to get: \[f(g(x)) = 1 - 2\sqrt{x} + x.\]
02
Find the formula for g ∘ f
To find \(g^{\circ} f\), we substitute \(f(x) = x^2\) into \(g(x) = 1 - \sqrt{x}\). This gives us: \[g(f(x)) = g(x^2) = 1 - \sqrt{x^2}.\] Since \(\sqrt{x^2} = |x|\), \[g(f(x)) = 1 - |x|.\]
03
Find the domain of f ∘ g
The domain of \(f^{\circ} g = (1 - \sqrt{x})^2\) is determined by the domain of \(g(x)\), since \(f(x)\) is defined for all real numbers. For \(g(x) = 1 - \sqrt{x}\) to be real, \(x\) must be non-negative. Thus, the domain of \(f^{\circ} g\) is \([0, \infty)\).
04
Find the domain of g ∘ f
The domain of \(g^{\circ} f = 1 - |x|\) is determined by ensuring \(f(x) = x^2\) is non-negative (it's always true since squares are positive or zero), and \(\sqrt{x^2} = |x|\) is defined for all real \(x\). Therefore, the domain of \(g^{\circ} f\) is \((-\infty, \infty)\).
05
Find the range of f ∘ g
The range of \(f^{\circ} g = 1 - 2\sqrt{x} + x\) depends on feasible values. Since \(1 - \sqrt{x}\) is always positive for \(x \geq 0\), \((1 - \sqrt{x})^2\) achieves a minimum of 0 at \(x = 1\) and increases without bound as \(x\) increases. Therefore, the range is \([0, \infty)\).
06
Find the range of g ∘ f
The range of \(g^{\circ} f = 1 - |x|\) depends on the values \(|x|\) can take. Since \(|x|\) ranges from 0 to infinity, \(1 - |x|\) ranges from 1 to negative infinity. Thus, the range is \((-\infty, 1]\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain and Range
Understanding the domain and range of a function is crucial for fully grasping function compositions. The **domain** of a function is the set of all possible input values (the x-values) which will produce a valid output, while the **range** is the set of all possible output values (the y-values) that the function can produce.
When dealing with the function compositions like
For example, in the composition \( f^{\circ} g = (1 - \sqrt{x})^2 \), since the function \( g(x) \) must be defined, \( x \) should be non-negative, giving a domain of \([0, \infty)\). Additionally, the range resulted from the values the composition can reach, such as being all non-negative values that start from zero and go towards infinity.
Similarly, for \( g^{\circ} f = 1 - |x| \), the domain is all real numbers because it starts with a function \( f(x) \) defined for all real numbers. The range here reaches from \(-\infty\) to 1 because \( 1 - |x| \) can never be more than 1, introducing transformations from the composition functions.
When dealing with the function compositions like
- \( f \circ g \)
- \( g \circ f \)
For example, in the composition \( f^{\circ} g = (1 - \sqrt{x})^2 \), since the function \( g(x) \) must be defined, \( x \) should be non-negative, giving a domain of \([0, \infty)\). Additionally, the range resulted from the values the composition can reach, such as being all non-negative values that start from zero and go towards infinity.
Similarly, for \( g^{\circ} f = 1 - |x| \), the domain is all real numbers because it starts with a function \( f(x) \) defined for all real numbers. The range here reaches from \(-\infty\) to 1 because \( 1 - |x| \) can never be more than 1, introducing transformations from the composition functions.
Square Root Functions
Square root functions, like \( g(x) = 1 - \sqrt{x} \), have specific properties that influence both domain and range.
When calculating compositions involving square roots, each step must maintain non-negative constraints. For example, within the composition \( f \circ g \), which evaluates to \( (1 - \sqrt{x})^2 \), this domain restriction persists but affects the output in its range by transforming values to vary from zero upwards as \( x \) increases, due to the squaring effect neutralizing potential negative impacts.
- The domain of a square root function includes all values for which the expression inside the square root is non-negative, since square roots of negative numbers are not defined in the set of real numbers.
- This means for \( g(x) = 1 - \sqrt{x} \), \( x \) must be greater than or equal to zero. As a result, the domain is \([0, \infty)\).
When calculating compositions involving square roots, each step must maintain non-negative constraints. For example, within the composition \( f \circ g \), which evaluates to \( (1 - \sqrt{x})^2 \), this domain restriction persists but affects the output in its range by transforming values to vary from zero upwards as \( x \) increases, due to the squaring effect neutralizing potential negative impacts.
Absolute Value Functions
The absolute value function, represented here as \( |x| \), is used in the composition \( g(f(x)) = 1 - |x| \).
Through the composition \( g \circ f \), one sees that \( |x| \) maintains function integrity over all real numbers, allowing a domain of \((-\infty, \infty)\). The range, on the other hand, adjusts to \((-\infty, 1]\) because subtracting non-negative values (\(|x|\)) from 1 provides outputs that peak at 1 and extend downwards without bound. The understanding of absolute value functions reinforces how compositions can invert or maintain expected value outputs.
- The absolute value of a number returns its distance from zero on the number line, essentially removing any negative sign, so it's always non-negative.
- This property is valuable in ensuring outputs that rely on symmetry around zero, such as when calculating expressions like \( \sqrt{x^2} = |x| \).
Through the composition \( g \circ f \), one sees that \( |x| \) maintains function integrity over all real numbers, allowing a domain of \((-\infty, \infty)\). The range, on the other hand, adjusts to \((-\infty, 1]\) because subtracting non-negative values (\(|x|\)) from 1 provides outputs that peak at 1 and extend downwards without bound. The understanding of absolute value functions reinforces how compositions can invert or maintain expected value outputs.