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Solve the differential equations in Exercises \(1-14\) $$y^{\prime}+(\tan x) y=\cos ^{2} x, \quad-\pi / 2 < x < \pi / 2$$

Short Answer

Expert verified
The solution is \( y = \sin x \cos x + C \cos x \).

Step by step solution

01

Identify the Type of Differential Equation

The given differential equation is of the form \( y' + P(x)y = Q(x) \) with \( P(x) = \tan x \) and \( Q(x) = \cos^2 x \). This is a first-order linear differential equation.
02

Find the Integrating Factor

The integrating factor \( \mu(x) \) is given by \( e^{\int P(x) \, dx} = e^{\int \tan x \, dx} \). The integral of \( \tan x \) is \( -\ln |\cos x| \), so the integrating factor is \( \mu(x) = e^{\ln |\sec x|} = \sec x \).
03

Multiply through by the Integrating Factor

Multiply the entire differential equation by the integrating factor \( \sec x \): \[ \sec x y' + y \cdot \sec x \tan x = \cos x. \] This simplifies to \[ \frac{d}{dx}(y \cdot \sec x) = \cos x. \]
04

Integrate Both Sides

Integrate both sides of the equation: \[ \int \frac{d}{dx}(y \cdot \sec x) \, dx = \int \cos x \, dx. \] This gives \[ y \cdot \sec x = \sin x + C, \] where \( C \) is the integration constant.
05

Solve for y

Multiply both sides by \( \cos x \) to solve for \( y \): \[ y = \sin x \cos x + C \cos x. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integrating Factor
In the world of differential equations, the integrating factor is a crucial tool for simplifying first-order linear differential equations. An integrating factor is essentially a function that, when multiplied by the original differential equation, makes it easier to solve. It transforms the equation into one where the left-hand side becomes the derivative of a product of functions. This allows for direct integration to find the solution.

To determine the integrating factor, we compute \[ \mu(x) = e^{\int P(x) \, dx} \]where \( P(x) \) is the coefficient of \( y \) in the equation \( y' + P(x) y = Q(x) \). In our example, \( P(x) = \tan x \). The integrating factor hence becomes \[ \mu(x) = e^{\int \tan x \, dx} = e^{-\ln |\cos x|} = \sec x. \]Applying the integrating factor transforms the differential equation into a form that can be easily integrated on both sides. This is why the integrating factor is such a powerful concept in solving linear differential equations.
Differential Equations
Differential equations are equations that relate a function with its derivatives. These can be used to model a wide array of real-world systems, such as physics dynamics, population growth, or electrical circuits. In essence, they are crucial for understanding how changing rates affect systems.

Our given differential equation \( y' + \tan x y = \cos^2 x \) is a first-order linear differential equation. This means that it involves the first derivative of \( y \), which is \( y' \), and the terms \( y \) and \( x \) themselves, but no higher derivatives or powers of \( y \).

Understanding these types of equations involves identifying their form, which can often be written as \( y' + P(x) y = Q(x) \). Solving these equations often requires techniques like finding the integrating factor, which helps to make them solvable by standard integration methods.
Solutions of Differential Equations
Once we've utilized techniques like determining the integrating factor, we can proceed to solve the differential equation. The solution process generally involves these steps:
  • Identifying the type and structure of the differential equation.
  • Finding and applying the integrating factor to transform the equation.
  • Integrating both sides to find the general solution.
  • Solving for the original function \( y \) if necessary.
In our example, after applying the integrating factor, the transformation allows us to integrate both sides effortlessly. The right side, when integrated with respect to \( x \), leads us to the expression \( y \cdot \sec x = \sin x + C \), where \( C \) is the constant of integration.

Finally, to solve for \( y \), we isolate it by multiplying both sides by \( \cos x \), giving us the solution:

\[ y = \sin x \cos x + C \cos x \]
This represents a family of functions that solve the differential equation, each different \( C \) corresponding to a specific solution depending on initial conditions or further constraints.
Trigonometric Functions
Trigonometric functions play a significant role when working with differential equations, especially when the equations are defined over specific intervals involving angles. Functions like sine, cosine, and tangent frequently appear in problems due to their periodicity and relationships with angles in radians, which are crucial in physics and engineering.

In our differential equation, we encountered \( \tan x \) and \( \cos^2 x \) as key components. The tangent function is particularly interesting as its derivative has trigonometric relationships that can simplify through integration, as seen in the integrating factor's calculation: \( \int \tan x \, dx = -\ln |\cos x| \).

By understanding these functions and their derivatives, we can simplify and solve equations that might otherwise seem complex. Mastery of trigonometric identities and integration techniques is vital in addressing differential equations like these efficiently.

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Most popular questions from this chapter

In 1925 Lotka and Volterra introduced the predator-prey equations, a system of equations that models the populations of two species, one of which preys on the other. Let \(x(t)\) represent the number of rabbits living in a region at time \(t,\) and \(y(t)\) the number of foxes in the same region. As time passes, the number of rabbits increases at a rate proportional to their population, and decreases at a rate proportional to the number of encounters between rabbits and foxes. The foxes, which compete for food, increase in number at a rate proportional to the number of encounters with rabbits but decrease at a rate proportional to the number of foxes. The number of encounters between rabbits and foxes is assumed to be proportional to the product of the two populations. These assumptions lead to the autonomous system $$ \begin{array}{l}{\frac{d x}{d t}=(a-b y) x} \\ {\frac{d y}{d t}=(-c+d x) y}\end{array} $$ where \(a, b, c, d\) are positive constants. The values of these constants vary according to the specific situation being modeled. We can study the nature of the population changes without setting these constants to specific values. What happens to the rabbit population if there are no foxes present?

In Exercises \(1-8\) \begin{equation}\begin{array}{l}{\text { a. Identify the equilibrium values. Which are stable and which }} \\ {\text { are unstable? }} \\ {\text { b. Construct a phase line. Identify the signs of } y^{\prime} \text { and } y^{\prime \prime} \text { . }} \\ {\text { c. Sketch several solution curves. }}\end{array}\end{equation} $$y^{\prime}=\sqrt{y}, \quad y>0$$

Use Euler's method to calculate the first three approximations to the given initial value problem for the specified increment size. Calculate the exact solution and investigate the accuracy of your approximations. Round your results to four decimal places. \(y^{\prime}=2 x e^{x^{2}}, \quad y(0)=2, \quad d x=0.1\)

Show that the solution of the initial value problem $$y^{\prime}=x+y, \quad y\left(x_{0}\right)=y_{0}$$ is $$y=-1-x+\left(1+x_{0}+y_{0}\right) e^{x-x_{0}}.$$

Write an equivalent first-order differential equation and initial condition for \(y .\) \(y=2-\int_{0}^{x}(1+y(t)) \sin t d t\)

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