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Use Euler's method to calculate the first three approximations to the given initial value problem for the specified increment size. Calculate the exact solution and investigate the accuracy of your approximations. Round your results to four decimal places. \(y^{\prime}=2 x y+2 y, \quad y(0)=3, \quad d x=0.2\)

Short Answer

Expert verified
Euler's approximations at steps: 4.2, 6.016, 9.3850. Exact values: 4.5559, 6.3882, 8.954.

Step by step solution

01

Understand Euler's Method

Euler's method is a numerical technique for solving ordinary differential equations (ODEs). It gives an approximate solution by using an iterative approach. The formula is given by: \[ y_{n+1} = y_n + f(x_n, y_n) imes dx \] where \( f(x_n, y_n) = y' \), and \( dx \) is the step size.
02

Define the Function and Initial Values

From the exercise, the ODE is \( y' = 2xy + 2y \), and the initial condition is \( y(0) = 3 \). The step size is \( dx = 0.2 \). This means we will calculate the new approximations of \( y \) starting from \( y(0) \).
03

Calculate the First Approximation

Using Euler's method, calculate \( y_1 \):- Start with \( x_0 = 0 \) and \( y_0 = 3 \).- Calculate \( f(x_0, y_0) = 2 \times 0 \times 3 + 2 \times 3 = 6 \).- Compute \( y_1 = y_0 + f(x_0, y_0) \times dx = 3 + 6 \times 0.2 = 4.2 \).
04

Calculate the Second Approximation

Now, calculate \( y_2 \):- Substitute \( x_1 = 0.2 \) and \( y_1 = 4.2 \).- Calculate \( f(x_1, y_1) = 2 \times 0.2 \times 4.2 + 2 \times 4.2 = 10.08 \).- Compute \( y_2 = y_1 + f(x_1, y_1) \times dx = 4.2 + 10.08 \times 0.2 = 6.016 \).
05

Calculate the Third Approximation

Proceed with \( y_3 \):- Substitute \( x_2 = 0.4 \) and \( y_2 = 6.016 \).- Calculate \( f(x_2, y_2) = 2 \times 0.4 \times 6.016 + 2 \times 6.016 = 16.8448 \).- Compute \( y_3 = y_2 + f(x_2, y_2) \times dx = 6.016 + 16.8448 \times 0.2 = 9.38496 \).- Round \( y_3 \) to four decimal places: 9.3850.
06

Determine the Exact Solution

To find the exact solution, solve the differential equation analytically. The equation can be rewritten as \( y' = 2y(x+1) \). This suggests a separation of variables, leading to \( \frac{dy}{y} = 2(x+1)dx \). Integrating both sides, we get:- \( \ln |y| = x^2 + 2x + C \).- Solve for \( y \): \( y = Ce^{x^2 + 2x} \).- Use the initial condition \( y(0) = 3 \) to determine \( C \): \( 3 = Ce^0 \), hence \( C = 3 \).- The exact solution is \( y = 3e^{x^2 + 2x} \).
07

Compare with Exact Values

Calculate the exact values at each step and compare them with the approximations:- At \( x = 0.2 \), exact \( y = 3e^{0.44} \approx 4.5559 \).- At \( x = 0.4 \), exact \( y = 3e^{1.36} \approx 6.3882 \).- At \( x = 0.6 \), exact \( y = 3e^{2.76} \approx 8.954 \).
08

Conclusion on Accuracy

Compare approximation and exact solution values:- At \( x = 0.2 \), approximation: 4.2, exact: 4.5559.- At \( x = 0.4 \), approximation: 6.016, exact: 6.3882.- At \( x = 0.6 \), approximation: 9.3850, exact: 8.954.The approximations diverge slightly from the exact solution, demonstrating some error inherent in Euler's method.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Numerical Methods
Numerical methods are mathematical techniques used to find approximate solutions to complex mathematical problems. These methods are particularly useful for solving equations that cannot be easily solved analytically. One popular numerical method is Euler's method, which is often used to approximate solutions to ordinary differential equations (ODEs).
Euler's method provides a straightforward approach, calculating successive values through an iterative process. The method uses a small step size to move from one point to the next, building an approximation of the function's curve. Although it introduces some errors, the simplicity of Euler's method makes it a good starting point for understanding numerical solutions in mathematics.
It's essential to remember that the choice of step size \( dx \) significantly affects the accuracy of the approximation. Smaller step sizes generally lead to more accurate results, though they require more computations to cover the same range.
Ordinary Differential Equations
An ordinary differential equation (ODE) involves functions and their derivatives. They describe how a function's value changes concerning another variable. ODEs appear frequently in various scientific and engineering fields to model real-world dynamics, from physics to economics.
The particular ODE in our exercise is \( y' = 2xy + 2y \). This equation means that the rate of change of \( y \) depends on the current values of \( x \) and \( y \). Solving an ODE provides you with a function or set of values that detail how these changes unfold across different values of \( x \).
Due to their complexity, many ODEs cannot be solved using standard algebraic methods. That's where numerical methods like Euler's come into play, offering approximate solutions where exact solutions might not be readily available.
Initial Value Problem
An initial value problem (IVP) involves an ODE accompanied by a specific value called the initial condition. This condition ties down the starting point of the function at a given value of \( x \). For example, in our exercise, the initial condition is \( y(0) = 3 \).
The initial condition ensures that among the numerous possible solutions to the differential equation, we find the one that starts from this particular point. It is like setting an anchor point for the curve we are approximating.
The computed solutions, starting with the initial value, help trace out the path of the curve as it moves away from the initial condition. Euler's method heavily relies on the initial value to compute subsequent approximations, making accurate determination of this initial setup crucial.
Approximation Accuracy
Approximation accuracy in numerical methods like Euler's revolves around measuring how close the approximated values are to the exact solution. It involves evaluating and comparing the results obtained from the method with the known or exact function solutions.
In our exercise, at each step of Euler's approximation, we create a certain degree of error due to the incremental nature of the method. The longer the steps (larger \( dx \)), the more significant the error tends to become. However, smaller steps increase computational effort.
For example, at \( x = 0.4 \), the approximation \( y = 6.016 \) is off from the exact solution \( y \approx 6.3882 \), demonstrating Euler's method's inherent trade-off between ease of computation and precision. Understanding this error and its sources is key in enhancing the effectiveness of numerical approaches in solving differential equations.

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Most popular questions from this chapter

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