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Solve the initial value problems in Exercises \(15-20\) $$\theta \frac{d y}{d \theta}+y=\sin \theta, \quad \theta>0, \quad y(\pi / 2)=1$$

Short Answer

Expert verified
The solution is \( y = \frac{-\cos\theta + \frac{\pi}{2}}{\theta} \).

Step by step solution

01

Identify the Type of Differential Equation

The given differential equation \( \theta \frac{dy}{d\theta} + y = \sin\theta \) is a linear first-order non-homogeneous differential equation. We will solve it using an integrating factor.
02

Rearrange the Equation

Standard form for the differential equation is \( \frac{dy}{d\theta} + P(\theta)y = Q(\theta) \). The given equation can be rearranged to \( \frac{dy}{d\theta} + \frac{1}{\theta}y = \frac{\sin\theta}{\theta} \). Identify \( P(\theta) = \frac{1}{\theta} \) and \( Q(\theta) = \frac{\sin\theta}{\theta} \).
03

Find the Integrating Factor

The integrating factor \( \mu(\theta) \) is found using the formula \( \mu(\theta) = e^{\int P(\theta) d\theta} = e^{\int \frac{1}{\theta} d\theta} = e^{\ln|\theta|} = \theta \).
04

Apply the Integrating Factor

Multiply the entire differential equation by the integrating factor \( \theta \) to obtain \( \theta \frac{dy}{d\theta} + y = \sin\theta \), which simplifies to \( \theta \frac{dy}{d\theta} + y = \sin\theta \). This is the original equation, confirming the factor is correctly applied.
05

Solve the Differential Equation

The equation \( \frac{d}{d\theta}(\theta y) = \sin\theta \) implies \( \theta y = \int \sin\theta \, d\theta + C \). Integrating \( \int \sin\theta \, d\theta \) gives \( -\cos\theta \). Therefore, \( \theta y = -\cos\theta + C \).
06

Apply the Initial Condition

Given that \( y(\pi/2) = 1 \), substitute \( \theta = \frac{\pi}{2} \) and \( y = 1 \) into \( \theta y = -\cos\theta + C \). This results in \( \frac{\pi}{2} \cdot 1 = -\cos\left(\frac{\pi}{2}\right) + C \), simplifying to \( \frac{\pi}{2} = 0 + C \). Hence, \( C = \frac{\pi}{2} \).
07

Write the Final Solution

Substituting \( C = \frac{\pi}{2} \) back into the expression for \( \theta y \), we have \( \theta y = -\cos\theta + \frac{\pi}{2} \), and thus \( y = \frac{-\cos\theta + \frac{\pi}{2}}{\theta} \). This is the solution to the differential equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integrating Factor
A crucial tool for solving linear first-order differential equations is the integrating factor. This clever method transforms a complex differential equation into something much simpler. To use it, you first rearrange the equation into the standard form: \( \frac{dy}{dx} + P(x)y = Q(x) \). Here, \( P(x) \) and \( Q(x) \) are known functions. The integrating factor, denoted as \( \mu(x) \), is calculated using the expression \( e^{\int P(x) \, dx} \).

In our exercise, with \( P(\theta) = \frac{1}{\theta} \), the integrating factor becomes \( \theta \). When you multiply every term in the differential equation by this factor, it allows the left-hand side to be expressed as the derivative of a product, \( \frac{d}{d\theta}(\theta y) \).

This is very helpful because it simplifies the differential equation significantly, making it easy to integrate both sides. The power of the integrating factor lies in reducing the problem to a standard integration task.
Initial Value Problem
An initial value problem (IVP) in differential equations is more than just finding a general solution. It also involves satisfying specific conditions given at an initial point. Typically, this is presented with a differential equation alongside conditions such as \( y(x_0) = y_0 \) for some initial point \( x_0 \).

In this exercise, the initial value is given as \( y(\pi/2) = 1 \). After we find the general solution to the differential equation, we use this initial condition to solve for any constants of integration. It helps to pin down a specific solution (among many possible ones) that exactly fits the behavior described by the IVP.

This step is essential when modeling real-world situations, where starting conditions are known, and the behavior of the system needs to be predicted accurately from there.
Non-Homogeneous Differential Equation
A linear differential equation is termed non-homogeneous if it includes a term independent of the unknown function, usually denoted as \( Q(x) \). This is as opposed to homogeneous equations, which only involve the function and its derivatives equating to zero.

The equation \( \theta \frac{dy}{d\theta} + y = \sin \theta \) is such an example, where \( Q(\theta) = \sin \theta \). Solving non-homogeneous equations often requires finding a particular solution that satisfies this extra term and the corresponding homogeneous equation solution.

Using the integrating factor simplifies this task, as the integrating factor correctly modifies the differential equation to easily incorporate \( Q(x) \). Conclusively, by integrating, we tackle both aspects simultaneously, merging into the complete solution that encompasses both the homogeneous and particular parts.

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Most popular questions from this chapter

Have no explicit solution in terms of elementary functions. Use a CAS to explore graphically each of the differential equations. \(y^{\prime}=\cos (2 x-y), \quad y(0)=2 ; \quad 0 \leq x \leq 5, \quad 0 \leq y \leq 5\)

Obtain a slope field and graph the particular solution over the specified interval. Use your CAS DE solver to find the general solution of the differential equation. A logistic equation \(y^{\prime}=y(2-y), y(0)=1 / 2 ; 0 \leq x \leq 4,\) \(0 \leq y \leq 3\)

Show that the solution of the initial value problem $$y^{\prime}=x+y, \quad y\left(x_{0}\right)=y_{0}$$ is $$y=-1-x+\left(1+x_{0}+y_{0}\right) e^{x-x_{0}}.$$

Use Euler's method to calculate the first three approximations to the given initial value problem for the specified increment size. Calculate the exact solution and investigate the accuracy of your approximations. Round your results to four decimal places. \(y^{\prime}=2 x e^{x^{2}}, \quad y(0)=2, \quad d x=0.1\)

Use a CAS to explore graphically each of the differential equations. Perform the following steps to help with your explorations. a. Plot a slope field for the differential equation in the given \(x y\)-window. b. Find the general solution of the differential equation using your CAS DE solver. c. Graph the solutions for the values of the arbitrary constant \(C=-2,-1,0,1,2\) superimposed on your slope field plot. d. Find and graph the solution that satisfies the specified initial condition over the interval \([0, b].\) e. Find the Euler numerical approximation to the solution of the initial value problem with 4 subintervals of the \(x\)-interval and plot the Euler approximation superimposed on the graph produced in part (d). f. Repeat part (e) for \(8,16,\) and 32 subintervals. Plot these three Euler approximations superimposed on the graph from part (e). g. Find the error \((y\) (exact) \(-y\) (Euler)) at the specified point \(x=b\) for each of your four Euler approximations. Discuss the improvement in the percentage error. \(y^{\prime}=(\sin x)(\sin y), \quad y(0)=2 ; \quad-6 \leq x \leq 6, \quad-6 \leq y \leq 6;\) \(b=3 \pi / 2\)

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