Chapter 9: Problem 12
The autonomous differential equations in Exercises \(9-12\) represent models for population growth. For each exercise, use a phase line analysis to sketch solution curves for \(P(t),\) selecting different starting values \(P(0) .\) Which equilibria are stable, and which are unstable? $$\frac{d P}{d t}=3 P(1-P)\left(P-\frac{1}{2}\right)$$
Short Answer
Step by step solution
Identify Equilibrium Points
Analyze Stability of Equilibrium Points
Sketch Phase Line
Solution Curves Based on Initial Conditions
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Population Growth
- Growth rate: the multiplier of the function, which in this case is 3.
- Carrying capacity: represented by the factor \((1-P)\), suggesting a decrease in growth rate as the population nears the carrying capacity.
- Allee Effect: represented by \(P-\frac{1}{2}\), implying a threshold below which population cannot sustain.
Equilibrium Points
- \( P = 0 \)
- \( P = \frac{1}{2} \)
- \( P = 1 \)
Phase Line Analysis
- Between \( P = 0 \) and \( P = \frac{1}{2} \), the arrow points right, showing population increase in this range.
- Convergence of arrows at \( P = \frac{1}{2} \) shows stability.
- Between \( P = \frac{1}{2} \) and \( P = 1 \), the arrow points right initially and left after passing \( P = 1 \).
Stability Analysis
- \( P = 0 \): Unstable, since small increases cause the population to grow.
- \( P = \frac{1}{2} \): Stable, as small deviations result in the population returning to this level.
- \( P = 1 \): Unstable, as deviations can cause population decrease towards \( 0.5 \)