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Centroid Find the centroid of the region bounded by the \(x\) -axis, the curve \(y=\sec x,\) and the lines \(x=-\pi / 4, x=\pi / 4\)

Short Answer

Expert verified
The centroid is \((0, \frac{1}{2 \ln(\sqrt{2} + 1)})\).

Step by step solution

01

Identify the region

The region is bounded by the curve \( y = \sec x \), the \( x \)-axis, and the vertical lines \( x = -\frac{\pi}{4} \) and \( x = \frac{\pi}{4} \). This forms a symmetric region about the \( y \)-axis.
02

Calculate the area

The area \( A \) of the region is given by the integral \( A = \int_{-\pi/4}^{\pi/4} \sec x \, dx \). We calculate this integral using trigonometric identities and integration techniques, resulting in \( A = 2 \ln(\sqrt{2} + 1) \).
03

Compute the centroid coordinates

The centroid \( (\overline{x}, \overline{y}) \) for a region is given by \( \overline{x} = \frac{1}{A} \int_{-\pi/4}^{\pi/4} x \sec x \, dx \) and \( \overline{y} = \frac{1}{2A} \int_{-\pi/4}^{\pi/4} \sec^2 x \, dx \).
04

Solve for \( \overline{x} \)

Since the region is symmetric about the \( y \)-axis, \( \overline{x} = 0 \).
05

Solve for \( \overline{y} \)

To find \( \overline{y} \), compute the integral \( \int_{-\pi/4}^{\pi/4} \sec^2 x \, dx \), which equals \( 2 \tan(\pi/4) = 2 \). Therefore, \( \overline{y} = \frac{1}{2 \cdot 2 \ln(\sqrt{2} + 1)} \).
06

Simplify \( \overline{y} \)

Simplifying gives \( \overline{y} = \frac{1}{2 \ln(\sqrt{2} + 1)} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

trigonometric integration
When working with functions like secant, trigonometric integration offers a systematic approach to solve the integral. Given a curve like \( y = \sec x \), you need to integrate trigonometric identities to find values like area or centroid coordinates. The integral involved, \( \int \sec x \, dx \), appears difficult, but with substitution and identities, like \( \sec x = \frac{1}{\cos x} \), the problem becomes manageable. Combined with integration techniques, you'll simplify complex expressions and successfully determine the desired quantities. By recognizing the right identity and application, tasks such as finding areas under a secant curve become straightforward.
area under a curve
Calculating the area under a curve helps in various applications like physics or engineering to distinguish segments bounded by specific lines. Consider the integral \( A = \int_{-\pi/4}^{\pi/4} \sec x \, dx \). This integral determines the area of the curve above the \( x \)-axis by evaluating how much space the function takes up in that interval. The technique involves computing this integral to find \( A \), in this case, using the function \( \sec x \). Resulting in \( 2 \ln(\sqrt{2} + 1) \), this value informs further calculations, such as finding the centroid. Understanding areas like this underlines geometry and calculus's role in explaining the shape and space within curves.
symmetric region
A symmetric region means that part of your integral calculation can be simplified. Because the region from \( x = -\frac{\pi}{4} \) to \( x = \frac{\pi}{4} \) is symmetric about the \( y \)-axis, certain features allow short cuts. Specifically, because symmetry provides provable prediction about shape and center, the x-coordinate of the centroid becomes \( \overline{x} = 0 \). This symmetry effectively halves the work needed compared to non-symmetric calculations, allowing concentration on solving for \( \overline{y} \) alone. Recognizing symmetrical properties in calculus calculations simplifies many integral computations, which is beneficial for time-saving and accuracy.
integration techniques
Integration techniques play a pivotal role in solving equations dealing with centroids and other geometric features. Various techniques such as substitution, parts integration, and recognizing fundamental trigonometric identities are essential during calculations. For the integral of \( \sec x \), techniques involve using known identities to make the function integrable. For \( y = \sec^2 x \), it becomes simpler with trigonometric identities or parts integration. Mastering these techniques enables tackling similar problems efficiently and eliminates errors during the process. Practice with these techniques is crucial because it develops intuition for identifying possible substitutions and transformations necessary for solving complex integrals.

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