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Height The average height of American females aged \(18-24\) is normally distributed with mean \(\mu=65.5\) inches and \(\sigma=2.5\) inches. a. What percentage of females are taller than 68 inches? b. What is the probability a female is between \(5^{\prime} 1^{\prime \prime}\) and \(5^{\prime} 4^{\prime \prime}\) tall?

Short Answer

Expert verified
a. About 15.87% of females are taller than 68 inches. b. The probability a female is between 5'1" and 5'4" is approximately 23.84%.

Step by step solution

01

Convert Height to Z-score for Part (a)

First, transform the height from inches to a Z-score using the formula: \(Z = \frac{X - \mu}{\sigma}\). For part (a), the height \(X = 68\) inches, the mean \(\mu = 65.5\) inches, and the standard deviation \(\sigma = 2.5\) inches. The Z-score calculation is: \[ Z = \frac{68 - 65.5}{2.5} = 1.0 \].
02

Find the Percentage Taller than 68 Inches

Use the standard normal distribution table (Z-table) to find the probability that a Z-score is greater than 1.0. The table gives the probability less than a Z-score of 1.0 as approximately 0.8413. Therefore, the percentage of females taller than 68 inches is \(1 - 0.8413 = 0.1587\) or about 15.87%.
03

Convert Height to Inches for Part (b)

Convert the height from feet and inches to only inches. For a height of \(5'1''\), convert to inches: \(5 \times 12 + 1 = 61\) inches. Similarly, for \(5'4''\), convert to inches: \(5 \times 12 + 4 = 64\) inches. Thus, we need to find the probability for heights between 61 inches and 64 inches.
04

Find Z-scores for Part (b)

Calculate the Z-scores for both heights. For \(X = 61\) inches: \[ Z = \frac{61 - 65.5}{2.5} = -1.8 \]. For \(X = 64\) inches: \[ Z = \frac{64 - 65.5}{2.5} = -0.6 \].
05

Find Probabilities for Z-scores

Use the Z-table to find the probabilities for these Z-scores. For \(Z = -1.8\), the cumulative probability is approximately 0.0359. For \(Z = -0.6\), the cumulative probability is approximately 0.2743. The probability that a height is between these two values is the difference: \(0.2743 - 0.0359 = 0.2384\).
06

Convert to Percentage for Part (b)

To convert the probability to a percentage, multiply by 100. Thus, the probability that a female is between \(5'1''\) and \(5'4''\) is approximately 23.84%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score
In statistics, the Z-score is a powerful tool used to understand how far away a specific data point is from the mean of a distribution. It's especially useful when dealing with normally distributed data, like heights or test scores. The formula to calculate a Z-score is: \[ Z = \frac{X - \mu}{\sigma} \] Where:
  • \(X\) is the value you're interested in.
  • \(\mu\) is the mean of the distribution.
  • \(\sigma\) is the standard deviation.
The Z-score tells you how many standard deviations away your value, \(X\), is from the mean. A positive Z-score means the value is above the mean, while a negative Z-score means it's below the mean. For example, if the height of 68 inches corresponds to a Z-score of 1.0, this means it's one standard deviation above the average height. Using Z-scores can make finding probabilities in a normal distribution much easier and is a fundamental technique in statistics.
Standard Deviation
Standard deviation, symbolized as \(\sigma\), is a measure of the amount of variation or dispersion in a set of data values. It helps us understand how spread out the values in a distribution are around the mean. A small standard deviation means the data points tend to be close to the mean, while a large standard deviation indicates they are more spread out. Here's why standard deviation is so important:
  • It allows us to understand data variability and consistency.
  • It plays a crucial role in determining the Z-score.
  • It helps compare the spread of different datasets.
In the context of our height distribution, the standard deviation is 2.5 inches. This means most young adult American females' heights are within a range of 2.5 inches above or below the mean height of 65.5 inches. Whenever working with data sets, standard deviation is a key metric for assessing how clustered or spread the data is.
Probability
Probability in the context of normal distribution allows us to assess how likely it is for a particular value or range of values to occur. A standard normal distribution, or bell curve, has characteristics that make predictions possible. It is symmetrical with a peak at the mean, where most data points fall. To find probabilities:
  • Calculate the Z-score for the value(s) you're interested in.
  • Use a Z-table or standard normal distribution table to find the probability.
In our example with the height of American females: - For a height of 68 inches or more, we converted the height to a Z-score and found about 15.87% of females are taller than 68 inches. - For the probability of being between 61 and 64 inches tall, we used Z-scores to find a probability of approximately 23.84%. This is the likelihood of a female falling within this height range. By understanding probability, you gain insights into the expected frequencies of outcomes within a set of data, making it a cornerstone concept in statistics and data analysis.

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