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In Exercises \(35-68\) , use integration, the Direct Comparison Test, or the Limit Comparison Test to test the integrals for convergence. If more than one method applies, use whatever method you prefer. $$\int_{0}^{\pi / 2} \cot \theta d \theta$$

Short Answer

Expert verified
The integral diverges.

Step by step solution

01

Recognize the Integral

The integral we need to evaluate is \( \int_{0}^{\pi / 2} \cot \theta \, d\theta \). The cotangent function, \( \cot \theta = \frac{\cos \theta}{\sin \theta} \), is not defined at \( \theta = 0 \) and approaches infinity as \( \theta \) approaches \( \frac{\pi}{2} \) from the left.
02

Express as Improper Integral

Due to the behaviour of the cotangent function at the endpoints, we express the integral as an improper integral: \( \lim_{a \to 0^+} \int_{a}^{\pi/2} \cot \theta \, d\theta \).
03

Find Antiderivative

To integrate \( \cot \theta \), recall that the antiderivative of \( \cot \theta \) is \( \ln|\sin \theta| \) because the derivative of \( \ln|\sin \theta| \) is \( \frac{1}{\sin \theta} \cdot \cos \theta = \cot \theta \).
04

Evaluate the Improper Integral

Use the antiderivative to evaluate: \[\lim_{a \to 0^+} \int_{a}^{\pi/2} \cot \theta \, d\theta = \lim_{a \to 0^+} \left[ \ln|\sin \theta| \right]_{a}^{\pi/2}\] Evaluate it: \[= \lim_{a \to 0^+} \left(\ln |\sin(\pi/2)| - \ln |\sin(a)| \right)= \lim_{a \to 0^+} \left(0 - \ln(a) \right) = -\infty\] The integral diverges because \(\ln(a) \to -\infty\) as \(a \to 0^+\).
05

Conclusion

Since the limit as \(a \to 0^+\) results in negative infinity, the original improper integral \(\int_{0}^{\pi/2} \cot \theta \, d\theta\) diverges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergence Tests
Convergence tests are critical tools when dealing with improper integrals. These tests help us determine whether an integral converges to a finite value or diverges to infinity. An improper integral is usually evaluated over an infinite interval or approaches infinity at some point within the limits of integration. For such integrals, regular methods do not suffice, and convergence tests come into play.

A basic approach is to consider the behavior of the function near the problematic points. Key tests include:
  • The Direct Comparison Test - compare to an integral you already know converges or diverges.
  • The Limit Comparison Test - use a known integral and focus on the ratio of the functions.
The importance of these tests lies in their ability to identify convergence patterns efficiently, directing us to whether an integral will have a finite or infinite solution outcome.
Direct Comparison Test
The Direct Comparison Test is a straightforward method to analyze the convergence of improper integrals. It involves comparing the integral of interest to another integral whose behavior is already understood.

In using the Direct Comparison Test:
  • Choose a comparable function, \(g(x)\), such that \(0 \leq f(x) \leq g(x)\) for all \(x\) in the interval of integration.
  • If \(\int g(x)\) converges, then \(\int f(x)\) must also converge.
  • Similarly, if \(\int g(x)\) diverges, then \(\int f(x)\) must also diverge.
In practice, identifying an appropriate \(g(x)\) is crucial. For an effective comparison, one should know integrals of simpler functions (like polynomials or basic trigonometric ratios) and use them as benchmarks to predict convergence or divergence of complicated ones.
Limit Comparison Test
The Limit Comparison Test, while less direct than its counterpart, offers a robust way to determine convergence. With this test, we look at the limit of the ratio between the given function \(f(x)\) and a known function \(g(x)\) as \(x\) approaches the problematic point.

Here's how the Limit Comparison Test works:
  • Find a function \(g(x)\) that behaves similarly to \(f(x)\) near the point of concern.
  • Calculate the limit: \(\lim_{x \to c} \frac{f(x)}{g(x)}\), where \(c\) is the problematic point (could be infinity or a finite endpoint).
  • If this limit is a positive finite number, both \(\int f(x)\) and \(\int g(x)\) share the same convergence behavior.
Becoming comfortable with the Limit Comparison Test involves recognizing how different functions grow compared to each other, aiding in constructing an effective strategy to predict convergence or divergence outcomes.
Divergence
In calculus, divergence is the failure of a series or an integral to converge to a finite limit. Specifically, an integral diverging implies it grows without bound or tends to infinity.

More often than not, divergence is identified by finding that the limit of an evaluation of an improper integral approaches infinity. Common signs of potential divergence include:
  • The integrand grows rapidly as it approaches infinity.
  • The presence of a singularity within the integration bounds (e.g., division by zero).
  • Inability to bound the function compared to a known convergent integral.
Divergence can often be confirmed using tests like the Direct Comparison or the Limit Comparison Tests. Recognizing and diagnosing whether an integral diverges is fundamental in understanding the broader behaviors of functions and integrals in calculus.

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