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The integrals in Exercises \(1-34\) converge. Evaluate the integrals without using tables. $$\int_{-\infty}^{\infty} 2 x e^{-x^{2}} d x$$

Short Answer

Expert verified
The integral evaluates to 0.

Step by step solution

01

Identify the Integral Type

The integral \( \int_{-\infty}^{\infty} 2x e^{-x^2} \, dx \) is an improper integral because it involves integration over an infinite interval.
02

Recognize Symmetry and Odd Function

Notice that the integrand \( 2x e^{-x^2} \) is an odd function because \( f(-x) = -f(x) \). Since the limits of integration are symmetric (from \(-\infty\) to \(\infty\)), we can conclude that the integral of an odd function over symmetric limits is zero.
03

Conclude the Integral

By properties of definite integrals and odd functions, we conclude that \( \int_{-\infty}^{\infty} 2x e^{-x^2} \, dx = 0 \). This is due to the symmetry of the function canceling out the positive and negative areas.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Odd Functions
In mathematics, a function is considered odd if it satisfies the condition \( f(-x) = -f(x) \). This means that when you substitute a negative input into the function, the output is the negative of what you get with the positive input. For example, with our function \( 2x e^{-x^2} \), if we plug in \(-x\), we get \(-2x e^{-x^2} \), proving it's odd.
Odd functions have a special symmetry around the origin, meaning they are symmetric with respect to the origin in the coordinate plane. This symmetry can be very useful, as it often simplifies the work you have to do when calculating certain integrals, especially over symmetric intervals like from \(-\infty\) to \(\infty\).
Understanding when a function is odd helps identify patterns in integrals, especially when they're calculated over symmetrical limits.
Symmetry in Integrals
Symmetry is a powerful concept that can simplify the evaluation of integrals. When you deal with a function that has symmetry, such as being even or odd, there are specific properties that can be used. For odd functions, the symmetric integration property is quite straightforward:
- When you integrate an odd function over a symmetric interval \([-a, a]\), the result is always zero.
This is because the function's values over these intervals are mirror images that cancel each other out. Positive and negative areas under the curve offset, resulting in a total integral of zero.
The integral \(\int_{-\infty}^{\infty} 2x e^{-x^2} \, dx\) employs this property. The function \(2xe^{-x^2}\) is odd, and the limits of integration are symmetric. Thus, the integral resolves to zero without further computation!
Integration over Infinite Intervals
Improper integrals often deal with infinite intervals. They require special handling, as traditional calculus techniques assume finite limits. Instead of working directly from \(-\infty\) to \(\infty\), the integral is approached through the limit process.
- We define the improper integral by taking limits: \(\int_{-\infty}^{\infty} f(x) \, dx = \lim_{A \to \infty} \int_{-A}^{A} f(x) \, dx\).
This means you start by evaluating \(\int_{-A}^{A} f(x) \, dx\) and then take the limit as \(A\) approaches infinity. This method allows for evaluating \(\int_{-\infty}^{\infty} 2x e^{-x^2} \, dx\) once the odd function property is recognized, thereby quickly confirming that this integral equals zero.
By understanding how to work with infinite limits and recognizing odd functions, you can solve many problems involving improper integrals more efficiently.

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