Chapter 7: Problem 85
Show that $$\lim _{k \rightarrow \infty}\left(1+\frac{r}{k}\right)^{k}=e^{r}$$
Short Answer
Expert verified
The limit is \( e^r \).
Step by step solution
01
Understand the Limit Definition
Recognize that the expression \( \lim_{k\rightarrow \infty} \left(1+\frac{r}{k}\right)^{k} \) is a well-known limit that defines the exponential function. Specifically, as \( k \to \infty \), the expression \( \left(1+\frac{r}{k}\right)^k \) approaches \( e^r \).
02
Express in Exponential Form
Rewrite the expression using the natural exponential function. Recognize that the expression \( \left(1+\frac{r}{k}\right)^{k} \) can be rewritten as \( \exp\left(k \ln\left(1+\frac{r}{k}\right)\right) \).
03
Use Logarithmic Approximation
For values where \( x \) is close to 0, use the approximation \( \ln(1+x) \approx x - \frac{x^2}{2} + \frac{x^3}{3} - \ldots \). Applying this to \( \ln\left(1+\frac{r}{k}\right) \), we have \( \ln\left(1+\frac{r}{k}\right) \approx \frac{r}{k} - \frac{1}{2}\left(\frac{r}{k}\right)^2 + \ldots \).
04
Simplify the Expression
Multiply the approximation by \( k \):\( k \ln\left(1+\frac{r}{k}\right) \approx k \left(\frac{r}{k} - \frac{1}{2}\left(\frac{r}{k}\right)^2 + \ldots \right) = r - \frac{r^2}{2k} + \ldots \).
05
Take the Limit as \( k \to \infty \)
Observe that as \( k \to \infty \), the terms \(-\frac{r^2}{2k} + \ldots \) approach zero, which simplifies the expression to \( r \). Thus, the limit becomes:\( \lim_{k\rightarrow \infty} \exp\left(r - \frac{r^2}{2k} + \ldots\right) = \exp(r) \).
06
Conclude That the Limit is \( e^r \)
Since \( \exp(r) = e^r \), we conclude that:\( \lim _{k \rightarrow \infty}\left(1+\frac{r}{k}\right)^{k}=e^{r} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Function
An exponential function is a mathematical expression in which a variable appears in the exponent. One of the most important forms is the natural exponential function expressed as \( e^x \), where \( e \) is the mathematical constant approximately equal to 2.71828. Exponential functions have unique properties, especially their rate of growth, which is determined by the base. In this case, the base \( e \) results in a function that grows proportionally at every point, making it a key concept in calculus and natural phenomena.
- Exponential functions are essential in modeling population growth, radioactive decay, and many other natural processes.
- The limit expression given in the exercise, \( \left(1+\frac{r}{k}\right)^{k} \), is a classic example of approaching an exponential function as \( k \) becomes very large.
Natural Logarithm
The natural logarithm, denoted as \( \ln(x) \), is the inverse of the natural exponential function \( e^x \). Understanding the natural logarithm helps us deal with the exponential function and solve equations involving exponentials. It is based on Euler's number \( e \) and is hugely significant in calculus due to its ability to simplify the differentiation and integration of exponential functions.
- The natural logarithm is used to reverse the effect of an exponential, making expressions like \( \ln(e^x) \) simply equal to \( x \).
- In the exercise, \( \ln(1+\frac{r}{k}) \) is approximated to pave the way for expressing the original limit in terms of exponentials.
Limit Definition
In mathematics, a limit is a value that a function or sequence "approaches" as the input or index approaches some value. The limit is a fundamental notion in calculus and provides a way to understand the behavior of functions as they approach specific points. In this problem, the limit \( \lim_{k \rightarrow \infty} \left(1+\frac{r}{k}\right)^{k} = e^{r} \) is a key aspect of defining exponential growth through continuous compounding.
- Understanding limits helps in grasping how functions behave towards specific inputs, which is crucial in calculus.
- This problem showcases a special limit that underpins the natural exponential function \( e^x \).
Logarithmic Approximation
Logarithmic approximation is a technique used to simplify complex logarithmic expressions, making them more manageable, especially as certain values approach zero. The formula \( \ln(1+x) \approx x - \frac{x^2}{2} + \frac{x^3}{3} - \cdots \) is often used when \( x \) is small. This approximation is vital when expressing limits involving exponential functions.
- This method simplifies the understanding and calculation of limits, especially when the initial expressions are complex.
- In the exercise, it allows us to express \( \ln(1+\frac{r}{k}) \) in a form that can be easily managed as \( k \) approaches infinity.