/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 Designing a wok You are designin... [FREE SOLUTION] | 91Ó°ÊÓ

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Designing a wok You are designing a wok frying pan that will be shaped like a spherical bowl with handles. A bit of experimentation at home persuades you that you can get one that holds about 3L if you make it 9 \(\mathrm{cm}\) deep and give the sphere a radius of 16 \(\mathrm{cm}\) . To be sure, you picture the wok as a solid of revolution, as shown here, and calculate its volume with an integral. To the nearest cubic centimeter, what volume do you really get? (1 \(=1000 \mathrm{cm}^{3}\) )

Short Answer

Expert verified
The volume of the wok is approximately 3310 cm³.

Step by step solution

01

Set the Formula for Volume of a Spherical Cap

To find the volume of a spherical cap, we use the formula: \[ V = \frac{1}{3} \pi h^2 (3R - h) \] where \( h \) is the height of the cap (9 cm) and \( R \) is the radius of the sphere (16 cm).
02

Substitute the Values into the Formula

Plug the given values into the formula: \[ V = \frac{1}{3} \pi (9)^2 (3 \times 16 - 9) \].
03

Calculate the Expression

First, calculate \( (9)^2 = 81 \) and \( 3 \times 16 - 9 = 39 \). Then substitute back into the equation: \[ V = \frac{1}{3} \pi \times 81 \times 39 \].
04

Simplify to Find the Volume

Perform the multiplication: \( 81 \times 39 = 3159 \). Then, \[ V = \frac{1}{3} \times \pi \times 3159 = 1053 \times \pi \].
05

Calculate the Decimal Value

Finally, multiplying by \( \pi \approx 3.14159 \), we find \[ V = 1053 \times 3.14159 \approx 3310 \text{ cm}^3 \]. Since we round to the nearest cubic centimeter, the approximate volume is 3310 cm³.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Integral Calculus
Integral calculus is a branch of mathematics focusing on the concept of integration, which can be used to calculate quantities such as area, volume, and other results that describe accumulation. In simpler terms, it helps us add up infinitesimally small pieces to find a total value.
For volume calculations, integration involves summing up tiny slices or discs that make up a solid. This is especially useful for objects with curved surfaces, which can't easily be broken down into simpler shapes. When designing the wok, integral calculus helps us compute the precise volume of the spherical shape by considering it as an accumulated sum of thin discs.
In the exercise given, the calculation requires integrating to find the volume contained within the spherical cap of the wok. This approach allows us to be exact, despite the complex surface.
Exploring Spherical Geometry
Spherical geometry is the study of geometric properties on the surface of a sphere. Unlike Euclidean geometry, which deals with flat surfaces, spherical geometry involves curved spaces, making it interesting for calculations involving spheres.
A key feature of spherical geometry is that straight lines are replaced by great circles, which are the largest possible circles that can be drawn on the sphere. This understanding is crucial in designing objects like the wok.
The problem we are examining involves a spherical cap, a portion of the sphere "cut off" by a plane. The radius of the sphere and the height of the cap are primary parameters for calculating this cap's volume. By understanding these parameters, we can better comprehend how geometrical properties differ on a sphere compared to flat surfaces.
Volume Calculation in Context
Volume calculation is a fundamental aspect when designing real-world objects to ensure they meet specific functional requirements. It involves determining the amount of space an object occupies. In our case, this ensures that the wok can hold the desired amount of liquid or food.
The formula used, \( V = \frac{1}{3} \pi h^2 (3R - h) \), is specific to calculating the volume of a spherical cap, a common form in spherical objects. This formula works by considering the height of the cap and the sphere's radius, ultimately giving us the volume in cubic centimeters, a practical unit for design specifications.
By substituting the given values into the formula, we determined the wok's capacity accurately. This step involves simple arithmetic to obtain a concrete answer, followed by multiplication by π to accommodate for the circular nature of the object. Proper calculation ensures the wok holds the designated 3 liters.
Application of Solid of Revolution
A solid of revolution is a three-dimensional object created by rotating a two-dimensional shape around an axis. This concept is vital for understanding how the wok design can be visualized and calculated.
When the wok's cross-section is revolved around an axis, it creates a solid shape resembling the lower portion of a sphere, known as a spherical cap. This approach simplifies volume calculations because it uses the symmetry of the shape around the axis of rotation.
Recognizing the wok as a solid of revolution allows us to apply spherical geometry and integral calculus in a cohesive manner, converting a practical cooking design into a mathematical problem-solving exercise. By understanding the geometry and integrating across the shape, we can precisely compute how much space the wok occupies, ensuring its functionality.

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