Chapter 6: Problem 3
Find the volumes of the solids. The solid lies between planes perpendicular to the \(x\) -axis at \(x=-1\) and \(x=1 .\) The cross-sections perpendicular to the \(x\) -axis between these planes are squares whose bases run from the semicircle \(y=-\sqrt{1-x^{2}}\) to the semicircle \(y=\sqrt{1-x^{2}}.\)
Short Answer
Expert verified
The volume of the solid is 8 cubic units.
Step by step solution
01
Understanding the Problem
We're given shapes (squares) with bases on a semicircle from \(y = -\sqrt{1-x^2}\) to \(y = \sqrt{1-x^2}\) for \(x\) values from \(-1\) to \(1\). We need to find the volume of the 3D solid formed by these squares as they move along the \(x\)-axis.
02
Determine the Side Length of the Square
Each square is positioned with its base from \(y = -\sqrt{1-x^2}\) to \(y = \sqrt{1-x^2}\), making the base length \(\text{side} = 2\sqrt{1-x^2}\).
03
Express the Area of the Cross-Section
Since the cross-section is a square, the area \(A(x)\) can be calculated as the square of its side length. Therefore, \(A(x) = \left(2\sqrt{1-x^2}\right)^2 = 4(1-x^2)\).
04
Setup the Integral for the Volume
We need the volume of the solid, which is obtained by integrating the area of the cross-section from \(x = -1\) to \(x = 1\): \[ V = \int_{-1}^{1} A(x)\, dx = \int_{-1}^{1} 4(1-x^2)\, dx \]
05
Evaluate the Integral
Calculate the definite integral for volume:\[V = \int_{-1}^{1} 4(1-x^2)\, dx = 4 \left[ x - \frac{x^3}{3} \right]_{-1}^{1} \]First evaluate at \(x = 1\):\(4 \left( 1 - \frac{1^3}{3} \right) = 4 \left( 1 - \frac{1}{3} \right) = \frac{4 \cdot 2}{3} = \frac{8}{3}\)Then at \(x = -1\):\(4 \left( -1 + \frac{(-1)^3}{3} \right) = 4 \left( -1 + \frac{-1}{3} \right) = 4 \left( -\frac{4}{3} \right) = -\frac{16}{3}\)Volume calculation combining both results:\(V = \frac{8}{3} - \left(-\frac{16}{3}\right) = \frac{8}{3} + \frac{16}{3} = \frac{24}{3} = 8\)
06
Final Volume Calculation
The integral has been evaluated, giving us a final volume. Therefore, the volume of the solid is 8 cubic units.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross-Sectional Area
Cross-sectional areas are key to understanding the structure of a solid. When imagining a 3D solid, visualize cutting it down into simpler 2D shapes, called cross-sections. This process eases the calculation of volume.
In our exercise, the solid is sliced into square cross-sections along the x-axis. The base of each square stretches from the lower bound of the semicircle, given by the equation \(y = -\sqrt{1-x^2}\), to the upper bound \(y = \sqrt{1-x^2}\). This means that as we move along different values of \(x\), the length of each side of these square cross-sections will change.
In our exercise, the solid is sliced into square cross-sections along the x-axis. The base of each square stretches from the lower bound of the semicircle, given by the equation \(y = -\sqrt{1-x^2}\), to the upper bound \(y = \sqrt{1-x^2}\). This means that as we move along different values of \(x\), the length of each side of these square cross-sections will change.
- The base runs between two points: \(-\sqrt{1-x^2}\) and \(\sqrt{1-x^2}\).
- The length of the base is calculated as \(2\sqrt{1-x^2}\).
Definite Integral
The process of finding the volume of a solid using integration involves setting up and evaluating a definite integral. The definite integral allows you to add up the infinite cross-sectional areas along the interval where the solid exists.
When you compute a definite integral, you essentially sum up tiny bits, or increments, of area. These are represented as small slices along the \(x\)-axis, and by adding these slices together, you approximate the entire volume of the solid.
When you compute a definite integral, you essentially sum up tiny bits, or increments, of area. These are represented as small slices along the \(x\)-axis, and by adding these slices together, you approximate the entire volume of the solid.
- The definite integral from our exercise: \[ V = \int_{-1}^{1} 4(1-x^2)\, dx \] calculates the total volume.
- It is evaluated between \(x = -1\) and \(x = 1\), enclosing the full span where the cross-sections are defined.
Solid of Revolution
A solid of revolution is a 3D object created by rotating a 2D shape around an axis. It's similar to creating pottery on a spinning wheel—the shape you draw creates the full volumetric form as it spins.
For the problem in question, however, instead of revolving a shape, we use cross-sectional areas orthogonal (at a right angle) to the axis, which is somewhat similar. In this case, squares laid along the \(x\)-axis are similar in principle, because they're symmetric around the central axis of the semicircle.
For the problem in question, however, instead of revolving a shape, we use cross-sectional areas orthogonal (at a right angle) to the axis, which is somewhat similar. In this case, squares laid along the \(x\)-axis are similar in principle, because they're symmetric around the central axis of the semicircle.
- The semicircle equation, \(y = \pm\sqrt{1-x^2}\), creates a set boundary for our cross-sections.
- Though it's not a traditional 'revolution', the formation mirrors the idea since the final solid maintains symmetry.