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In Exercises \(15-22,\) graph the integrands and use known area formulas to evaluate the integrals. $$ \int_{-1}^{1}(2-|x|) d x $$

Short Answer

Expert verified
The integral evaluates to 1.

Step by step solution

01

Understanding the integrand

The given integrand is a function, defined as \(2 - |x|\). This function is a piecewise linear function that forms a V-shape when graphed. As we know, \(|x|\) is the absolute value of \(x\), which means this function measures the distance of \(x\) from 0 without considering the direction.
02

Graph the integrand function

The function \(2 - |x|\) can be split into two linear equations based on the absolute value:- For \(x \geq 0\), the function is \(f(x) = 2 - x\).- For \(x < 0\), the function is \(f(x) = 2 + x\). The graph is a V-shaped figure with a vertex at \((0, 2)\) and intercepts at \((1, 1)\) and \((-1, 1)\).
03

Identify the geometry of the graph

The graph of \(2 - |x|\) between \(-1\) and \(1\) forms an isosceles triangle. The vertices of this triangle are \((-1, 1)\), \((1, 1)\), and the vertex \((0, 2)\).
04

Calculate the base and height of the triangle

The base of the triangle extends horizontally from \(-1\) to \(1\), giving a base length of \(2\). The height of the triangle extends vertically from the base point (0, 1) up to the vertex (0, 2), giving a height of \(1\).
05

Apply the area formula for a triangle

To find the area of the triangle, we use the area formula for a triangle: \(\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}\).Substitute the base and height values: \[\text{Area} = \frac{1}{2} \times 2 \times 1 = 1.\]
06

Evaluate the integral

Since the area under the curve \(2 - |x|\) from \(-1\) to \(1\) corresponds to the area of the triangle, the integral \(\int_{-1}^{1}(2-|x|) dx\) evaluates to the area of the triangle, which is \(1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Piecewise Linear Functions
A piecewise linear function is a type of function built from straight-line sections. It's like connecting dots on a graph with straight lines. Just like in a puzzle, each segment or piece fits a specific part of the graph based on the input value (in this case, \(x\)).
In our exercise, the function \(2 - |x|\) is piecewise linear because it behaves differently depending on whether \(x\) is positive or negative.
  • For \(x \geq 0\), the function is \(2 - x\), which descends linearly as \(x\) increases.
  • For \(x < 0\), the function is \(2 + x\), which ascends linearly as \(x\) decreases.
These characteristics make the function look like the letter "V" when graphed, showcasing its piecewise linear nature.
Absolute Value
The absolute value function is a mathematical concept that determines the distance a number is from zero on a number line, without regard to direction. In simpler terms, it makes any number positive.
In the formula \(|x|\), this symbol "| |" indicates absolute value, taking any given \(x\) and converting it into its non-negative counterpart.
  • If \(x = 3\), then \(|x| = 3\).
  • If \(x = -5\), then \(|x| = 5\).
Absolute value is crucial in defining piecewise linear functions because it helps shape the curves by treating inputs symmetrically on either side of the y-axis.
Area Under a Curve
Finding the area under a curve is a fundamental concept in calculus, closely related to definite integrals. It involves calculating the space between the curve of a function and the x-axis over a specified interval.
This concept is like measuring the amount of paint needed to cover a shape bounded by the curve and the axis.
  • The graph of \(2 - |x|\) from \(-1\) to \(1\) forms a triangular shape.
  • The area under this curve can be found using geometry because the shape is a triangle.
By understanding the area under a curve, we can evaluate definite integrals like \(\int_{-1}^{1}(2-|x|) dx\), giving us insight into the accumulation or total change of a quantity described by the function.
Triangle Area Formula
The area of a triangle can be computed using the simple formula: \(\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}\). This equation helps determine the extent of a two-dimensional space enclosed by a triangular figure.
  • The base is one side of the triangle, often parallel to the x-axis in graph problems.
  • The height is the perpendicular distance from the base to the opposite vertex.
In our exercise, using the vertices \((-1, 1)\), \((1, 1)\), and the vertex \((0, 2)\), we identified that the base spans from \(-1\) to \(1\), resulting in a length of \(2\), and the height is \(1\). Applying these into the formula, the area becomes \(\frac{1}{2} \times 2 \times 1 = 1\), which helps us evaluate the integral as well.

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