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In Exercises \(1-16,\) find an antiderivative for each function. Do as many as you can mentally. Check your answers by differentiation. $$\text { a. }2 x^{-3} \quad \text { b. } \frac{x^{-3}}{2}+x^{2} \quad \text { c. }-x^{-3}+x-1 $$

Short Answer

Expert verified
a) \(-x^{-2} + C\); b) \(-\frac{x^{-2}}{4} + \frac{x^3}{3} + C\); c) \(\frac{x^{-2}}{2} + \frac{x^2}{2} - x + C\).

Step by step solution

01

Identify the function to integrate

We need to find an antiderivative of the given function. Let's start with part a, which is the function \(2x^{-3}\).
02

Use the power rule for integration

The power rule for integration states that \(\int x^n \, dx = \frac{x^{n+1}}{n+1} + C\) for \(n eq -1\). Here, \(n = -3\). Applying this rule: \[\int 2x^{-3} \, dx = 2 \cdot \frac{x^{-3+1}}{-3+1} + C = 2 \cdot \frac{x^{-2}}{-2} + C = -x^{-2} + C.\]
03

Apply the rule to part b

Evaluate the integral of \(\frac{x^{-3}}{2} + x^2\). The integral of each term using the power rule is: \[\int \frac{x^{-3}}{2} \, dx = \frac{1}{2} \cdot \frac{x^{-2}}{-2} = -\frac{x^{-2}}{4},\] \[\int x^2 \, dx = \frac{x^3}{3}.\] Combine these results to get the antiderivative: \[-\frac{x^{-2}}{4} + \frac{x^3}{3} + C.\]
04

Apply the rule to part c

Evaluate the integral of \(-x^{-3} + x - 1\). Integrating each term separately, we have: \[\int -x^{-3} \, dx = -\frac{x^{-2}}{-2} = \frac{x^{-2}}{2},\] \[\int x \, dx = \frac{x^2}{2},\] \[\int -1 \, dx = -x.\] Combine these results to get the antiderivative: \[\frac{x^{-2}}{2} + \frac{x^2}{2} - x + C.\]
05

Verify by differentiation

Differentiate the antiderivatives to verify correctness. Part a: \( -x^{-2} + C' = \frac{2x^{-3}}{-2} = x^{-3} \), matches \(2x^{-3}\). Part b: differentiate \(-\frac{x^{-2}}{4} + \frac{x^3}{3} + C\) and check if it simplifies to the original function, \(\frac{x^{-3}}{2} + x^2\). Part c: differentiate \(\frac{x^{-2}}{2} + \frac{x^2}{2} - x + C\) to confirm it simplifies back to \(-x^{-3} + x - 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration Techniques
Integration is a fundamental concept in calculus, used to find the antiderivative of a function. One of the most common methods for integrating simple algebraic polynomials involves using basic integration techniques, such as the power rule.

In simpler terms, integration can be seen as the reverse process of differentiation. Whereas differentiation talks about rates of change and slopes, integration focuses more on accumulation, such as the area under a curve.

To successfully find the antiderivative, or integral, of a function, you will use various techniques that suit different types of functions. For instance:
  • The power rule is often employed for polynomial functions, where exponents are easily manageable.
  • Specific rules are used for trigonometric and exponential functions.


Understanding these techniques is crucial in solving calculus problems where integration is required.
Power Rule
The power rule for integration is one of the most essential tools for finding antiderivatives of polynomial functions. This rule states that for any function that can be expressed as a power of x, its integral can be found using the formula: \[ \int x^n \, dx = \frac{x^{n+1}}{n+1} + C, \] where \( n eq -1 \).

So, if you're trying to integrate a term like \( 2x^{-3} \), the first thing to do is to identify the exponent and then apply the power rule.

Here's how:
  • Add one to the exponent: \(-3 + 1 = -2.\)
  • Divide by the new exponent: \( \frac{x^{-2}}{-2} \).


Don't forget the constant of integration, \( C \), which accounts for any constant that differentiates down to zero.

This approach simplifies the process of finding antiderivatives, especially when dealing with polynomial expressions in exercises.
Calculus Exercises
Working through calculus exercises is key to mastering integration and the application of the power rule in real-world problems. These exercises are designed to cover a variety of functions and challenge your understanding of various integration techniques.

For example, in the exercise given:
  • Part (a) involves integrating \(2x^{-3} \), which introduces the handling of negative exponents.
  • Part (b) combines different terms: \( \frac{x^{-3}}{2} + x^2 \), demonstrating how to integrate each term separately.
  • Part (c) mixes terms with different properties, \(-x^{-3} + x - 1 \), offering a chance to apply the power rule effectively on each term.


Such exercises often include checking your integrals by differentiating your results to ensure they match the original functions, a practice that strengthens your calculus skills.
Verifying Solutions by Differentiation
After obtaining an antiderivative, it is vital to verify the solution through differentiation. This process ensures that your integration was carried out correctly and the solution matches the initial function.

Differentiating each antiderivative should return you to your original function. Here's how to verify:
  • For Part (a), differentiate \(-x^{-2} + C \) to ensure it yields \(2x^{-3} \).
  • In Part (b), take the derivative of \(-\frac{x^{-2}}{4} + \frac{x^3}{3} + C \) and it should simplify to \( \frac{x^{-3}}{2} + x^2 \).
  • For Part (c), check that differentiating \( \frac{x^{-2}}{2} + \frac{x^2}{2} - x + C \) returns \(-x^{-3} + x - 1 \).


This step not only confirms the accuracy of your antiderivative but also reinforces the close relationship between differentiation and integration in calculus.

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