/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 Find the limits $$ \lim _{x ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the limits $$ \lim _{x \rightarrow 0} \sec \left[\cos x+\pi \tan \left(\frac{\pi}{4 \sec x}\right)-1\right] $$

Short Answer

Expert verified
The limit is -1.

Step by step solution

01

Analyze the expression inside secant

We start by examining the expression: \( \cos x + \pi \tan \left(\frac{\pi}{4 \sec x}\right) - 1 \). As \( x \to 0 \), we know that \( \cos(0) = 1 \). Therefore, the first term becomes 1 when \( x \to 0 \).
02

Simplify the tangent argument

Next, consider the term \( \pi \tan \left( \frac{\pi}{4 \sec x} \right) \). As \( x \to 0 \), \( \sec x = \frac{1}{\cos x} \approx 1 + \frac{x^2}{2} \) and so \( \frac{\pi}{4 \sec x} \approx \frac{\pi}{4} \). Therefore, \( \tan \left( \frac{\pi}{4 \sec x} \right) \approx 1 \) as the angle approaches \( \frac{\pi}{4} \).
03

Calculate the tangent term

Given that \( \tan \left( \frac{\pi}{4 \sec x} \right) \approx 1 \), we have \( \pi \tan \left( \frac{\pi}{4 \sec x} \right) \approx \pi \cdot 1 = \pi \).
04

Evaluate the overall expression inside secant

Now combine all parts: \( \cos x + \pi \tan \left( \frac{\pi}{4 \sec x} \right) - 1 \to 1 + \pi - 1 = \pi \) as \( x \to 0 \).
05

Evaluate the secant of the expression

We need to evaluate \( \sec(\pi) \). Recall that \( \sec(\theta) = \frac{1}{\cos(\theta)} \). Since \( \cos(\pi) = -1 \), we have \( \sec(\pi) = -1 \).
06

Find the limit

Finally, since the inside of the secant approaches \( \pi \) as \( x \to 0 \), the limit becomes \( \sec(\pi) = -1 \). Therefore, \( \lim_{x \to 0} \sec \left[ \cos x + \pi \tan \left( \frac{\pi}{4 \sec x} \right) - 1 \right] = -1 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Limits
Trigonometric limits are a powerful technique in calculus for analyzing how trigonometric functions behave as they approach a specific value. These limits are vital when solving various calculus problems, particularly those involving oscillating functions like sine, cosine, and tangent.

When dealing with trigonometric limits, we often look at how these functions approach their bounds (such as 0 or infinity) and how these changes affect the overall expression. For instance, as seen in the original exercise, evaluating the limit as \( x \to 0 \) requires finding how the trigonometric components simplify and lead to the overall value of the limit.

A common strategy is to use identities or approximations that simplify these trigonometric functions, especially near specific points like zero. Often, approximations such as \( \cos x \approx 1 - \frac{x^2}{2} \) come in handy. Using these provides a straightforward way to evaluate complex trigonometric expressions.
Secant Function
The secant function, denoted as \( \sec(x) \), is the reciprocal of the cosine function: \( \sec(x) = \frac{1}{\cos(x)} \). This function is particularly intriguing due to its asymptotic nature — that is, it shoots off to infinity wherever cosine equals zero.

Understanding the secant function is key to solving limit problems involving secants. The basic idea is that if cosine approaches zero, secant tends towards infinity. Thus, you should always be mindful of these points when evaluating limits.

In the context of the exercise given, the secant function \( \sec(\pi) \) equates to \( \frac{1}{\cos(\pi)} = -1 \) since \( \cos(\pi) = -1 \). Recognizing these trigonometric values helps simplify the process of taking limits.
Tangent Function
The tangent function, represented as \( \tan(x) \), is defined as the ratio of the sine and cosine functions: \( \tan(x) = \frac{\sin(x)}{\cos(x)} \). This function is periodic and has vertical asymptotes at points where cosine is zero.

For limit problems, simplifying tangent expressions often involves understanding these asymptotes and the properties of sine and cosine near certain points. As shown in the original exercise, recognizing \( \tan(\frac{\pi}{4}) = 1 \) helped solve for the expression quickly by approximating near that point.

Approximating the argument of tangent functions to simpler forms like \( \tan(\frac{\pi}{4 \sec(x)}) \approx 1 \) can often strip away complexities to reveal the underlying behavior of the function.
Limit Evaluation Steps
Finding the limit of complex functions involves several key steps that simplify the problem systematically. First, understanding the components of the function within the limit itself is crucial. This involves decomposing and approximating each function component evaluated around the point of interest.

Next, combine these simplified forms to construct the overall approach to the problematic point. Using identities, solving small approximate problems, and keeping within the bounds of trigonometric identities smooth the process.
  • Start by simplifying the inner expressions of functions like tangent or sine and cosine.
  • Use trigonometric identities and approximations for nearing values.
  • Combine the results to determine the overarching trend.
  • Evaluate the limit of the result using foundational trigonometric values.
Taking these steps will help in systematically approaching limit problems and arriving at the correct evaluation, ensuring a successful solution.

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Most popular questions from this chapter

Cardiac output In the late 1860 s, Adolf Fick, a professor of physiology in the Faculty of Medicine in Wurzberg, Germany, developed one of the methods we use today for measuring how much blood your heart pumps in a minute. Your cardiac output as you read this sentence is probably about 7 \(\mathrm{L} / \mathrm{min.}\) . At rest it is likely to be a bit under 6 \(\mathrm{L} / \mathrm{min}\) . If you are a trained marathon runner running a marathon, your cardiac output can be as high as 30 \(\mathrm{L} / \mathrm{min.}\) Your cardiac output can be calculated with the formula $$y=\frac{Q}{D}$$ where \(Q\) is the number of milliliters of \(\mathrm{CO}_{2}\) you exhale in a minute and \(D\) is the difference between the \(\mathrm{CO}_{2}\) concentration \((\mathrm{ml} / \mathrm{L})\) in the blood pumped to the lungs and the \(\mathrm{CO}_{2}\) concentration in the blood returning from the lungs. With \(Q=233 \mathrm{ml} / \mathrm{min}\) and \(D=97-56=41 \mathrm{ml} / \mathrm{L}\) $$y=\frac{233 \mathrm{ml} / \mathrm{min}}{41 \mathrm{ml} / \mathrm{L}} \approx 5.68 \mathrm{L} / \mathrm{min}$$ fairly close to the 6 \(\mathrm{L} / \mathrm{min}\) that most people have at basal (resting) conditions. (Data courtesy of J. Kenneth Herd, M.D. Quillan College of Medicine, East Tennessee State University.) Suppose that when \(Q=233\) and \(D=41,\) we also know that \(D\) is decreasing at the rate of 2 units a minute but that \(Q\) remains unchanged. What is happening to the cardiac output?

Slopes on the graph of the tangent function Graph \(y=\tan x\) and its derivative together on \((-\pi / 2, \pi / 2) .\) Does the graph of the tangent function appear to have a smallest slope? A largest slope? Is the slope ever negative? Give reasons for your answers.

For each of the following functions, solve both \(f^{\prime}(x)=0\) and \(f^{\prime \prime}(x)=0\) for \(x .\) $$f(x)=x(x-4)^{3}$$

Temperatures in Fairbanks, Alaska The graph in the accompanying figure shows the average Fahrenheit temperature in Fairbanks, Alaska, during a typical 365 -day year. The equation that approximates the temperature on day \(x\) is $$y=37 \sin \left[\frac{2 \pi}{365}(x-101)\right]+25$$ and is graphed in the accompanying figure. a. On what day is the temperature increasing the fastest? b. About how many degrees per day is the temperature increasing when it is increasing at its fastest?

Find the derivatives of the functions in Exercises \(19-40\) $$ y=(2 x-5)^{-1}\left(x^{2}-5 x\right)^{6} $$

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