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In Exercises \(41-58\) find \(d y / d t\) $$ y=\sin ^{2}(\pi t-2) $$

Short Answer

Expert verified
\( \frac{dy}{dt} = \pi \sin(2(\pi t - 2)) \)

Step by step solution

01

Identify the Derivative

We need to find the derivative of the function: \[ y = \ sin^{2}(\pi t - 2) \]This function is a composite function, where we have an inner function, \(u = \pi t - 2\), and the outer function is \( \sin^2(u) \). We'll use the chain rule to find the derivative.
02

Differentiate the Outer Function

The outer function is \(v = \sin^2(u)\). Using the chain rule, the derivative with respect to \(u\) is:\[ \frac{d}{du} [\sin^2(u)] = 2\sin(u) \cdot \cos(u) \]This simplifies using the double angle formula to:\[ = \sin(2u) \]
03

Differentiate the Inner Function

Now, differentiate the inner function \(u = \pi t - 2\) with respect to \(t\):\[ \frac{du}{dt} = \pi \]
04

Apply the Chain Rule

Now use the chain rule to find \( \frac{dy}{dt} \), which is the product of the derivative of the outer function and the derivative of the inner function:\[ \frac{dy}{dt} = \frac{d}{du}[\sin^2(u)] \cdot \frac{du}{dt} = \sin(2u) \cdot \pi \]
05

Substitute Back the Inner Function

Substitute \(u = \pi t - 2\) back into our result:\[ \frac{dy}{dt} = \pi sin(2(\pi t - 2)) \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Composite Function
In mathematics, a composite function is created when one function is applied within another. To evaluate composite functions, you process the inner function first and then use the result as the input for the outer function. In our exercise, we deal with a composite function, where the inner function is represented by \( u = \pi t - 2 \), and the outer function is \( y = \sin^2(u) \).
The significance of understanding composite functions lies in their frequent occurrence in calculus problems. They require handling two or more layers of functions, making the use of the chain rule vital for differentiation.
  • Identify each function involved (inner and outer).
  • Calculate the derivatives separately before combining them.
Differentiating complex functions accurately helps in a variety of applications, from physics to engineering, bridging the gap between abstract theory and real-world problems.
Derivative of Trigonometric Functions
Trigonometric functions like \( \sin \), \( \cos \), and \( \tan \) are fundamental in calculus and have unique methods of differentiation. For example, the derivative of \( \sin(u) \) with respect to \( u \) is \( \cos(u) \), while the derivative of \( \cos(u) \) is \(-\sin(u) \). These derivatives form the basis for solving more complex problems, including those involving composite functions.
In the given exercise, we differentiate \( \sin^2(u) \) by first taking the derivative of \( \sin(u) \) and then applying it in conjunction with the chain rule. This results in a new function, \( 2\sin(u)\cos(u) \), which simplifies further using trigonometric identities.
Understanding the nuances of these trigonometric derivatives allows for easier manipulation and simplification of expressions, improving problem-solving ability for intricate calculus problems.
Differentiation Using Double Angle Formula
The double angle formula is a trigonometric identity used to simplify expressions, especially within calculus. For example, \( \sin(2u) = 2\sin(u)\cos(u) \). This formula is particularly useful when differentiating functions that result in products of sine and cosine.
In our exercise, once we arrive at \( 2\sin(u)\cos(u) \) from differentiating \( \sin^2(u) \), the double angle formula enables us to rewrite this as \( \sin(2u) \). This step simplifies further calculations and makes the derivative easier to interpret.
  • Simplifies expressions for ease in computation.
  • Reduces the complexity of trigonometric functions in derivatives.
The application of such formulas is crucial for streamlining solutions, especially in advanced calculus where handling complex expressions becomes routine.

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Most popular questions from this chapter

Find the derivatives of the functions in Exercises \(19-40\) $$ g(x)=\frac{\tan 3 x}{(x+7)^{4}} $$

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