Chapter 3: Problem 19
Find the derivatives of the functions. \begin{equation} g(x)=\frac{x^{2}-4}{x+0.5} \end{equation}
Short Answer
Expert verified
The derivative is \(g'(x) = \frac{x^2 + x + 4}{(x + 0.5)^2}\).
Step by step solution
01
Identify the Functions
Before differentiating, identify the top function (numerator) and the bottom function (denominator). Here, the numerator is \(x^2 - 4\) and the denominator is \(x + 0.5\).
02
Apply the Quotient Rule
To differentiate \(g(x) = \frac{u(x)}{v(x)}\), use the Quotient Rule: \(g'(x) = \frac{u'(x)v(x) - u(x)v'(x)}{(v(x))^2}\). Here, \(u(x) = x^2 - 4\) and \(v(x) = x + 0.5\).
03
Calculate Derivatives of Numerator and Denominator
Find \(u'(x)\) and \(v'(x)\):- \(u'(x) = \frac{d}{dx}(x^2 - 4) = 2x\)- \(v'(x) = \frac{d}{dx}(x + 0.5) = 1\).
04
Substitute into the Quotient Rule
Substitute \(u'(x)\), \(u(x)\), \(v(x)\), and \(v'(x)\) into the Quotient Rule:\[g'(x) = \frac{(2x)(x + 0.5) - (x^2 - 4)(1)}{(x + 0.5)^2}\].
05
Simplify the Numerator
Expand and simplify the numerator:\[(2x)(x + 0.5) - (x^2 - 4) = 2x^2 + x - x^2 + 4 = x^2 + x + 4\].
06
Write the Final Derivative
Substitute the simplified numerator back into the expression:\[g'(x) = \frac{x^2 + x + 4}{(x + 0.5)^2}\].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quotient Rule
When dealing with functions written as fractions, like our function \(g(x) = \frac{x^2 - 4}{x + 0.5}\), the quotient rule is the go-to method for finding the derivative. The quotient rule is used when you have a situation where one function is divided by another. The formula for the quotient rule is straightforward:
- If you have a function \( g(x) = \frac{u(x)}{v(x)} \), then its derivative \( g'(x) \) is given by:
- \( u'(x) \) is the derivative of the numerator
- \( v'(x) \) is the derivative of the denominator
- The denominator of the derivative is always the square of the original denominator \( (v(x))^2 \)
Differentiation
Differentiation is a key concept in calculus that focuses on determining the rate at which something changes. When you have a mathematical function, you use differentiation to find its derivative, which tells you how the function value changes as its input changes. In our exercise, the function \( g(x) = \frac{x^2 - 4}{x + 0.5} \) requires us to differentiate both the numerator \( x^2 - 4 \) and the denominator \( x + 0.5 \) separately. Here's a quick way to find derivatives:
- The derivative of \( x^n \) is \( nx^{n-1} \), meaning for \( x^2 \), the derivative is \( 2x \).
- Constants vanish when differentiating, so the derivative of \(-4\) is \( 0 \).
- For linear expressions like \( x + 0.5 \), since the rate of change is constant, the derivative is \( 1 \).
Calculus
Calculus is a broad and crucial branch of mathematics, playing a vital role in understanding the world through math. It is primarily divided into two fields:
- Differential Calculus: Concerned with the concept of differentiation, which helps find derivatives. It examines how functions change and what the slope of a curve represents at any given point.
- Integral Calculus: Focuses on integrals and accumulation. It's all about summing things up and finding areas under curves.