Chapter 3: Problem 17
Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there. \(f(x)=\sqrt{x}, \quad(4,2)\)
Short Answer
Expert verified
The slope is \(\frac{1}{4}\). The tangent line is \(y = \frac{1}{4}x + 1\).
Step by step solution
01
Find the Derivative
The slope of the function at a given point is given by the derivative of the function. For the function \(f(x) = \sqrt{x}\), we can rewrite it as \(f(x) = x^{1/2}\). Using the power rule for differentiation, the derivative \(f'(x)\) is \(\frac{1}{2}x^{-1/2} = \frac{1}{2\sqrt{x}}\).
02
Evaluate the Derivative at the Given Point
Substitute \(x = 4\) into the derivative \(f'(x) = \frac{1}{2\sqrt{x}}\) to find the slope at the point \((4, 2)\). This gives us \(f'(4) = \frac{1}{2\sqrt{4}} = \frac{1}{4}\). Thus, the slope of the tangent line at \(x = 4\) is \(\frac{1}{4}\).
03
Use Point-Slope Form to Write the Tangent Line Equation
The equation for a line with slope \(m\) passing through a point \((x_1, y_1)\) is given by the point-slope form \(y - y_1 = m(x - x_1)\). Substituting \(m = \frac{1}{4}\), \(x_1 = 4\), and \(y_1 = 2\) into this equation, we have: \(y - 2 = \frac{1}{4}(x - 4)\).
04
Simplify the Tangent Line Equation
Solve the equation \(y - 2 = \frac{1}{4}(x - 4)\) for \(y\) to express it in slope-intercept form. Distribute \(\frac{1}{4}\) to get \(y - 2 = \frac{1}{4}x - 1\). Add 2 to both sides: \(y = \frac{1}{4}x + 1\). This is the equation of the tangent line at \((4, 2)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Tangent Line
A tangent line is a straight line that touches a curve at just one point, without crossing it at that point. This line represents the immediate direction the curve is heading and provides a linear approximation of the curve at that point. Think of it like balancing a pencil upright against your finger; if you aren't pushing, just touching gently, that pencil is tangential to your finger.
- It's an important concept in calculus because it gives insight into the instantaneous rate of change of a function.
- The tangent line has the same slope as the curve at the point of tangency.
Power Rule
The Power Rule is a fundamental tool in calculus for taking derivatives of polynomial functions. It's like a shortcut that makes finding derivatives much simpler and quicker. The rule states that for any function of the form \(f(x) = x^n\), its derivative is \(f'(x) = nx^{n-1}\).
- This is especially helpful for functions that are written as powers of \(x\), such as when converting square root functions into exponent form.
- In our exercise, the derivative \( \sqrt{x}\) becomes \( x^{1/2}\), allowing us to apply the Power Rule and find the derivative seamlessly.
Slope of a Function
The slope of a function at a particular point, often used interchangeably with the term "derivative," measures how steep or flat the curve is at that specific location. It's like the angle of a road you're driving on: steep indicates a rapid increase or decrease, while a flatter slope suggests a more gradual change.
- To determine this slope, we calculate the derivative of the function, which gives us a general formula for the slope at any point along the curve.
- In the example provided, \(f'(x) = \frac{1}{2\sqrt{x}}\) describes the slope of \(f(x) = \sqrt{x}\) at any \(x\).
Derivative Evaluation
Evaluating the derivative at a specific point gives us a concrete value representing the slope of the tangent line at that point. This is a critical step in writing the equation for the tangent line. Essentially, it's like planting a flag at that point on the curve; the slope of the flagpole indicates the curve's direction.
- We compute this by substituting the \(x\)-value of our point of interest into the derivative formula.
- For instance, by inputting \(x = 4\) into \(f'(x) = \frac{1}{2\sqrt{x}}\), we deduce that the slope is \(\frac{1}{4}\).