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Differentiate the functions and find the slope of the tangent line at the given value of the independent variable. $$ y=\frac{x+3}{1-x}, \quad x=-2 $$

Short Answer

Expert verified
The slope of the tangent line at \( x = -2 \) is \( \frac{4}{9} \).

Step by step solution

01

Simplify the Function

First, let's express the function in a way that's easier to differentiate. We have:\[ y = \frac{x+3}{1-x}. \]This form is already simplified and suitable for applying the derivative.
02

Compute the Derivative

To find the derivative of \( y \) with respect to \( x \), we use the quotient rule, which states \( \left(\frac{u}{v}\right)' = \frac{u'v - uv'}{v^2} \), where \( u = x+3 \) and \( v = 1-x \).Find \( u' \) and \( v' \):\[ u' = \frac{d}{dx}(x+3) = 1, \]\[ v' = \frac{d}{dx}(1-x) = -1. \]Now apply the quotient rule:\[ y' = \frac{(1)(1-x) - (x+3)(-1)}{(1-x)^2} = \frac{1-x + x + 3}{(1-x)^2}. \]This simplifies to:\[ y' = \frac{4}{(1-x)^2}. \]
03

Substitute the Given x-value

Now we substitute \( x = -2 \) into the derivative to find the slope of the tangent line:\[ y'(-2) = \frac{4}{(1 - (-2))^2} = \frac{4}{(1 + 2)^2} = \frac{4}{9}. \]
04

Conclusion on Tangent Slope

After computing the derivative and substituting \( x = -2 \), we find that the slope of the tangent line to the curve at \( x = -2 \) is \( \frac{4}{9} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient Rule
In calculus, the quotient rule is a method for finding the derivative of a quotient of two functions. When we have a function expressed as a fraction, such as \( y = \frac{u}{v} \), where both \( u \) and \( v \) are functions of \( x \), the quotient rule provides a systematic way to find its derivative. Given by:\[\left(\frac{u}{v}\right)' = \frac{u'v - uv'}{v^2}\]**Steps to Apply the Quotient Rule:**
  • Identify the numerator function \( u \) and the denominator function \( v \).
  • Calculate the derivative of \( u \), denoted as \( u' \).
  • Calculate the derivative of \( v \), denoted as \( v' \).
  • Substitute these values into the quotient rule formula.
  • Simplify the expression to get the final derivative.
In the given exercise, \( u = x+3 \) and \( v = 1-x \). We find \( u' = 1 \) and \( v' = -1 \) and then apply the quotient rule to arrive at the derivative:\[y' = \frac{4}{(1-x)^2}\] This process highlights how the quotient rule breaks down complex derivatives into manageable steps.
Tangent Line
The tangent line is a straight line that touches a curve at a single point without crossing it at that point. This line represents the "instantaneous rate of change" of the function at a given point, which is the same as the derivative's value at that point. **Understanding Tangent Lines:**
  • At any given point \( x \) on the curve, the slope of the tangent line is equal to the derivative of the function at that point, \( y'(x) \).
  • The equation of the tangent line can be derived using the slope-point form: \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \( (x_1, y_1) \) is the point of tangency.
In the exercise, after finding the derivative \( y' = \frac{4}{(1-x)^2} \), substituting \( x = -2 \) gives us the slope of the tangent line:\[y'(-2) = \frac{4}{9}\]This implies that at \( x = -2 \), the curve is rising at a rate of \( \frac{4}{9} \), providing insight into how steep or gentle the curve is at that point.
Derivative Calculation
Calculating derivatives is a fundamental skill in calculus. It lets us understand how a function is changing at any specific point. The derivative of a function gives the slope of the tangent line to the graph of the function at that point.**Steps for Derivative Calculation:**
  • Identify the function you are working with. It might already be in a simplifiable form, or you might need to rewrite it using algebraic manipulations.
  • Apply the appropriate rules, such as product, sum, or quotient rules, to find the derivative.
  • Simplify the derivative expression to make further calculations easier.
  • Substitute any given values into the derivative to find specific information like slopes or rates of change.
For the function \( y = \frac{x+3}{1-x} \), we recognize it as a quotient, suggesting direct application of the quotient rule. After simplifying, the derivative calculated is \( y' = \frac{4}{(1-x)^2} \). When substituting \( x = -2 \), the derivative helps us determine the rate at which the function is changing at that precise point, resulting in a slope of \( \frac{4}{9} \) for the tangent line.

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