Chapter 2: Problem 26
At what points are the functions continuous? $$ y=\sqrt[4]{3 x-1} $$
Short Answer
Expert verified
The function is continuous for \( x \geq \frac{1}{3} \).
Step by step solution
01
Identify the Conditions for Continuity
A function is continuous at a point if it does not have breaks, holes, or jumps at that point. For the function \( y = \sqrt[4]{3x - 1} \), we need the expression inside the fourth root, \(3x - 1\), to be non-negative for \( y \) to be real and defined. This is because the fourth root of a negative number is not a real number.
02
Set the inequality
Since the expression inside the fourth root must be non-negative, we set up the inequality: \[ 3x - 1 \geq 0 \] This will determine the values of \( x \) for which the function is defined and potentially continuous.
03
Solve the inequality
Solve the inequality \[ 3x - 1 \geq 0 \]Add 1 to both sides:\[ 3x \geq 1 \]Now, divide both sides by 3:\[ x \geq \frac{1}{3} \]
04
Determine the interval of continuity
The function is continuous on the interval \( [\frac{1}{3}, \, \infty) \). This means the function has values whereby it remains continuous starting from \( x = \frac{1}{3} \) and continues to positive infinity. There are no values within this range at which the function is discontinuous.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Fourth Root Function
The fourth root function is a mathematical operation represented by the radical expression \( y = \sqrt[4]{3x - 1} \). In this function, "fourth root" refers to finding a number which, when multiplied by itself three more times, results in the original number inside the root symbol. For example, the fourth root of 16 is 2, because \( 2^4 = 16 \). The function \( \sqrt[4]{3x - 1} \) specifically deals with the value inside the fourth root, \( 3x - 1 \), determining whether it can yield a real number.
- The base function \( y = \sqrt[n]{x} \) is continuous where its radicand \( x \) is non-negative if \( n \) is even.
- The fourth root extends the concept of square roots by involving higher exponents, specifically four in this context.
Non-negative Inequality
Understanding non-negative inequalities is essential for determining areas of continuity in functions involving roots or radicals. In the given problem, the expression inside the fourth root must satisfy a non-negative inequality: \( 3x - 1 \geq 0 \). This inequality ensures that the expression inside does not become negative, which would result in an undefined or non-real result.
- Non-negative inequalities form when we want the values of an expression to remain zero or positive.
- Solutions to such inequalities indicate where the function is real and potentially continuous.
Interval of Continuity
Intervals of continuity provide a range of \( x \)-values where a function is continuous, meaning there are no jumps, breaks, or holes. For the function \( y = \sqrt[4]{3x - 1} \), the interval of continuity is determined to be \( [\frac{1}{3}, \, \infty) \).
- The lower bound, \( \frac{1}{3} \), comes from solving the inequality \( 3x - 1 \geq 0 \) and making sure the expression inside the root is valid and non-negative.
- From this point onward to positive infinity, the function remains continuous as all included \( x \)-values ensure a non-negative expression inside the root.
Solving Inequalities
Solving inequalities is a necessary skill to define regions where a function behaves appropriately under given conditions, such as continuity or real number outputs. The inequality \( 3x - 1 \geq 0 \) needs to be solved to determine the domain where the fourth root function is defined.The process involves simple algebraic manipulations:
- First, add 1 to both sides to isolate the term involving \( x \): \( 3x \geq 1 \).
- Then, divide both sides by 3 to solve for \( x \): \( x \geq \frac{1}{3} \).