/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Find the limits. \begin{equati... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the limits. \begin{equation}\quad \text { a. }\lim _{x \rightarrow 1^{+}} \frac{\sqrt{2 x}(x-1)}{|x-1|} \quad \text { b. } \lim _{x \rightarrow 1^{-}} \frac{\sqrt{2 x}(x-1)}{|x-1|}\end{equation}

Short Answer

Expert verified
a. \( \sqrt{2} \); b. \( -\sqrt{2} \).

Step by step solution

01

Understand the Problem

We need to find the one-sided limits of the function \( \frac{\sqrt{2x}(x-1)}{|x-1|} \) as \( x \) approaches 1 from the right (\(1^+\)) and from the left (\(1^-\)). This involves analyzing the behavior of the function for values of \( x \) slightly greater than 1 and slightly less than 1, respectively.
02

Analyze When \( x \to 1^+ \)

For \( x \to 1^+ \), \( |x-1| = x-1 \) because the expression inside the absolute value is positive for \( x > 1 \). Thus, the function simplifies to \( \frac{\sqrt{2x}(x-1)}{x-1} = \sqrt{2x} \). As \( x \to 1^+ \), \( \sqrt{2x} \to \sqrt{2 \times 1} = \sqrt{2} \). Therefore, \( \lim_{x \to 1^+} \frac{\sqrt{2x}(x-1)}{|x-1|} = \sqrt{2} \).
03

Analyze When \( x \to 1^- \)

For \( x \to 1^- \), \( |x-1| = -(x-1) \) because the expression inside the absolute value is negative for \( x < 1 \). Thus, the function simplifies to \( \frac{\sqrt{2x}(x-1)}{-(x-1)} = -\sqrt{2x} \). As \( x \to 1^- \), \( -\sqrt{2x} \to -\sqrt{2 \times 1} = -\sqrt{2} \). Therefore, \( \lim_{x \to 1^-} \frac{\sqrt{2x}(x-1)}{|x-1|} = -\sqrt{2} \).
04

Conclusion

The limit when approaching from the right (\( x \to 1^+ \)) is \( \sqrt{2} \) and the limit when approaching from the left (\( x \to 1^- \)) is \( -\sqrt{2} \). Since these are not equal, the two-sided limit at \( x = 1 \) does not exist.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

One-sided limits
When we talk about one-sided limits, we're focusing on understanding how a function behaves as it approaches a particular point from one side only. Essentially, we look at two kinds of one-sided limits: the right-hand limit and the left-hand limit.
  • The right-hand limit (\( ext{lim}_{x o a^+} f(x) \)) examines the function values as they get closer to a specific point of interest, \( a \), from values greater than \( a \).
  • The left-hand limit (\( ext{lim}_{x o a^-} f(x) \)) looks at the function values approaching \( a \) from values less than \( a \).
In our exercise, it was crucial to evaluate both these limits as \( x \) approaches 1 to understand the behavior of the given expression. For example, as \( x \) approaches 1 from the right, we handled the function differently than when \( x \) approached 1 from the left. This difference is key to determining the overall behavior and nature of the limit at a point.
Absolute value
The absolute value function is a fundamental concept that measures the distance of a number from zero on the number line. It ensures non-negative results regardless of whether the input is positive or negative.
In mathematical terms, the absolute value of a number \( x \) is denoted as \( |x| \). It is defined as follows:
  • If \( x \geq 0 \), then \( |x| = x \).
  • If \( x < 0 \), then \( |x| = -x \).
In our exercise, we saw how the expression inside the absolute value, \( |x-1| \), behaved differently depending on whether \( x \) was greater or less than 1. For \( x \) approaching 1 from the right (\( x > 1 \)), \( |x-1| \) was simply \( x-1 \). In contrast, for \( x \) approaching 1 from the left (\( x < 1 \)), we had \( |x-1| = -(x-1) \). This intricacy played a crucial role in how the expression was simplified for each one-sided limit.
Square root function
The square root function is a mathematical operation that returns the number which, when multiplied by itself, results in the given number. Symbolized as \( \sqrt{x} \), it always returns the non-negative root of a real number, with a few specific properties:
  • The function is only defined for non-negative inputs (\( x \geq 0 \)).
  • For each non-negative number, there is exactly one square root.
In the context of our exercise, the function \( \sqrt{2x} \) was pivotal. As \( x \) approached 1, \( \sqrt{2x} \) approached \( \sqrt{2} \). The function's smooth and continuous nature provided straightforward calculations for the limit problems. It demonstrated how square roots can simplify mathematical expressions when evaluated within their domain.
Two-sided limit
A two-sided limit explores the behavior of a function as the input approaches a particular point from both directions. It's about how the function's "output" behaves as \( x \) approaches \( a \) from both the left (\( x o a^- \)) and the right (\( x o a^+ \)). For a two-sided limit to exist at a point \( a \), the left-hand limit and the right-hand limit must both exist and must be equal:
  • If \( ext{lim}_{x o a^-} f(x) = ext{lim}_{x o a^+} f(x) = L \), then \( ext{lim}_{x o a} f(x) = L \).
In our example, the limits from both sides, approaching 1, were not equal. On one side, we found \( ext{lim}_{x o 1^+} f(x) = \sqrt{2} \), while on the other side, \( ext{lim}_{x o 1^-} f(x) = -\sqrt{2} \). This disparity means that the two-sided limit does not exist at \( x = 1 \). Hence, understanding both one-sided and two-sided limits gives a complete picture of how the function behaves around the point of interest.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.