/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 In Exercises 9-20, use the Diver... [FREE SOLUTION] | 91Ó°ÊÓ

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In Exercises 9-20, use the Divergence Theorem to find the outward flux of \(\mathbf{F}\) across the boundary of the region \(D .\) Sphere \(\quad \mathbf{F}=x^{3} \mathbf{i}+y^{3} \mathbf{j}+z^{3} \mathbf{k}\) \(D :\) The solid sphere \(x^{2}+y^{2}+z^{2} \leq a^{2}\)

Short Answer

Expert verified
The divergence of \( \mathbf{F} \) is \( 3(x^2+y^2+z^2) \).

Step by step solution

01

Understanding the Divergence Theorem

The Divergence Theorem states \( \iint_{\partial D} \mathbf{F} \cdot \mathbf{n} \, dS = \iiint_{D} abla \cdot \mathbf{F} \, dV \), where \( \mathbf{F} \) is a vector field, \( \partial D \) is the boundary of the region \( D \), and \( abla \cdot \mathbf{F} \) is the divergence of \( \mathbf{F} \). This theorem allows us to convert a surface integral into a volume integral.
02

Find the Divergence of \( \mathbf{F} \)

Given \( \mathbf{F} = x^{3} \mathbf{i} + y^{3} \mathbf{j} + z^{3} \mathbf{k} \), we find the divergence: \( abla \cdot \mathbf{F} = \frac{\partial}{\partial x}(x^{3}) + \frac{\partial}{\partial y}(y^{3}) + \frac{\partial}{\partial z}(z^{3}) = 3x^{2} + 3y^{2} + 3z^{2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Flux Calculation
Flux is a fundamental concept in vector calculus used to compute the flow of a vector field across a surface. Consider a vector field \( \mathbf{F} \), which represents the flow within a space. The flux of \( \mathbf{F} \) through a surface is essentially the amount of \( \mathbf{F} \) passing through that surface along a particular direction. In this sphere exercise, the task is to determine the outward flux of \( \mathbf{F} \) across the boundary of the region \( D \). By leveraging the Divergence Theorem, the problem simplifies from a complex surface integral to a more manageable volume integral. This shift to volume significantly eases the calculation process in this context. It requires finding the divergence of \( \mathbf{F} \) to integrate over the sphere's volume.
Surface Integral
A surface integral extends the concept of a line integral to higher dimensions. It is used to calculate the total field passing through a 3D surface. For our sphere example, a surface integral of vector field \( \mathbf{F} \) would consider the entirety of the sphere's surface \( \partial D \).The surface integral \( \iint_{\partial D} \mathbf{F} \cdot \mathbf{n} \, dS \) involves integrating the dot product of \( \mathbf{F} \) and the unit normal vector \( \mathbf{n} \) across the boundary surface. This calculation directly measures the flow of \( \mathbf{F} \) through \( \partial D \). However, instead of performing this direct computation, the Divergence Theorem allows an alternative approach by converting the surface integral into an equivalent, and often simpler, volume integral.
Volume Integral
Volume integrals extend integrals into three-dimensional space, helping to evaluate a quantity over a volume in space. The Divergence Theorem assists in transforming a surface integral into this volume integral \( \iiint_{D} abla \cdot \mathbf{F} \, dV \). Here, you integrate the divergence of \( \mathbf{F} \) over the region \( D \) enclosed by the sphere.In our exercise, you've already derived the divergence of \( \mathbf{F} \) as \( 3x^2 + 3y^2 + 3z^2 \). This expression is further integrated over the sphere defined by \( x^2 + y^2 + z^2 \leq a^2 \), greatly simplifying the task of computing the flux through the surface by focusing instead on the volume.
Vector Field Divergence
Divergence is a measure of how much a vector field spreads out from a given point, and it is represented as \( abla \cdot \mathbf{F} \). For any vector field \( \mathbf{F} \), calculating the divergence involves taking partial derivatives of its components with respect to their respective variables and summing the results.In this problem, \( \mathbf{F} = x^3 \mathbf{i} + y^3 \mathbf{j} + z^3 \mathbf{k} \). The divergence is found as follows:
  • Partial derivative of \( x^3 \) with respect to \( x \) gives \( 3x^2 \).
  • Partial derivative of \( y^3 \) with respect to \( y \) gives \( 3y^2 \).
  • Partial derivative of \( z^3 \) with respect to \( z \) gives \( 3z^2 \).
Thus, \( abla \cdot \mathbf{F} = 3x^2 + 3y^2 + 3z^2 \). Understanding divergence is crucial because it serves as the bridge between surface and volume integrals in the context of the Divergence Theorem, streamlining flux calculations across complex surfaces.

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Most popular questions from this chapter

Let \(\mathbf{F}=(y \cos 2 x) \mathbf{i}+\left(y^{2} \sin 2 x\right) \mathbf{j}+\left(x^{2} y+z\right) \mathbf{k} .\) Is there a vector field \(\mathbf{A}\) such that \(\mathbf{F}=\nabla \times \mathbf{A} ?\) Explain your answer.

The tangent plane at a point \(P_{0}\left(f\left(u_{0}, v_{0}\right), g\left(u_{0}, v_{0}\right), h\left(u_{0}, v_{0}\right)\right)\) on a parametrized surface \(\mathbf{r}(u, v)=f(u, v) \mathbf{i}+g(u, v) \mathbf{j}+h(u, v) \mathbf{k}\) is the plane through \(P_{0}\) normal to the vector \(\mathbf{r}_{u}\left(u_{0}, v_{0}\right) \times \mathbf{r}_{v}\left(u_{0}, v_{0}\right),\) the cross product of the tangent vectors \(\mathbf{r}_{u}\left(u_{0}, v_{0}\right)\) and \(\mathbf{r}_{v}\left(u_{0}, v_{0}\right)\) at \(P_{0} .\) In Exercises \(27-30,\) find an equation for the plane tangent to the surface at \(P_{0} .\) Then find a Cartesian equation for the surface and sketch the surface and tangent plane together. $$ \begin{array}{l}{\text { Circular cylinder } \text { The circular cylinder } \mathbf{r}(\theta, z)=(3 \sin 2 \theta) \mathbf{i}+} \\ {\left(6 \sin ^{2} \theta\right) \mathbf{j}+z \mathbf{k}, 0 \leq \theta \leq \pi, \text { at the point } P_{0}(3 \sqrt{3} / 2,9 / 2,0)} \\ {\text { corresponding to }(\theta, z)=(\pi / 3,0) \text { (See Example } 3 . )}\end{array} $$

Outward flux of a gradient field Let \(S\) be the surface of the portion of the solid sphere \(x^{2}+y^{2}+z^{2} \leq a^{2}\) that lies in the first octant and let \(f(x, y, z)=\ln \sqrt{x^{2}+y^{2}}+z^{2}\) . Calculate $$\iint_{S} \nabla f \cdot \mathbf{n} d \sigma$$ \((\nabla f \cdot \mathbf{n}\) is the derivative of \(f\) in the direction of outward normal \(\mathbf{n} .)\)

Hyperboloid of two sheets Find a parametrization of the hyperboloid of two sheets \(\left(z^{2} / c^{2}\right)-\left(x^{2} / a^{2}\right)-\left(y^{2} / b^{2}\right)=1\)

Work along different paths Find the work done by \(\mathbf{F}=\) \(e^{y z} \mathbf{i}+\left(x z e^{y z}+z \cos y\right) \mathbf{j}+\left(x y e^{y z}+\sin y\right) \mathbf{k}\) over the following paths from \((1,0,1)\) to \((1, \pi / 2,0)\). \begin{equation}\text { a. The line segment }x=1, y=\pi t / 2, z=1-t, 0 \leq t \leq 1\end{equation} \begin{equation}\begin{array}{l}{\text { b. The line segment from }(1,0,1) \text { to the origin followed by the }} \\ {\text { line segment from the origin to }(1, \pi / 2,0)}\\\\{\text { c. The line segment from }(1,0,1) \text { to }(1,0,0), \text { followed by the }} \\ {x \text { -axis from }(1,0,0) \text { to the origin, followed by the parabola }} \\ {y=\pi x^{2} / 2, z=0 \text { from there to }(1, \pi / 2,0)}\end{array}\end{equation}

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