Chapter 16: Problem 1
Find the \(\mathbf{k}\) -component of \(\operatorname{curl}(\mathbf{F})\) for the following vector fields on the plane. \(\mathbf{F}=(x+y) \mathbf{i}+(2 x y) \mathbf{j}\)
Short Answer
Expert verified
The \( k \)-component of the curl is \( 2y - 1 \).
Step by step solution
01
Identify the Vector Field Components
The given vector field is \( \mathbf{F} = (x+y) \mathbf{i} + (2xy) \mathbf{j} \). In component form, this can be expressed as \( \mathbf{F} = (P, Q) \), where \( P = x+y \) and \( Q = 2xy \).
02
Recall the Formula for Curl in 2D
In two dimensions, the curl of a vector field \( \mathbf{F} = (P, Q) \) is given by \( \operatorname{curl}(\mathbf{F}) = (Q_x - P_y) \mathbf{k} \), where \( Q_x \) is the partial derivative of \( Q \) with respect to \( x \) and \( P_y \) is the partial derivative of \( P \) with respect to \( y \).
03
Calculate Partial Derivatives \(Q_x\) and \(P_y\)
Compute the partial derivative \( Q_x \):\[ Q = 2xy \Rightarrow Q_x = \frac{\partial}{\partial x} (2xy) = 2y. \]Compute the partial derivative \( P_y \):\[ P = x+y \Rightarrow P_y = \frac{\partial}{\partial y} (x+y) = 1. \]
04
Compute the \( k \)-component of Curl
Substitute the partial derivatives into the curl formula:\[ \operatorname{curl}(\mathbf{F}) = (Q_x - P_y) \mathbf{k} = (2y - 1) \mathbf{k}. \]
05
Final Expression for the \( k \)-component
The \( k \)-component of \( \operatorname{curl}(\mathbf{F}) \) is \( 2y - 1 \). There is no need for additional components since it's a 2D vector field on the plane.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Field
In the world of calculus, a vector field is a function that assigns a vector to every point in space. Imagine it as a collection of arrows spread throughout a plane or space, where each arrow has both a direction and a magnitude.
For instance, the vector field mentioned in the original exercise is given by \( \mathbf{F} = (x+y) \mathbf{i} + (2xy) \mathbf{j} \). This means at any point \((x, y)\), this field assigns a vector with:
For instance, the vector field mentioned in the original exercise is given by \( \mathbf{F} = (x+y) \mathbf{i} + (2xy) \mathbf{j} \). This means at any point \((x, y)\), this field assigns a vector with:
- a component \((x+y)\) in the \(\mathbf{i}\) direction, which typically represents the x-axis,
- and a component \((2xy)\) in the \(\mathbf{j}\) direction, representing the y-axis.
Partial Derivative
A partial derivative is a derivative where we hold some variables constant while we differentiate with respect to one variable. This allows us to understand how a function changes as only one of its input changes.
In the exercise, we had to calculate two partial derivatives:
In the exercise, we had to calculate two partial derivatives:
- \(Q_x = \frac{\partial}{\partial x} (2xy) = 2y\)
- \(P_y = \frac{\partial}{\partial y} (x+y) = 1\)
2D Curl
The concept of 2D curl is used to measure the tendency of a vector field to rotate around a point in two-dimensional space. It's represented as a single scalar since in 2D there is essentially only one direction that rotation can occur (out of the plane).
In mathematics, specifically in the exercise, the 2D curl of a vector field \( \mathbf{F} = (P, Q) \) is defined as:
This formula provides us the \(k\)-component of the curl, which can indicate the swirling strength of the field.
In mathematics, specifically in the exercise, the 2D curl of a vector field \( \mathbf{F} = (P, Q) \) is defined as:
- \(\operatorname{curl}(\mathbf{F}) = (Q_x - P_y) \mathbf{k}\)
This formula provides us the \(k\)-component of the curl, which can indicate the swirling strength of the field.
k-component
In the realm of vector calculus, especially when dealing with a 2D vector field on a plane, the \(k\)-component is crucial. Although we're operating in two dimensions, we're interested in knowing about rotation which "pokes out" in the third dimension, usually represented as the \(k\)-component.
The \(k\)-component of the curl is essentially the only relevant component for 2D fields because it gives the measure of rotation in a plane perpendicular to the x-y plane. In our original exercise, the formula for the 2D curl yielded the \( k \)-component:\[ \operatorname{curl}(\mathbf{F}) = (2y - 1) \mathbf{k} \]
Thus, the expression \((2y - 1)\) represents the intensity of the rotation about a point for this specific vector field. Understanding this component helps in visualizing how much the field "twirls" at each point in the plane.
The \(k\)-component of the curl is essentially the only relevant component for 2D fields because it gives the measure of rotation in a plane perpendicular to the x-y plane. In our original exercise, the formula for the 2D curl yielded the \( k \)-component:\[ \operatorname{curl}(\mathbf{F}) = (2y - 1) \mathbf{k} \]
Thus, the expression \((2y - 1)\) represents the intensity of the rotation about a point for this specific vector field. Understanding this component helps in visualizing how much the field "twirls" at each point in the plane.