Chapter 15: Problem 9
Let \(R\) be the region in the first quadrant of the \(x y\) -plane bounded by the hyperbolas \(x y=1, x y=9\) and the lines \(y=x, y=4 x\) . Use the transformation \(x=u / v, y=u v\) with \(u>0\) and \(v>0\) to rewrite $$\iint_{R}\left(\sqrt{\frac{y}{x}}+\sqrt{x y}\right) d x d y$$ as an integral over an appropriate region \(G\) in the \(u v\) -plane. Then evaluate the \(u v\) -integral over \(G .\)
Short Answer
Step by step solution
Identify the region R
Apply the transformation
Change of variables in the integral
Calculate the Jacobian
Write the integral over G
Evaluate the integral
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Jacobian Transformation
- \( \frac{\partial x}{\partial u} \) and \( \frac{\partial x}{\partial v} \) for the variable \(x\).
- \( \frac{\partial y}{\partial u} \) and \( \frac{\partial y}{\partial v} \) for the variable \(y\).
Change of Variables
- Replacing \(x = \frac{u}{v}\) and \(y = uv\) effectively transforms challenging expressions into simpler ones like \(v\) and \(u\), respectively.
- The rectangular region \(R\) defined with hyperbolas and lines can be more easily described in the new variables as region \(G\), simplifying the nature of integration bounds.
Coordinate Transformation
- The line \(xy = 1\) becomes \(u^2 = 1\), reducing to \(u = 1\).
- The line \(xy = 9\) becomes \(u^2 = 9\), simplifying to \(u = 3\).
- The line \(y = x\) translates to \(v = 1\).
- The line \(y = 4x\) transforms into \(v = 4\).