Chapter 15: Problem 12
The area of an ellipse the area \(\pi a b\) of the ellipse \(x^{2} / a^{2}+y^{2} / b^{2}=1\) can be found by integrating the function \(f(x, y)=1\) over the region bounded by the ellipse in the \(x y\) -plane. Evaluating the integral directly requires a trigonometric substitution. An easier way to evaluate the integral is to use the transformation \(x=a u, y=b v\) and evaluate the transformed integral over the disk \(G : u^{2}+v^{2} \leq 1\) in the \(u v\) -plane. Find the area this way.
Short Answer
Step by step solution
Understanding the Problem
Perform Coordinate Transformation
Calculate the Jacobian of Transformation
Convert and Evaluate the Integral
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coordinate Transformation
By using the transformations \( x = au \) and \( y = bv \), we simplify the equation into \( u^{2} + v^{2} \leq 1 \), which is the equation of a circle with radius 1.
- This makes our region a unit circle in the \( uv \)-plane.
- Transforming coordinates helps change complex shapes (like ellipses) into simpler ones (like circles), making integral calculations easier.
Jacobian Determinant
- \( x = au \), resulting in \( \frac{\partial x}{\partial u} = a \)
- \( y = bv \), resulting in \( \frac{\partial y}{\partial v} = b \).
Integral Evaluation
- The expression \( 1 \cdot ab \) indicates the area element is scaled by the Jacobian determinant \( ab \).
- \( dudv \) represents tiny elements of area within the \( uv \)-disk.
Trigonometric Substitution
- While trigonometric substitutions are essential in integration techniques, by transforming to the \( uv \)-plane, we manage the integral more directly.
- This approach prevents unnecessary complexities that these substitutions usually handle.