Chapter 14: Problem 51
Estimating maximum error Suppose that \(T\) is to be found from the formula \(T=x\left(e^{y}+e^{-y}\right),\) where \(x\) and \(y\) are found to be 2 and ln 2 with maximum possible errors of \(|d x|=0.1\) and \(|d y|=\) \(0.02 .\) Estimate the maximum possible error in the computed value of \(T .\)
Short Answer
Step by step solution
Identify Given Values
Differentiate the Formula for T
Express the Differential dT
Substitute Given Values into dT
Calculate the Maximum Error
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Partial Derivatives
This means when calculating \(\frac{\partial T}{\partial x}\), we treat \(y\) as a constant, which gives us \(e^y + e^{-y}\).
Similarly, for \(\frac{\partial T}{\partial y}\), \(x\) is treated as a constant, giving us \(x(e^y - e^{-y})\).
Partial derivatives are crucial because they give us the rate of change or the slope of the function in the direction of each variable. Thus, they form the backbone for identifying how small changes in \(x\) and \(y\) can propagate to change \(T\).
Differentials
For our function \(T\), the differential \(dT\) can be expressed using its partial derivatives and the differentials of \(x\) and \(y\): \[ dT = \frac{\partial T}{\partial x} \cdot dx + \frac{\partial T}{\partial y} \cdot dy \]
This formula allows us to estimate the tiny changes in \(T\) by combining the effects of changes in \(x\) and \(y\).
Given the computed partial derivatives, we substituted these along with the maximum errors \(|dx| = 0.1\) and \(|dy| = 0.02\) into our differential formula to estimate how errors in \(x\) and \(y\) might combine to affect the error in \(T\).
Using differentials is a powerful method to approximate the effect of input variations, capturing the potential extent and direction of errors in calculations.
Error Propagation
When we measure \(x\) and \(y\), each has a known maximum possible error. By applying the rules of differentiation as seen in differentials, we propagate these errors through the formula to estimate their combined effect on \(T\).
In our analysis, the equation for \(dT\), \[ dT = (e^y + e^{-y}) \cdot dx + x(e^y - e^{-y}) \cdot dy \]
demonstrates this propagation. Errors \(|dx|\) and \(|dy|\) influence \(T\) as scaled by the partial derivatives.
This technique helps in predicting the potential variability in computed outcomes, preparing us to address or adjust for these possible discrepancies during data analysis or experiment evaluation.
Maximum Possible Error
For the function \(T = x(e^y + e^{-y})\), after determining our partial derivatives and calculating \(dT\), we substitute our given maximum errors in \(x\) and \(y\) into the differential expression.
The calculations show:
- \(dT = (2+\frac{1}{2}) \times 0.1 + 2 \times (2-\frac{1}{2}) \times 0.02\)
- This simplifies to \(dT = 0.25 + 0.06 = 0.31\).
Hence, the maximum possible error in the calculated value of \(T\) is 0.31.
This gives us a limit on how inaccuracy in \(x\) and \(y\) measurements might affect the calculated \(T\), aiding in establishing error bounds in practical scenarios.