Chapter 14: Problem 20
In Exercises \(13-24,\) draw a dependency diagram and write a Chain Rule formula for each derivative. $$ \frac{\partial y}{\partial r} \text { for } y=f(u), \quad u=g(r, s) $$
Short Answer
Expert verified
\( \frac{\partial y}{\partial r} = f'(u) \cdot \frac{\partial g}{\partial r} \).
Step by step solution
01
Understand the Problem
Identify the functions involved in the problem. We have a function \( y = f(u) \), where \( u = g(r, s) \). This tells us that \( y \) is dependent on \( u \), and \( u \) is dependent on both \( r \) and \( s \).
02
Draw a Dependency Diagram
Visualize the relationships: \( r \) and \( s \) are inputs to \( g \), which determines \( u \). Then, \( u \) is an input to \( f \), producing \( y \). The diagram looks like this: \(\begin{array}{c} & r & \quad & s & \ & \searrow & \swarrow & \ & \quad u = g(r, s) & \ & \quad \downarrow & \ & y = f(u) & \\end{array}\)
03
Apply the Chain Rule
The goal is to find \( \frac{\partial y}{\partial r} \). Use the chain rule: \[ \frac{\partial y}{\partial r} = \frac{df}{du} \cdot \frac{\partial g}{\partial r} \]This formula reflects that the change in \( y \) with respect to \( r \) can be found by taking the derivative of \( y \) with respect to \( u \), then multiplying it by the derivative of \( u \) with respect to \( r \).
04
Write the Final Expression
Express \( \frac{\partial y}{\partial r} \) using the chain rule found:\[ \frac{\partial y}{\partial r} = f'(u) \cdot \frac{\partial g}{\partial r} \] Remember that \( f'(u) \) is the derivative of \( f \) with respect to \( u \), and \( \frac{\partial g}{\partial r} \) is the partial derivative of \( g \) with respect to \( r \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Partial Derivatives
Partial derivatives are a fundamental concept in calculus, especially when dealing with multivariable functions. When we have a function that depends on multiple variables, such as \( u = g(r, s) \), it can be useful to investigate how the function changes with respect to just one of those variables at a time. This is where partial derivatives come in.
- The notation \( \frac{\partial g}{\partial r} \) denotes the partial derivative of \( g \) with respect to \( r \). It measures the rate of change of \( g \) when only \( r \) changes, while keeping \( s \) constant.
- Similarly, \( \frac{\partial y}{\partial r} \) is the partial derivative of \( y \) with respect to \( r \). It tells us how \( y \) changes when \( r \) changes and \( s \) remains fixed.
Dependency Diagram
A dependency diagram is a visual representation that helps in understanding the relationship between different variables within a problem, and it’s particularly useful in multivariable calculus.
- It illustrates how each variable depends on others. In our problem, the dependency diagram shows \( r \) and \( s \) as the initial variables.
- They both affect \( u = g(r, s) \) as they are inputs to the function \( g \).
- Then \( u \) becomes the input to another function \( f(u) \), which consequently determines the output \( y \).
Multivariable Functions
Multivariable functions are functions that have more than one input variable. This exercise involves such functions, as seen with the function \( u = g(r, s) \). These functions provide a way to model scenarios where output depends on several factors.
- For example, \( u \) depends on both \( r \) and \( s \), illustrating a typical scenario in real-world applications like physics, engineering, and economics.
- The function \( y = f(u) \) further highlights how one multivariable function can be nested within another, requiring careful analysis using calculus techniques such as the chain rule.