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In Exercises \(1-8,\) let \(\mathbf{u}=\langle 3,-2\rangle\) and \(\mathbf{v}=\langle- 2,5\rangle .\) Find the (a) component form and (b) magnitude (length) of the vector. $$\mathbf{u}+\mathbf{v}$$

Short Answer

Expert verified
Component form: \(\langle 1, 3 \rangle\); Magnitude: \(\sqrt{10}\).

Step by step solution

01

Find the component form of \(\mathbf{u}+\mathbf{v}\)

To find the component form of \(\mathbf{u}+\mathbf{v}\), add the corresponding components of vectors \(\mathbf{u}\) and \(\mathbf{v}\). Thus, we have: \( \mathbf{u} + \mathbf{v} = \langle 3, -2 \rangle + \langle -2, 5 \rangle = \langle 3 + (-2), -2 + 5 \rangle = \langle 1, 3 \rangle \).
02

Calculate the magnitude of the vector \(\mathbf{u}+\mathbf{v}\)

To find the magnitude of the vector \(\mathbf{u}+\mathbf{v}\), use the formula \( \sqrt{x^2 + y^2} \) for a vector \(\langle x, y \rangle\). Here, \(x = 1\) and \(y = 3\), so the magnitude is \( \sqrt{1^2 + 3^2} = \sqrt{1 + 9} = \sqrt{10} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Component Form
When working with vectors, understanding their component form is crucial. Vectors such as \( \mathbf{u} \) and \( \mathbf{v} \) are typically expressed in component form as \( \langle x, y \rangle \). This notation breaks down the vector into its respective components along the
  • x-axis, represented by the first value
  • y-axis, represented by the second value
This allows us to easily manipulate and compute different vector operations, such as addition. To find the component form of a vector sum, like \( \mathbf{u} + \mathbf{v} \), simply add the corresponding components from each vector. For instance, if \( \mathbf{u} = \langle 3, -2 \rangle \) and \( \mathbf{v} = \langle -2, 5 \rangle \), we ensure that each component is added individually:
\[ \mathbf{u} + \mathbf{v} = \langle 3 + (-2), -2 + 5 \rangle = \langle 1, 3 \rangle \]
This resulting vector \( \langle 1, 3 \rangle \) represents the total displacement in the coordinate plane. Understanding the component form simplifies complex vector calculations and is a foundational skill in vector operations.
Magnitude of a Vector
The magnitude of a vector gives us its length or size regardless of its direction. If you imagine a vector as an arrow, the magnitude is simply how long that arrow is. It is always a non-negative number. To calculate the magnitude of a vector in 2D space, use the Pythagorean theorem. For a vector \( \langle x, y \rangle \), this is expressed as:
  • \( \sqrt{x^2 + y^2} \)
This formula derives from treating the vector as the hypotenuse of a right triangle, where \(x\) and \(y\) are the legs. For the vector \( \mathbf{u} + \mathbf{v} = \langle 1, 3 \rangle \), we compute:
\[ \text{Magnitude} = \sqrt{1^2 + 3^2} = \sqrt{1 + 9} = \sqrt{10} \]This result, \( \sqrt{10} \), gives us the length of the vector without considering its direction. Calculating the magnitude is an essential step in vector analysis because it helps quantify the size of the vector.
Vector Operations
Vector operations form the basis of vector algebra, enabling us to perform calculations that model physical phenomena like forces and velocities. Key operations include:
  • Addition: To add vectors, simply sum their respective components as demonstrated earlier with \( \mathbf{u} + \mathbf{v} \).
  • Subtraction: Similar to addition, but involves subtracting corresponding components of vectors.
  • Scalar Multiplication: This operation involves multiplying each component of the vector by the same scalar (number).
Using these operations, we can transform and manipulate vectors in meaningful ways. For instance, vector addition can be used to determine resultant directions in navigation or combine forces in physics problems. Vector subtraction can find the change in position or velocity. Scalar multiplication can scale the magnitude of vectors, maintaining their direction.
Understanding and being comfortable with these operations is fundamental in fields ranging from engineering to graphics to physics.

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