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In Exercises \(17-22,\) express each vector in the form \(\mathbf{v}=v_{1} \mathbf{i}+\) \(v_{2} \mathbf{j}+v_{3} \mathbf{k} .\) \(\overrightarrow{P_{1} P_{2}}\) if \(P_{1}\) is the point \((1,2,0)\) and \(P_{2}\) is the point \((-3,0,5)\)

Short Answer

Expert verified
\( \overrightarrow{P_1 P_2} = -4 \mathbf{i} - 2 \mathbf{j} + 5 \mathbf{k} \)

Step by step solution

01

Understand the Problem

The problem asks us to find the vector \( \overrightarrow{P_1 P_2} \) from point \( P_1(1, 2, 0) \) to point \( P_2(-3, 0, 5) \) and express it in the form \( \mathbf{v} = v_1 \mathbf{i} + v_2 \mathbf{j} + v_3 \mathbf{k} \).
02

Calculate Each Component of the Vector

To find the components \( v_1 \), \( v_2 \), and \( v_3 \), subtract the coordinates of \( P_1 \) from the coordinates of \( P_2 \). Thus, \( v_1 = -3 - 1 = -4 \), \( v_2 = 0 - 2 = -2 \), and \( v_3 = 5 - 0 = 5 \).
03

Express the Vector in Required Form

Now that we have the components, we express the vector as: \( \overrightarrow{P_1 P_2} = -4 \mathbf{i} - 2 \mathbf{j} + 5 \mathbf{k} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Components
Vectors in a three-dimensional space are often broken down into smaller parts known as components. These components are expressed in terms of the unit vectors \( \mathbf{i} \), \( \mathbf{j} \), and \( \mathbf{k} \), which correspond to the x, y, and z axes, respectively. This is similar to how we might express directions using distances along roads going north, east, and upwards (uphill) in real life.

For any vector \( \mathbf{v} \) in 3D space, it can be broken down into \( v_1 \mathbf{i} + v_2 \mathbf{j} + v_3 \mathbf{k} \), where \( v_1 \), \( v_2 \), and \( v_3 \) are the magnitudes of the vector in the respective directions of the coordinate axes. When finding the components of a vector that joins two points, you simply find the difference in the corresponding coordinates.

**Key Points to Remember:**
  • Each vector is described uniquely by its three components.
  • Components are calculated by subtracting the start point coordinates from the endpoint coordinates.
3D Coordinate System
The 3D coordinate system is used to describe the positions of points in a three-dimensional space, much like a location pinpointed on a physical map, but with height added. In the 3D system, each point is defined as \((x, y, z)\), with x, y, and z representing displacements along their respective axes. Imagine it like finding the exact position of an object using three rulers: one lying flat, another standing upright, and the third pointing out towards you.

The axes intersect at the origin \((0, 0, 0)\), similar to the center of a cube. Each axis aligns with one dimension: the x-axis runs along the length, the y-axis runs along the width, and the z-axis runs vertically.
**Benefits of the 3D Coordinate System:**
  • It allows precise definition of space using three parameters, which is essential in fields like physics and engineering.
  • Many real-world problems can be conveniently modeled and analyzed.
Vector Subtraction
Vector subtraction is an essential operation in vector mathematics. It involves finding a vector that points from one vector to another. This is akin to finding a straight path between two locations using a map marked with coordinates for both starting and ending points.

When subtracting vectors, you subtract each of the components individually: for two vectors \( \mathbf{a} = a_1 \mathbf{i} + a_2 \mathbf{j} + a_3 \mathbf{k} \) and \( \mathbf{b} = b_1 \mathbf{i} + b_2 \mathbf{j} + b_3 \mathbf{k} \), the result of \( \mathbf{b} - \mathbf{a} \) is \( (b_1 - a_1) \mathbf{i} + (b_2 - a_2) \mathbf{j} + (b_3 - a_3) \mathbf{k} \).

**Understanding Vector Subtraction:**
  • It's widely used to determine differences in direction and magnitude.
  • The calculation helps in finding vectors representing distances, relative motion, and directions.
Vector subtraction is not only a foundational technique but also a versatile tool in solving practical and theoretical problems in various scientific areas.

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