Chapter 12: Problem 11
In Exercises \(9 - 14 ,\) sketch the coordinate axes and then include the vectors \(\mathbf { u } , \mathbf { v } ,\) and \(\mathbf { u } \times \mathbf { v }\) as vectors starting at the origin. $$ \mathbf { u } = \mathbf { i } - \mathbf { k } , \quad \mathbf { v } = \mathbf { j } + \mathbf { k } $$
Short Answer
Step by step solution
Understand the Vectors
Calculate the Cross Product
Evaluate the Determinant
Simplify the Cross Product
Sketch the Coordinate Axes
Plot the Vectors
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
A convenient property of the cross product is that it provides a vector that is orthogonal to both original vectors. This is particularly useful in physics and engineering to find directions such as the orientation of a plane.
- It is defined only in three-dimensional space.
- The result of the cross product is another vector, not a scalar.
- Cross products can be calculated using a 3x3 determinant with the unit vectors and the vector components.
3D Coordinate System
In the exercise, the vector \( \mathbf{u} \) with components (1, 0, -1) is plotted from the origin, extending in the positive x-direction and negative z-direction. The vector \( \mathbf{v} \) starts at the same point, moving in both the positive y and z directions. Combined, their cross product, \( \mathbf{u} \times \mathbf{v} = \mathbf{i} - \mathbf{j} + \mathbf{k} \), is also plotted from the origin, showing us how the three vectors interact in three-dimensional space.
- 3D coordinate systems are essential for describing points and vectors in space.
- They help in visualizing and solving problems involving vectors.
- The axes form three perpendicular planes, making it simple to interpret vector directions.
Determinants
The determinant has a systematic way of breaking down these computations:
- Multiply the diagonal elements and subtract the product of the off-diagonal elements.
- This provides the vector components along the \( \mathbf{i}, \mathbf{j}, \) and \( \mathbf{k} \) directions.
Vector Components
- The vector \( \mathbf{u} = \mathbf{i} - \mathbf{k} \) has components (1, 0, -1):
- 1 in the x-direction (represented by \( \mathbf{i} \))
- 0 in the y-direction (represented by \( \mathbf{j} \))
- -1 in the z-direction (represented by \( \mathbf{k} \))
- The vector \( \mathbf{v} = \mathbf{j} + \mathbf{k} \) has components (0, 1, 1):
- 0 in the x-direction
- 1 in the y-direction
- 1 in the z-direction