Chapter 12: Problem 10
In Exercises \(1-16,\) give a geometric description of the set of points in space whose coordinates satisfy the given pairs of equations. $$x^{2}+y^{2}+z^{2}=25, \quad y=-4$$
Short Answer
Expert verified
A circle in the plane \(y = -4\) with radius 3.
Step by step solution
01
Interpret the First Equation
The equation \(x^2 + y^2 + z^2 = 25\) represents a sphere centered at the origin \((0, 0, 0)\) with a radius of 5. This can be derived from the general equation of a sphere \((x - h)^2 + (y - k)^2 + (z - l)^2 = r^2\), where \((h, k, l)\) is the center and \(r\) is the radius.
02
Interpret the Second Equation
The equation \(y = -4\) represents a plane that is parallel to the XZ-plane and located 4 units below it in the 3D space. This equation fixes the y-coordinate of every point.
03
Combine the Two Equations
The system of equations \(x^2 + y^2 + z^2 = 25\) and \(y = -4\) describes the intersection of the sphere and the plane \(y = -4\). Substitute \(y = -4\) into the equation of the sphere to find the resulting shape.
04
Solve for the Intersection
Substitute \(y = -4\) into the sphere equation: \(x^2 + (-4)^2 + z^2 = 25\). Simplifying gives \(x^2 + 16 + z^2 = 25\), leading to \(x^2 + z^2 = 9\), which represents a circle in the XZ-plane.
05
Describe the Geometric Shape
The intersection is a circle in the plane \(y = -4\) with a radius of 3 (since \(x^2 + z^2 = 9\)), centered at \((0, -4, 0)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sphere
In 3D geometry, a sphere is a perfectly symmetrical object in three-dimensional space, defined by all points that are a fixed distance from a central point. This distance is known as the sphere's radius. The general equation of a sphere with a center at point \(h, k, l\) and radius \(r\) is given by: \\[(x - h)^2 + (y - k)^2 + (z - l)^2 = r^2\]For example, the equation \(x^2 + y^2 + z^2 = 25\) represents a sphere centered at the origin \(0, 0, 0\) with a radius of 5, since:
Understanding spheres involves recognizing how any point on the sphere's surface relates back to its center via the radius.
This provides a basis for solving many technical problems, such as finding intersections with other objects or understanding bounding volumes in space.
- The center is at \(h = 0, k = 0, l = 0\)
- The radius squared is \(r^2 = 25\), so \(r = 5\)
Understanding spheres involves recognizing how any point on the sphere's surface relates back to its center via the radius.
This provides a basis for solving many technical problems, such as finding intersections with other objects or understanding bounding volumes in space.
Plane
A plane in geometry is a flat, two-dimensional surface that extends infinitely in every direction. An equation representing a plane typically looks like \(Ax + By + Cz = D\), which is a linear equation involving three variables. Here, the equation \(y = -4\) describes a specific type of plane.
- This equation means that the plane is parallel to the XZ-plane.
- Every point on this plane has a y-coordinate of -4.
Intersection of Surfaces
When two 3D surfaces, such as a sphere and a plane, intersect, the resulting shape is usually a two-dimensional figure. Understanding surface intersections is crucial for 3D modeling, engineering, and physics.Given our sphere \(x^2 + y^2 + z^2 = 25\) and plane \(y = -4\), we observe their interaction by substituting the plane's information into the sphere's equation:
- Replace \(y = -4\) into \(x^2 + y^2 + z^2 = 25\):
- Get \(x^2 + (-4)^2 + z^2 = 25\), which simplifies to \(x^2 + 16 + z^2 = 25\).
- Solve \(x^2 + z^2 = 9\).