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The parabola \(x^{2}=-4 y\) is shifted left 1 unit and up 3 units to generate the parabola \((x+1)^{2}=-4(y-3).\) a. Find the new parabola's vertex, focus, and directrix. b. Plot the new vertex, focus, and directrix, and sketch in the parabola.

Short Answer

Expert verified
Vertex: (-1, 3), Focus: (-1, 2), Directrix: y = 4. Parabola opens downward.

Step by step solution

01

Identify Original Vertex

The original equation of the parabola is \(x^2 = -4y\). This equation represents a parabola that opens downward with its vertex at the origin \((0, 0)\).
02

Apply Transformation

The parabola \((x + 1)^2 = -4(y - 3)\) is derived by translating the original parabola 1 unit left and 3 units up. This shifts the vertex from \((0, 0)\) to \((-1, 3)\).
03

Determine the Focus and Directrix

For the equation \((x + 1)^2 = -4(y - 3)\), we note that it is of the form \((x - h)^2 = 4p(y - k)\). Here, \(4p = -4\) so \(p = -1\). The focus is located \(1\) unit down from the vertex, resulting in the focus \((-1, 2)\). The directrix is \(1\) unit up from the vertex, so it is the horizontal line \(y = 4\).
04

Plotting the Graph

Plot the vertex at \((-1, 3)\), the focus at \((-1, 2)\), and draw the directrix as the line \(y = 4\). The parabola should open downward because \(p < 0\). Sketch the parabola ensuring it is symmetric about the vertical line passing through the vertex and focus.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertex
In any parabola, the vertex is a crucial point that marks the tip or the turning point of the curve.
For the given transformed parabola equation \((x+1)^{2} = -4(y-3)\), we find the vertex through translation of the original equation \(x^{2} = -4y\) which had its vertex at \((0,0)\).
Translation involves moving the curve 1 unit to the left and 3 units up, resulting in a new vertex position at \((-1, 3)\). This new vertex is where the parabola reaches its peak, as it opens downward.
Remember, the vertex forms the middle point of a parabola and is vital in determining its symmetry and direction. It helps to visualize the parabola graphically, especially recognizing that it opens upwards or downwards based on its position and form.
In sum, the vertex is a focal point of the parabola where its symmetry and path are easiest to identify.
Focus
The focus of a parabola is a point that lies inside the curve. It plays a role in defining the shape and direction of the parabola.
In the transformed parabola equation \((x + 1)^2 = -4(y - 3)\), the focus is determined using the parameter \(p\).
From the equation, \(4p\) equals \(-4\), meaning \(p = -1\). This indicates that the focus is located 1 unit below the vertex due to the downward orientation of the parabola.
Thus, the focus for this parabola is at \((-1, 2)\). The significance of the focus is that every point on the parabola is equidistant from the focus and the directrix.
When sketching, plotting this point helps listeners understand how the parabola curves inward, emphasizing the concave nature towards the focus. The focus adds depth to the visual understanding of parabolas.
Directrix
The directrix of a parabola serves as an imaginary line against which the curve reflects and bends.
For the transformed equation \((x + 1)^2 = -4(y - 3)\), the directrix helps determine the set distance from the focus.
Just as the focus lies \(1\) unit below the vertex, the directrix lies the same unit distance above.
This places the directrix along the line \(y = 4\). The directrix acts as a boundary the parabola never crosses, guiding its curve.
In a more technical perspective, every point on the parabola is equidistant to the focus and the directrix. This property underscores the elliptical nature of a parabola and is crucial for accurate graph sketching.
Being familiar with the directrix is essential in drawing and understanding parabolas, offering a clear complementary counterpart to the focus.
Graph Sketching
Graph sketching of parabolas involves plotting key components like the vertex, focus, and directrix, and drawing the curve accordingly.
Here, with the vertex at \((-1, 3)\), focus at \((-1, 2)\), and the directrix at \(y = 4\), these points guide the direction and shape of the parabola.
Start by plotting the vertex, marking the central point of the parabola. Next, plot the focus, and draw the directrix as a dashed line.
Notice that because the parabola is defined by \((x + 1)^2 = -4(y - 3)\) with \(p < 0\), it opens downwards. This means the curve bends towards the bottom, towards the focus, while never crossing the directrix.
Sketching involves estimating the symmetrical curve about the vertical line passing through the vertex and focus, ensuring smoothness and accuracy.
Utilizing these principles allows for a greater understanding of the geometric properties of parabolas, aiding in applied problem-solving.

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