Chapter 11: Problem 34
In Exercises \(31-36,\) find a parametrization for the curve. the left half of the parabola \(y=x^{2}+2 x\)
Short Answer
Expert verified
Parametrization: \(x(t) = -t\), \(y(t) = t^2 - 2t\) for \(t \geq 0\).
Step by step solution
01
Understand the Shape of the Parabola
The given parabola is described by the equation \(y = x^2 + 2x\). This equation represents a parabola opening upwards. However, we are only interested in the left half, which occurs where \(x\) is negative.
02
Introduce a Parameter for \(x\)
We can parametrize the left side of the parabola using \(t\) as a parameter. Since \(t\) typically ranges over all real numbers in a parametrization, we can set \(x = -t\) where \(t \geq 0\) to ensure \(x\) remains negative.
03
Write the Parametrization Equations
Replace \(x\) in the original equation with \(-t\). This gives: \[ y = (-t)^2 + 2(-t) = t^2 - 2t \]. Now, we have the parametrization: \(x(t) = -t\) and \(y(t) = t^2 - 2t\) with \(t \geq 0\).
04
Validate the Parametrization
Verify that our parametrization orders points on the left half of the parabola. As \(t\) increases from 0, \(x\) moves from 0 towards negative infinity, covering all negative \(x\) as desired.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabolas and Their Properties
A parabola is a beautiful mathematical curve that follows the shape of the equation \( y = ax^2 + bx + c \). Parabolas open upwards or downwards depending on the sign of the coefficient \( a \). In this exercise, we are dealing with the parabola \( y = x^2 + 2x \), which opens upwards. This happens because the coefficient of \( x^2 \) is positive.
Parabolas have a symmetric property around a vertical line known as the axis of symmetry. For this specific equation, the axis is at \( x = -1 \), found using the formula \( x = -\frac{b}{2a} \), where \( a = 1 \) and \( b = 2 \). Due to this symmetry, the parabola is identical on both sides. However, our task is to focus only on the left half, which involves all the negative values of \( x \). To achieve this, it is essential to focus on the part returning negative \( x \)-values, which requires a particular approach in parametrization.
Parabolas have a symmetric property around a vertical line known as the axis of symmetry. For this specific equation, the axis is at \( x = -1 \), found using the formula \( x = -\frac{b}{2a} \), where \( a = 1 \) and \( b = 2 \). Due to this symmetry, the parabola is identical on both sides. However, our task is to focus only on the left half, which involves all the negative values of \( x \). To achieve this, it is essential to focus on the part returning negative \( x \)-values, which requires a particular approach in parametrization.
Understanding Parametric Equations
Parametric equations are an elegant way to represent curves by introducing a third variable, often [latex] t [latex], called a parameter. These equations express the coordinates \((x, y)\) of the curve as functions of \( t \). For a parabola like \( y = x^2 + 2x \), we can use parametric equations to separately express \( x \) and \( y \) in terms of \( t \).
A common method for parameterizing is to replace one of the variables in the function with \( t \). In our case, we parameterized \( x = -t \) to ensure we capture only the left side of the parabola. This implies that as \( t \) varies, both \( x \) and \( y \) change accordingly. The parametrization becomes:
A common method for parameterizing is to replace one of the variables in the function with \( t \). In our case, we parameterized \( x = -t \) to ensure we capture only the left side of the parabola. This implies that as \( t \) varies, both \( x \) and \( y \) change accordingly. The parametrization becomes:
- \( x(t) = -t \), keeping \( x\) negative as desired.
- \( y(t) = t^2 - 2t \), reflecting the original equation with modified values.
Handling Negative x-Values
The focus of this problem is on the left half of the parabola, where \( x \) values are negative. Ensuring that the parametrization covers these negative \( x \)-values effectively is key. By letting \( x = -t \) with \( t \geq 0 \), the condition for negative \( x \) values is naturally satisfied.
Here’s why this works:
Here’s why this works:
- As \( t \) approaches increasing values, \( x = -t \) ensures that \( x \) moves in the negative direction, such as \( -1, -2, -3, \) and so on.
- The parameter \( t \), starting from zero, guarantees all \( x \)-values along the left parabola are covered.