Chapter 10: Problem 99
Which of the sequences \(\left\\{a_{n}\right\\}\) converge, and which diverge? Find the limit of each convergent sequence. $$ a_{n}=\frac{1}{n} \int_{1}^{n} \frac{1}{x} d x $$
Short Answer
Expert verified
The sequence \( a_n \) converges to 0.
Step by step solution
01
Interpret the Sequence
The sequence is given by \( a_n = \frac{1}{n} \int_{1}^{n} \frac{1}{x} \, dx \). It represents the average value of the function \( f(x) = \frac{1}{x} \) over the interval \([1, n]\).
02
Evaluate the Integral
The integral is \( \int_{1}^{n} \frac{1}{x} \, dx \). This is a standard integral, yielding \( \ln|x| \). Evaluating it from 1 to \( n \) gives \( \ln n - \ln 1 = \ln n \).
03
Express Sequence in Terms of n
Substitute \( \ln n \) back into the sequence: \[ a_n = \frac{\ln n}{n} \]. We now need to analyze the behavior of this expression as \( n \to \infty \).
04
Analyze Limit Behavior
Investigate the limit of \( \frac{\ln n}{n} \) as \( n \to \infty \). Use L'Hopital's Rule since it is an indeterminate form \( \frac{\infty}{\infty} \).
05
Apply L'Hopital's Rule
Differentiate the numerator and denominator separately and evaluate the limit: \( \lim_{{n \to \infty}} \frac{1/n}{1} = \lim_{{n \to \infty}} \frac{1}{n} = 0 \).
06
Conclude Convergence and Limit
Since the limit is \( 0 \), the sequence converges to \( 0 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Integral Evaluation
Integral evaluation is a fundamental concept in calculus. An integral often represents the accumulation of quantities, like area under a curve, or in this case, the average value of a function.
For the sequence in our problem, we look at the integral \( \int_{1}^{n} \frac{1}{x} \, dx \). This integral cannot be evaluated directly until you realize it's a common form: \( \int \frac{1}{x} \, dx = \ln|x| + C \).
When evaluating definitively from 1 to \( n \), we find the result \( \ln n - \ln 1\). Notably, \( \ln 1 = 0 \), simplifying our integral to just \( \ln n \).
This integral evaluation plays a crucial role in determining the sequence's behavior, setting up for future analysis like limit behavior.
For the sequence in our problem, we look at the integral \( \int_{1}^{n} \frac{1}{x} \, dx \). This integral cannot be evaluated directly until you realize it's a common form: \( \int \frac{1}{x} \, dx = \ln|x| + C \).
When evaluating definitively from 1 to \( n \), we find the result \( \ln n - \ln 1\). Notably, \( \ln 1 = 0 \), simplifying our integral to just \( \ln n \).
This integral evaluation plays a crucial role in determining the sequence's behavior, setting up for future analysis like limit behavior.
- Common integral forms simplify the process.
- Definite integrals provide specific solutions useful for sequence evaluation.
Applying L'Hopital's Rule
L'Hopital's Rule is a handy tool when dealing with limits of indeterminate forms like \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \).
In the sequence \( a_n = \frac{\ln n}{n} \), as \( n \to \infty \), both the numerator and denominator approach infinity, creating a \( \frac{\infty}{\infty} \) form. Thus, it's a perfect candidate for applying L'Hopital's Rule.
To apply it, differentiate the numerator and denominator separately. The derivative of \( \ln n \) is \( \frac{1}{n} \), and for \( n \), it's simply 1. Now, we have:
In the sequence \( a_n = \frac{\ln n}{n} \), as \( n \to \infty \), both the numerator and denominator approach infinity, creating a \( \frac{\infty}{\infty} \) form. Thus, it's a perfect candidate for applying L'Hopital's Rule.
To apply it, differentiate the numerator and denominator separately. The derivative of \( \ln n \) is \( \frac{1}{n} \), and for \( n \), it's simply 1. Now, we have:
- Limit transform: \( \lim_{{n \to \infty}} \frac{\ln n}{n} \Rightarrow \lim_{{n \to \infty}} \frac{1/n}{1} \)
- This simplifies to \( \lim_{{n \to \infty}} \frac{1}{n} \)
Exploring Limit Behavior
Limit behavior examines what happens to a sequence or a function as it approaches a particular point or extends to infinity.
Our sequence \( a_n = \frac{\ln n}{n} \) addresses limit behavior by letting \( n \to \infty \). This analysis reveals how the sequence evolves and whether it settles on a specific value.
By previously applying L'Hopital's Rule, we've shown that as the numbers get outrageously large, \( \frac{1}{n} \) approaches 0.
This concept simplifies the difficulty of understanding how functions behave over infinite stretches, emphasizing practical and theoretical importance in analyzing sequences.
Our sequence \( a_n = \frac{\ln n}{n} \) addresses limit behavior by letting \( n \to \infty \). This analysis reveals how the sequence evolves and whether it settles on a specific value.
By previously applying L'Hopital's Rule, we've shown that as the numbers get outrageously large, \( \frac{1}{n} \) approaches 0.
- Indication: As \( n \to \infty, a_n \to 0 \)
- Conclusive behavior: The sequence converges to 0
This concept simplifies the difficulty of understanding how functions behave over infinite stretches, emphasizing practical and theoretical importance in analyzing sequences.