/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 99 Which of the sequences \(\left\\... [FREE SOLUTION] | 91Ó°ÊÓ

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Which of the sequences \(\left\\{a_{n}\right\\}\) converge, and which diverge? Find the limit of each convergent sequence. $$ a_{n}=\frac{1}{n} \int_{1}^{n} \frac{1}{x} d x $$

Short Answer

Expert verified
The sequence \( a_n \) converges to 0.

Step by step solution

01

Interpret the Sequence

The sequence is given by \( a_n = \frac{1}{n} \int_{1}^{n} \frac{1}{x} \, dx \). It represents the average value of the function \( f(x) = \frac{1}{x} \) over the interval \([1, n]\).
02

Evaluate the Integral

The integral is \( \int_{1}^{n} \frac{1}{x} \, dx \). This is a standard integral, yielding \( \ln|x| \). Evaluating it from 1 to \( n \) gives \( \ln n - \ln 1 = \ln n \).
03

Express Sequence in Terms of n

Substitute \( \ln n \) back into the sequence: \[ a_n = \frac{\ln n}{n} \]. We now need to analyze the behavior of this expression as \( n \to \infty \).
04

Analyze Limit Behavior

Investigate the limit of \( \frac{\ln n}{n} \) as \( n \to \infty \). Use L'Hopital's Rule since it is an indeterminate form \( \frac{\infty}{\infty} \).
05

Apply L'Hopital's Rule

Differentiate the numerator and denominator separately and evaluate the limit: \( \lim_{{n \to \infty}} \frac{1/n}{1} = \lim_{{n \to \infty}} \frac{1}{n} = 0 \).
06

Conclude Convergence and Limit

Since the limit is \( 0 \), the sequence converges to \( 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Integral Evaluation
Integral evaluation is a fundamental concept in calculus. An integral often represents the accumulation of quantities, like area under a curve, or in this case, the average value of a function.
For the sequence in our problem, we look at the integral \( \int_{1}^{n} \frac{1}{x} \, dx \). This integral cannot be evaluated directly until you realize it's a common form: \( \int \frac{1}{x} \, dx = \ln|x| + C \).
When evaluating definitively from 1 to \( n \), we find the result \( \ln n - \ln 1\). Notably, \( \ln 1 = 0 \), simplifying our integral to just \( \ln n \).
This integral evaluation plays a crucial role in determining the sequence's behavior, setting up for future analysis like limit behavior.
  • Common integral forms simplify the process.
  • Definite integrals provide specific solutions useful for sequence evaluation.
Understanding these basics helps in tackling more complex problems.
Applying L'Hopital's Rule
L'Hopital's Rule is a handy tool when dealing with limits of indeterminate forms like \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \).
In the sequence \( a_n = \frac{\ln n}{n} \), as \( n \to \infty \), both the numerator and denominator approach infinity, creating a \( \frac{\infty}{\infty} \) form. Thus, it's a perfect candidate for applying L'Hopital's Rule.
To apply it, differentiate the numerator and denominator separately. The derivative of \( \ln n \) is \( \frac{1}{n} \), and for \( n \), it's simply 1. Now, we have:
  • Limit transform: \( \lim_{{n \to \infty}} \frac{\ln n}{n} \Rightarrow \lim_{{n \to \infty}} \frac{1/n}{1} \)
  • This simplifies to \( \lim_{{n \to \infty}} \frac{1}{n} \)
The clear answer is 0, indicating that sequence trends towards 0 as \( n \) increases infinitely. Mastering L'Hopital's Rule opens many doors in calculus for managing complex limit problems.
Exploring Limit Behavior
Limit behavior examines what happens to a sequence or a function as it approaches a particular point or extends to infinity.
Our sequence \( a_n = \frac{\ln n}{n} \) addresses limit behavior by letting \( n \to \infty \). This analysis reveals how the sequence evolves and whether it settles on a specific value.
By previously applying L'Hopital's Rule, we've shown that as the numbers get outrageously large, \( \frac{1}{n} \) approaches 0.
  • Indication: As \( n \to \infty, a_n \to 0 \)
  • Conclusive behavior: The sequence converges to 0
Understanding limit behavior is central to many areas of mathematics, helping evaluate expressions' long-term tendencies, determine convergence, and explain practical implications.
This concept simplifies the difficulty of understanding how functions behave over infinite stretches, emphasizing practical and theoretical importance in analyzing sequences.

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Most popular questions from this chapter

Prove that if \(\left\\{a_{n}\right\\}\) is a convergent sequence, then to every positive number \(\varepsilon\) there corresponds an integer \(N\) such that $$ \left|a_{m}-a_{n}\right|<\varepsilon \quad \text { whenever } \quad m>N \quad \text { and } \quad n>N $$

Uniqueness of limits Prove that limits of sequences are unique. That is, show that if \(L_{1}\) and \(L_{2}\) are numbers such that \(a_{n} \rightarrow L_{1}\) and \(a_{n} \rightarrow L_{2},\) then \(L_{1}=L_{2}\)

Use a CAS to perform the following steps for the sequences. a. Calculate and then plot the first 25 terms of the sequence. Does the sequence appear to be bounded from above or below? Does it appear to converge or diverge? If it does converge, what is the limit \(L\) ? b. If the sequence converges, find an integer \(N\) such that \(\quad\left|a_{n}-L\right| \leq 0.01\) for \(n \geq N .\) How far in the sequence do you have to get for the terms to lie within 0.0001 of \(L ?\) $$ a_{n}=(123456)^{1 / n} $$

Which of the series in Exercises 13 46 converge, and which diverge? Give reasons for your answers. (When you check an answer, remember that there may be more than one way to determine the series' convergence or divergence.) $$ \sum_{n=2}^{\infty} \frac{\sqrt{n+2}-\sqrt{n+1}}{\sqrt{n+1} \sqrt{n+2}} $$

Use a CAS to perform the following steps for the sequences. a. Calculate and then plot the first 25 terms of the sequence. Does the sequence appear to be bounded from above or below? Does it appear to converge or diverge? If it does converge, what is the limit \(L\) ? b. If the sequence converges, find an integer \(N\) such that \(\quad\left|a_{n}-L\right| \leq 0.01\) for \(n \geq N .\) How far in the sequence do you have to get for the terms to lie within 0.0001 of \(L ?\) $$ a_{n}=(0.9999)^{n} $$

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