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Which of the sequences \(\left\\{a_{n}\right\\}\) converge, and which diverge? Find the limit of each convergent sequence. $$ a_{n}=\left(\frac{1}{n}\right)^{1 /(\ln n)} $$

Short Answer

Expert verified
The sequence \(\{a_n\}\) converges to 1.

Step by step solution

01

Understand the sequence

We are given the sequence \(a_n = \left( \frac{1}{n} \right)^{1 / (\ln n)}\). To understand its behavior as \(n \to \infty\), we'll examine it further. This sequence is of the form \(b_n^{g_n}\), where \(b_n = \frac{1}{n}\) and \(g_n = \frac{1}{\ln n}\).
02

Analyze base sequence behavior

Consider the base of the sequence \(b_n = \frac{1}{n}\). As \(n \to \infty\), we notice that \(b_n = \frac{1}{n} \to 0\).
03

Analyze the exponent function

Now, consider the exponent function \(g_n = \frac{1}{\ln n}\). As \(n \to \infty\), \(\ln n \to \infty\), so \(g_n = \frac{1}{\ln n} \to 0\).
04

Re-examine the original sequence

The sequence \(a_n\) can be rewritten as \(a_n = e^{\ln \left(\frac{1}{n}\right) \cdot g_n} = e^{-\frac{1}{n} \cdot \frac{1}{\ln n}}\). As both \(-\frac{1}{n}\) and \(\frac{1}{\ln n}\) tend to zero as \(n \to \infty\), the product also tends to zero. Thus, \(\ln \left(\frac{1}{n}\right) \cdot g_n \to 0\) as \(n \to \infty\).
05

Evaluate the limit of the sequence

Since \( \ln \left(\frac{1}{n}\right) \cdot g_n \to 0\), it follows that \(a_n = e^{0} = 1\). Therefore, the sequence \(\{a_n\}\) converges to 1 as \(n \to \infty\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit of a Sequence
A sequence is essentially a list of numbers following some specific pattern or rule. In the world of sequences, understanding their behavior as they extend towards infinity is key. The concept of a "limit" helps us describe this behavior. When a sequence approaches a specific number as its terms go on indefinitely, we call that number its "limit." For example, if the terms of a sequence close in on the value of 5, we say that the sequence's limit is 5. In mathematical notation, we express this as \( \lim_{{n \to \infty}} a_n = 5 \).

The idea here is to grasp where a sequence is "headed". Not every sequence will have a limit, but those that do offer a peek into their long-term behavior. Limit plays a crucial role in assessing whether a sequence converges or diverges.
Convergent Sequences
When a sequence has a limit, we say it is "convergent." Convergent sequences are those that gradually zero in on a particular value as they extend towards infinity.

Imagine watching a car slowly roll to a stop at a traffic light. The car, just like a convergent sequence, gets closer and closer to a stopping point. In the arithmetic world of sequences, the stopping point is the sequence's limit.
  • The sequence \( \{1, 1/2, 1/3, 1/4, \ldots\} \) converges to zero.
  • Another sequence \( \{a_n = (1/n)^{1/(\ln n)}\} \) converges to 1, as we demonstrated earlier.
In both cases, there is a tangible value the sequence is approaching. Convergent sequences are essential in mathematics because they allow us to predict the outcome or result of a sequence based on its pattern.
Divergent Sequences
Unlike convergent sequences, which focus in on a limit, divergent sequences don't settle. They either shoot off to infinity or continuously oscillate without ever nearing a single value.

Think of a bouncing ball that never loses height or a spaceship rocketing away from Earth without slowing down. These are metaphors for how divergent sequences behave.
  • The sequence \( \{1, 2, 3, 4, \ldots\} \) is divergent as it grows indefinitely.
  • An oscillating sequence such as \( \{-1, 1, -1, 1, \ldots\} \) also represents divergence, as it lacks a defining limit.
Divergence indicates inconsistency or lack of direction. Understanding whether a sequence diverges or converges is pivotal as it determines the predictability and potential conclusions we can draw from the sequence's behavior.

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