Chapter 10: Problem 31
Find the Taylor series generated by \(f\) at \(x=a.\) \(f(x)=e^{x}, \quad a=2\)
Short Answer
Expert verified
The Taylor series for \( e^x \) at \( x=2 \) is \( \sum_{n=0}^{\infty} \frac{e^2}{n!} (x-2)^n. \)
Step by step solution
01
Understand the Taylor Series Formula
The Taylor series of a function \( f \) at a point \( a \) is given by the formula: \[ f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!} (x-a)^n \] where \( f^{(n)}(a) \) is the \( n \)-th derivative of \( f \) evaluated at \( a. \)
02
Evaluate Derivatives of \( f(x) = e^x \)
The function \( f(x) = e^x \) has derivatives that repeat as \( f^{(n)}(x) = e^x \) for all \( n. \) Thus, \( f^{(n)}(a) = e^a \) for all \( n. \) Since we're evaluating at \( a = 2, \) then \( f^{(n)}(2) = e^2 \) for all \( n. \)
03
Substitute into the Taylor Series Formula
Substitute \( f^{(n)}(2) = e^2 \) into the Taylor series formula: \[ f(x) = \sum_{n=0}^{\infty} \frac{e^2}{n!} (x-2)^n \] This represents the Taylor series for \( e^x \) centered at \( x = 2. \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivatives of Functions
In calculus, understanding the derivative of a function is crucial. The derivative measures how a function changes as its input changes. For the exponential function \( f(x) = e^x \), the derivative is unique in the sense that it remains the same after differentiation. That is, each derivative of \( f(x) = e^x \) is also \( e^x \).
This property makes exponential functions quite straightforward to work with when finding derivatives multiple times.
This property makes exponential functions quite straightforward to work with when finding derivatives multiple times.
- The first derivative \( f'(x) \) is \( e^x \).
- The second derivative \( f''(x) \) is \( e^x \).
- In general, all the higher order derivatives \( f^{(n)}(x) \) will be \( e^x \).
Exponential Function
The exponential function \( f(x) = e^x \) is one of the most important and fascinating functions in mathematics. Its base, \( e \), is an irrational constant approximately equal to 2.71828. The exponential function has unique properties that make it very useful: it grows rapidly and has a distinctive self-similarity in its derivatives.
The function \( e^x \) can be applied in various contexts such as compound interest, population growth, and natural processes that follow an exponential trend.
The function \( e^x \) can be applied in various contexts such as compound interest, population growth, and natural processes that follow an exponential trend.
- It is defined in the real domain and continues to grow exponentially as \( x \) increases.
- As mentioned, its derivative is itself, which makes it very useful in differential equations and series expansions.
Series Expansion
A series expansion is a way of writing a function as an infinite sum of terms. The Taylor series is a specific type of series expansion used to approximate functions locally around a point \( a \). The general formula for the Taylor series of \( f(x) \) at \( a \) is:\[ f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!} (x-a)^n \]This means each term in the series is composed of derivatives computed at \( a \), multiplied by powers of \( x-a \), divided by factorials. When dealing with the exponential function \( e^x \), the simplicity of its derivatives allows us to write:\[ f(x) = \sum_{n=0}^{\infty} \frac{e^2}{n!} (x-2)^n \]
- This expansion centers the series at \( x=2 \).
- Each term \( \frac{e^2}{n!} (x-2)^n \) involves calculating powers of \( (x-2) \) and dividing by \( n! \), making it straightforward computationally once \( e^2 \) is known.