Chapter 10: Problem 2
In Exercises \(1-36,\) (a) find the series' radius and interval of convergence. For what values of \(x\) does the series converge (b) absolutely (c) conditionally? $$ \sum_{n=0}^{\infty}(x+5)^{n} $$
Short Answer
Expert verified
The series converges absolutely for \(-6 < x < -4\); no conditional convergence.
Step by step solution
01
Identify the Series and General Form
The given series is \( \sum_{n=0}^{\infty} (x+5)^n \). This is a geometric series with the general form \( a_n = (x+5)^n \) where the first term \( a = 1 \) and the common ratio \( r = x+5 \). For a geometric series, we know that it converges if the absolute value of the common ratio is less than 1, i.e., \( |r| < 1 \). In this case, \( |x+5| < 1 \).
02
Solve for the Interval of Convergence
To find the interval of convergence, solve the inequality \( |x+5| < 1 \).This translates to \(-1 < x+5 < 1\).Subtract 5 from all sides of the inequality:\[-1 - 5 < x + 5 - 5 < 1 - 5\]Simplifying gives \(-6 < x < -4\). Thus, the interval of convergence is \(-6, -4\).
03
Determine Absolute Convergence
A geometric series either converges or diverges absolutely based on the value of \( r \). Since the series is geometric, it does not have conditions for absolute convergence separately as it's already covered by where it converges. If \( -6 < x < -4 \), the series converges absolutely.
04
Determine Conditional Convergence
For geometric series like \( \sum_{n=0}^{\infty} (x+5)^n \), there is no conditional convergence. It is either absolutely convergent or divergent based on the common ratio. Thus, there are no values of \( x \) where the series converges conditionally.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Geometric Series
A geometric series is a sum of terms in which each term is a fixed multiple of the previous one. In other words, it is a series where each term after the first is found by multiplying the previous term by a constant called the common ratio. For example, in the series
- \( a, ar, ar^2, ar^3, \ldots \)
Interval of Convergence
The interval of convergence is the range of
- x-values
- First, write \( -1 < x+5 < 1 \).
- Subtract 5 from each part:\(-6 < x < -4\).
Absolute Convergence
Absolute convergence is a strong form of convergence for series. A series
- converges absolutely